Stoichiometry
Latin:
Stoichon ➝ element
Metron ➝ measure
Study of quantitative relationships between the amounts of reactants used and the amounts of products formed by a chemical reaction
Cost - you don't want to buy any more than you need
Saving on chemicals - less waste
Saving time - reducing guesswork by knowing exactly how much you need
Purity - you have a better idea of purity
N2 + 3H2 ➝ 2NH3
Atomic level: (conserved? yes)
2 nitrogen atoms are combining with 6 hydrogen atoms to form a compound with 8 atoms.
Molecules: (conserved? no.)
1 molecule of nitrogen is combining with 3 molecules of hydrogen to make two molecules of ammonia
Moles: (conserved? no.)
1 mole of nitrogen and 3 moles of hydrogen combine to make 2 moles of ammonia.
Grams: (conserved? yes)
28g of nitrogen and 6g of hydrogen combine to make 34g of ammonia.
Molar Volume: (conserved? no)
22.4L + 67.2L ➝ 44.8L
2NaClO3 ➝ 2NaCl + 3O2
100g / 106.3 (MM) x 2/2 x 58.35 (MM) ➝ 54.9g NaCl
2C6H14 + 19O2 ➝ 12CO2 + 14H2O
26/(12.011 x 6)x(1.00794\cdot14\right)
%Yield = Actual Amount / Theoretical Amount
50mL of .1M Lead Nitrate solution is reacted with excess Zinc. How many grams of Pb is made?
Zn (excess) + Pb(NO3)2 (50mL .1M) ➝ Pb (?) + Zn(NO3)2 (not relevant)
M = mol/Litres
.1 * .05L ➝ .005mol Lead Nitrate in solution
.005mol * 207.2g ➝ 1.036g Lead
How do you determine the limiting reactant?
3AgNO3 (aq)+ Na3PO4 (aq)➝ Ag3PO4 (s) + 3Na2NO3 (aq)
3g AgNO3 + 1g Na3PO4 ➝ (?) Ag3PO4 + (?) 3Na2NO3
Block out one, solve for 1 gram.
1g/163.87 (AgNO3) x 3/1 (mole ratio) x 169.8 (Ag3NO3) ➝ 3.11g AgNO3
AgNO3 runs out first. AgNO3 is the limiting reactant - because you need 3.11 grams for a complete reaction and there are only 3 grams.
3g AgNO3 + 1g Na3PO4 ➝ (?) Ag3PO4 + (?) 3Na2NO3
3g/169.8 (AgNO3) x 1/3 x 418.5 (Ag3PO4) ➝ 2.4g Ag3PO4f