Redox Reactions
A redox reaction can be defined as a chemical reaction in which electrons are transferred between two reactants participating in it. This transfer of electrons can be identified by observing the changes in the oxidation states of the reacting species.
An illustration detailing the electron transfer between two reactants in a redox reaction is provided below.
In the illustration provided below, it can be observed that the reactant, an electron, was removed from reactant A, and this reactant is oxidized. Similarly, reactant B was handed an electron and was, therefore, reduced.
The loss of electrons and the corresponding increase in the oxidation state of a given reactant is called oxidation. The gain of electrons and the corresponding decrease in the oxidation state of a reactant is called reduction.
Electron-accepting species which tend to undergo a reduction in redox reactions are called oxidizing agents. An electron-donating species which tends to hand over electrons can be referred to as a reducing agent. These species tend to undergo oxidation. It can be noted that any redox reaction can be broken down into two half-reactions, namely, the oxidation half-reaction and the reduction half-reaction.
When writing these half-reactions separately, each of them must be balanced in a way that all the electrons are accounted for.
The different types of redox reactions are
Decomposition Reaction
Combination Reaction
Displacement Reaction
Disproportionation Reactions
This kind of reaction involves the breakdown of a compound into different compounds. Examples of these types of reactions are
2NaH → 2Na + H2
2H2O → 2H2 + O2
Na2CO3 → Na2O + CO2
All the above reactions result in the breakdown of smaller chemical compounds in the form of AB → A + B
But, there is a special case that confirms that all the decomposition reactions are not redox reactions.
For example, CaCO3 → CaO + CO2
Also Read: Types of Reactions
These reactions are the opposite of decomposition reactions and hence, involve the combination of two compounds to form a single compound in the form of A + B → AB. For example,
H2 + Cl2 → 2HClC+O2→CO2
4Fe+ 3O2→2Fe2O3
In this kind of reaction, an atom or an ion in a compound is replaced by an atom or an ion of another element. It can be represented in the form of X + YZ → XZ + Y. Further displacement reactions can be categorised into
Metal displacement reaction
Non-metal displacement reaction
In this type of reaction, a metal present in the compound is displaced by another metal. These types of reactions find their application in metallurgical processes where pure metals are obtained from their ores.
For example, CuSO4+Zn→Cu+ZnSO4
In this type of reaction, we can find a hydrogen displacement and, sometimes, rarely occurring reactions involving oxygen displacement.
Disproportionation reactions are known as reactions in which a single reactant is oxidized and reduced.
For example, P4 + 3NaOH + 3H2O → 3NaH2PO2 + PH3
A few examples of redox reactions, along with their oxidation and reduction half-reactions, are provided in this subsection.
In the reaction between hydrogen and fluorine, the hydrogen is oxidized, whereas the fluorine is reduced. The reaction can be written as follows.
H2 + F2 → 2HF
The oxidation half-reaction is: H2 → 2H+ + 2e–
The reduction half-reaction is: F2 + 2e– → 2F–
The hydrogen and fluorine ions go on to combine in order to form hydrogen fluoride.
This is a type of metal displacement reaction in which copper metal is obtained when zinc displaces the Cu2+ion in the copper sulphate solution, as shown in the reaction below.
Zn (s) + CuSO4 (aq) → ZnSO4 (aq) + Cu (s)
The oxidation half-reaction can be written as Zn → Zn2+ + 2e–
The reduction half-reaction can be written as Cu2+ + 2e– → Cu
Thus, copper is displaced from the copper sulphate solution by zinc in a redox reaction.
Fe2+ is oxidized to Fe3+ by hydrogen peroxide when an acid is present. This reaction is provided below.
2Fe2+ + H2O2 + 2H+ → 2Fe3+ + 2H2O
Oxidation half-reaction: Fe2+ → Fe3+ + e–
Reduction half-reaction: H2O2 + 2e– → 2 OH–
Thus, the hydroxide ion formed from the reduction of hydrogen peroxide combines with the proton donated by the acidic medium to form water.
In order to understand redox reactions, let us first deal with oxidation and reduction reactions individually.
Oxidation may be defined as the loss of electrons from a substance; the other definition of oxidation reactions states that the addition of oxygen or the more electronegative element or removal of hydrogen or the more electropositive element from a substance is called an oxidation reaction.
Following are some examples of oxidation reactions:
2S(s) + O2 (g) → SO2 (g) CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l)
Like oxidation reactions, reduction reactions are defined as the gain of electrons. Any substance that gains electrons during a chemical reaction gets reduced.
In other forms, the reduction reaction is stated as the addition of hydrogen or a more electropositive element or the removal of a more electronegative element or oxygen from a substance.
