( \frac{d}{dx}(c) = 0 )
( \frac{d}{dx}(x^n) = nx^{n-1} )
( \frac{d}{dx}(e^x) = e^x )
( \frac{d}{dx}(cf) = c\frac{d}{dx}(f) )
( \frac{d}{dx}(f + g) = \frac{d}{dx}(f) + \frac{d}{dx}(g) )
( \frac{d}{dx}(f - g) = \frac{d}{dx}(f) - \frac{d}{dx}(g) )
( \frac{d}{dx}(fg) = f\frac{d}{dx}(g) + g\frac{d}{dx}(f) )
( \frac{d}{dx}(\frac{f}{g}) = \frac{g\frac{d}{dx}(f) - f\frac{d}{dx}(g)}{g^2} )
Differentiate the following:
(a) ( y = x^3 \sin(x) )
(b) ( f(t) = \sqrt{t} (a + bt) )
(c) ( f(x) = (-2x^2 + 9x)(7e^x + 6) )
Finding Derivatives with Given Conditions:
If ( h(x) = xg(x) ) and ( g(3) = 5, \ g'(3) = 2 ), find ( h'(3) )
Differentiate to find derivatives:
(a) ( y = e^{x^2}(1+x) )
Tangent Line Equations:
Find an equation of the tangent line to ( y = e^x(1+x^3) ) at the point ( (1, e^1) )
( (\sin x)' = \cos x )
( (\csc x)' = -\csc x \cot x )
( (\cos x)' = -\sin x )
( (\sec x)' = \sec x \tan x )
( (\tan x)' = \sec^2 x )
( (\cot x)' = -\csc^2 x )
Differentiate the following:
(a) ( g(x) = \sqrt{x} e^x )
(b) ( h(t) = e^t \sin(t) )
(c) ( f(x) = (x + e^x)^3 - \sqrt{x} )
Etc.
Definition: To find the derivative of a composite function ( F = f \circ g = f(g(x)) ).
Formulation:
If ( g ) is differentiable at ( x ) and ( f ) is differentiable at ( g(x) ), then:
( F'(x) = f'(g(x)) , g'(x) )
If ( n ) is any real number and ( u = g(x) ) is differentiable, then:
( \frac{d}{dx}[u^n] = nu^{n-1} , u' )
Find ( f'(x) ) for:
(a) ( f(x) = \sqrt{x^2 + 1} )
(b) ( f(x) = (2x + 5)^3 )
Implicit Differentiation: To differentiate equations where y is not explicitly solved for x.
Steps:
Differentiate both sides concerning x.
Apply the rules of differentiation.
Group terms containing ( y' ).
Solve for ( y' ).
Given ( x^3 + y^3 = 6xy )
Steps:
Differentiate: ( 3x^2 + 3y^2 y' = 6y + 6xy' )
Isolate and solve for ( y' ) after substituting values.
Related rates problems involve finding how the rate of change of one quantity relates to the rate of change of another.
Start with a relation equation between quantities and then differentiate with respect to time.
When the diameter of a spherical tumor is 16 mm and grows at a rate of 0.4 mm/day, find how fast the volume is changing at that time.
Volume formula: ( V = \frac{4}{3} \pi r^3 )
Differentiate to find ( \frac{dV}{dt} ).
Engage in practice exercises and examples to reinforce understanding of differentiation and applications in the medical context.