Derivatives at a point
find derivative
Plug in x or y values
Equations of tangent and normal lines
Tangent line
find derivative (FINDS SLOPE)
Then find the POINT by plugging in x value to ORIGINAL equation
Put in point slope form
y - y1 = m(x-x1)
Normal line
Same steps
The slope will be the opposite sign and reciprocal of the tangent line equation
Horizontal Tangent Lines
Find derivative
Find when the derivative equals zero
These are your x-values
Plug in the x values found into the original equation
Vertical Tangent Lines
Find derivative
Find when the derivative is undefined (set equal zero)
Horizontal Tangent Lines Implicitly
Find derivative implicitly
Set the numerator equal to zero
Find both x and y
Plug into original equation
Eliminate any answers that do not work
Vertical Tangent Lines Implicitly
Find when denominator is 0
Solve for y in terms of x
Plug into original equation
Plug the x values found into the original equation to make sure it is valid
Derivative Motion
Things to know (position functions)
s(t) - location of an object in relation to a point or origin
Derivative of s(t) is velocity or v(t)
Derivative of v(t) is acceleration or a(t)
Speed
Speed is the absolute value of velocity
Speed is increasing if v(t) and a(t) are both the same sign
Speed is decreasing if v(t) and a(t) are different signs
A positive v(t): direction is right or up
A negative v(t): direction is left or down
Position
Set the function equal to the height and factor
Choose the value that matches the equation
Plug into the derivative (or whatever it is asking)
Average velocity
Displacement/change in time
f(b)-f(a)/b-a
Graphing Derivatives with Original Function
X- intercepts
Where the derivative equals zero (x-intercept) that is where the original functions local max and mins are
Slopes
The function has a positive slope, the derivative is positive (increasing)
The function has a negative slope, the derivative is negative (decreasing)
Concavity
Points of inflection for the functions are the derivatives local max and mins (THE SLOPE OF THOSE POINTS OF INFLECTION IS WHERE YOU PLACE THEM)
Absolute Extreme Values
Where an y value is larger or smaller than all y values on the domain
WORDING
Where they occur is x-value
Absolute max or min is the y-value
Infinity is not an absolute max or min
Extreme Value Theorem
If the function is continuous on an interval, there is guaranteed a max and min
Local Extreme Values
Largest or smallest value on SOME interval
Solving for max and min
A function can only have max or min when the FIRST DERIVATIVE is undefined or equal to zero
Steps
Find derivative
See where it becomes undefined or zero (critical value)
This is where you set the denominator to zero (for undefined)
This is where you set the numerator to zero (for equaling zero)
Check endpoints
Plug in the domain to the original function
Find the smallest and largest
Finding domain
Set the denominator not equal to zero (more than and less than)
Find x
Piecewise functions for finding max and mins
Find derivative of each piece separately
Check for continuity with double sided limit
Then check if it is undefined
Plug in the value where the piecewise function equals on both functions
If they do not equal, then the other critical value is the one that the function equals in the piecewise
Check limits to infinity to check if one is absolute
Absolute value
Prove that the absolute value is positive from stating that x is more than zero
This gets rid of the absolute value
Solve for critical points like normal but remember restriction on domain
Solve for both situations (where x could be negative)
Solve like normal (with different restriction)
Then plug into original equation
Increasing and decreasing
Find critical value
Make sign chart
determine the interval according to the sign chart
The x values are the local max or min depending on the direction of sign chart
If the signs do not change, no local extrema
First derivative test
Find derivative
Find where it is undefined or equals zero
Use those x values to make a sign chart
If signs change there are local extrema
Plug in the x-values that have extrema into original equation
How to tell if there is a absolute extrema there as well
Use limits to find end behavior
Concavity
Concave up
Second derivative is positive
Concave down
Second derivative is negative
Steps
Find second derivative
Find when it is undefined or zero
Use sign chart and write intervals
Points of inflection
This is when the concavity changes
Find the second derivative
Find undefined or when equal to zero
Sign chart
Plug into original equation (x-values that switch)
Put in (a,b) format
Second derivative test
When the second derivative is positive, the local maximum at the x value found
When the second derivative is negative, the local minimum is the x-value found
Steps:
Find first derivative
Find x-values at 0
Find second derivative and plug in the x-values
Graphing
Requires original function
X and y intercepts
Asymptotes
Requires first derivative
Increasing and decreasing
Max and min
Requires second derivative
Concavity
Points of inflection
Local Linearity
Given (a,f[a])
Linearization equation: y= f(a) + f’(a)[x-a]
Set up
Make the function in terms of x
Let x = number
Make the variable “a” something easy to solve
Writing to solve
Original function = f(number) ~ L(number) = linearization equation
Differentials
Using tangent lines to approximate the value of the function
Dy = f’(x) times dx
Set up
Dx is the difference between the two positions
Replace x with the first position
Implicitly
Solve like implicit differentiation
Word problems
take equation for what you are trying to solve
manipulate into linearization equation
Newton’s Method
x(n) + 1 = x(n) - f(xn)/f’(xn)
Set up
State continuity
Choose two values that create the root by IVT
Choose a guess inbetween those intervals
Plug into newton's method equation
Hit enter on calculator till two values match
Tangent and Secant Approximations
Concave up
Tangent underestimates true value
Secant overestimate true value
Concave down
Tangent overestimate true value
Secant understimates true value
Set up tangent line
Find derivative
Plug in x value given to both the derivative and regular
These give you your slope and second y value
Put into point slope form
Plug in the approx value into x
Proving
Find second derivative to see concavity (pos - up, neg - down)
Set up secant line
Use the domain given to find two ordered pairs
Find the slope of them
Plug into the y = mx + b at the approx value
Rolles Theorem
If both f(x) are equal to each other
This means that the derivative equals 0 for some “c” on interval
Set derivative equal to 0 and solve
Mean Value Theorem for Derivatives
[a,b]
F’c = f(b)-f(a)/b-a
Set up
Find derivative of function in terms of c and set equal to the MVT value to find c
L’hopitals rule
The limit as x approaches a of f(x)/g(x) is equal to the limit as x approaches a of the derivative of f’(x)/g’(x)
REMEMBER: state limits equal zero INDIVIDUALLY
Dealing with infinites
Simplify your trig functions