Objective: Assess a company's claim that its antacid tablet neutralizes ten times more stomach acid than a competitor's product.
Approach:
Conduct an experiment to compare the acid-neutralizing capacity of both products.
Use a controlled environment to measure pH changes when equivalent amounts of each antacid are added to a standardized amount of acid.
Analyze the data to determine if the claim holds under scientific scrutiny.
Scenario: Working for a chemical company to produce 6.0 kg of methanol (CH3OH).
Determination Steps:
Use the balanced equation for the production of methanol:
Unbalanced Reaction: CO(g) + H2(g) → CH3OH(l)
Balanced Reaction: CO(g) + 2H2(g) → CH3OH(l)
Calculate moles of methanol to be produced:
Molar mass of CH3OH = 32.04 g/mol.
Moles of methanol = 6000 g / 32.04 g/mol ≈ 187.5 moles.
Use mole ratios from the balanced reaction to find the required amounts of CO and H2:
Ratio: 1 mol CO to 2 mol H2.
Moles of CO needed = 187.5 moles (methanol) * (1 mol CO / 1 mol CH3OH) = 187.5 moles CO.
Moles of H2 needed = 187.5 moles (methanol) * (2 mol H2 / 1 mol CH3OH) = 375 moles H2.
Convert moles to grams for ordering:
Molar mass of CO = 28.01 g/mol; mass of CO = 187.5 moles * 28.01 g/mol ≈ 5250 g CO.
Molar mass of H2 = 2.02 g/mol; mass of H2 = 375 moles * 2.02 g/mol ≈ 757.5 g H2.
Chemical equations represent the identities and quantities of reactants and products.
Coefficients in a balanced equation indicate the relative number of molecules or moles involved in the reaction.
Analogy: Making sandwiches to understand mole ratios:
Equation: 2 pieces of bread + 3 slices of meat + 1 slice of cheese → 1 sandwich.
For 50 sandwiches: Multiply coefficients by 50 resulting in 100 pieces of bread, 150 slices of meat, and 50 slices of cheese.
Reactants and Products: CO(g) + 2H2(g) → CH3OH(l)
Balance and interpret the equation:
Reactants needed for 1 mole of methanol include 1 mole of CO and 2 moles of H2.
Mole Definition: 6.022 x 10^23 units (Avogadro's number).
Example Balancing:
For the reaction: CO(g) + 2H2(g) → CH3OH(l)
Alternative representation in terms of moles:
1 mol CO + 2 mol H2 → 1 mol CH3OH.
Chemical Reaction:
2H2O(l) → 2H2(g) + O2(g)
Calculation Example:
Given 4 mol of water:
From balanced equation: 2 mol H2O → 2 mol H2 + 1 mol O2.
Therefore, for 4 mol H2O:
Yields 4 mol H2 and 2 mol O2.
Example Problem: Finding O2 needed for 4.30 mol of propane reaction.
Balanced Equation: C3H8 + 5O2 → 3CO2 + 4H2O
Mole Ratio: 1 mol C3H8 requires 5 mol O2.
Calculation:
4.30 mol C3H8 × (5 mol O2 / 1 mol C3H8) = 21.5 mol O2 needed.