Below are some examples of reduction reactions:
2CH2CH2 (g) + H2 (g) → CH3CH3 (g)
2FeCl3 (aq) + H2 (g) → 2FeCl2 (aq) + 2HCl (aq)
Now, if we closely examine the above reaction, we would find that all the reactions above have both reduction and oxidation reactions.
The reaction in which FeCl3 is getting reduced as electronegative element chlorine is being removed from it. At the same time, hydrogen is getting oxidized due to the addition of chlorine, an electronegative element, in the same reaction.
The substance (atom, ion and molecule) that gains electrons and is thereby reduced to a low valency state is called an oxidising agent.
The substance that loses electrons and is thereby oxidised to a higher valency state is called a reducing agent.
Molecules are made up of electronegative elements. Eg: O2, O3, and X2 (halogens)
Compounds containing an element that is in the higher oxidized state. Eg: KMnO4, K2Cv2O7, HNO3, KClo3
Oxides of metals and non-metals. Eg: MgO, CuO, CrO3, P4O10
Fluorine is the strongest oxidizing agent.
All metals, for example, Na, Zn, Fe, Al
A few non-metals, such as C, Hydrogen, S, P
Hydracids, for example, HCl, HBr, HI, H2S
A few compounds contain an element in the lower oxidation state. Examples include, FeCl2, FeSo4, SnCl2, Hg2Cl2
Metallic hydrides, including NaH, LiH, CaH2, etc.
Organic compounds like HCOOH
Lithium is the strongest reducing agent in the solution, and caesium is the strongest reducing agent in the absence of water. The substances which act as oxidizing as well as reducing agents are H2O2, SO2, H2SO3, HNO2 and NaNO2
Each half-reaction that makes up a redox reaction has a standard electrode potential. This potential equals the voltage produced by an electrochemical cell in which the cathode reaction is the half-reaction considered, whereas the anode is a standard hydrogen electrode.
This voltage produced by the half-reactions is called their reduction potentials (denoted by E0red). The value of the reduction potential of a half-reaction is positive for the oxidizing agents that are stronger than H+ and negative for the weaker ones.
Examples of the reduction potentials of some species are +2.866 V for F2 and -0.763 V for Zn2+.
If an element is in its higher possible oxidation state in a compound, it can function as an oxidising agent. Eg: KMnO4, K2Cr2O7, HNO3, H2SO4 and HClO4
If an element is in its possible lower oxidation state in a compound, it can function as a reducing agent. Eg: H2S, H2C2O4, FeSO4 and SnCl2
The compound will act as an oxidising agent if a highly electronegative element is in its highest oxidation state.
The compound acts as a reducing agent if a highly electronegative element is in its lowest oxidation state.
There are two ways of balancing the redox reaction. One method is by using the change in oxidation number of oxidizing agent and the reducing agent, and the other method is based on dividing the redox reaction into two half reactions-one of reduction and another of oxidation.
Example 1: Write the balanced redox equation when ferrous sulphate is treated with acidified (H2SO4) Potassium Permanganate.
Step I
𝐾𝑀𝑛𝑂4+𝐻2𝑆𝑂4+𝐹𝑒𝑆𝑂4→𝐾2𝑆𝑂4+𝑀𝑛𝑆𝑂4+𝐹𝑒2(𝑆𝑂4)3+𝐻2𝑂
Step II
Thus, here Mn+7 is reduced to Mn+2
This method is based on the fact that the number of electrons gained during the reduction reaction equals the number of electrons lost in oxidation.
Fe2+ is oxidised to Fe3+ oxidation:
2𝐹𝑒2+→𝐹𝑒2+3+2𝑒−[𝑜𝑥𝑖𝑑𝑎𝑡𝑖𝑜𝑛]
Reduction:
𝑀𝑛+7+5𝑒−→𝑀𝑛+2[𝑅𝑒𝑑𝑢𝑐𝑖𝑡𝑜𝑛]
Multiply the oxidation reaction by 5 and the reduction reaction by 2.
By substituting coefficient
2𝐾𝑀𝑛𝑂4+10𝐹𝑒𝑆𝑂4+𝐻2𝑆𝑂4→𝐾2𝑆𝑂4+5𝐹𝑒2(𝑆𝑂4)3+2𝑀𝑛𝑆𝑂4+𝐻2𝑂
𝐵𝑎𝑙𝑎𝑛𝑐𝑒 𝑆𝑂4−2 𝑏𝑦 𝑚𝑢𝑙𝑡𝑖𝑝𝑙𝑦𝑖𝑛𝑔 𝑤𝑖𝑡ℎ 8
⇒
2𝐾𝑀𝑛𝑂4+10𝐹𝑒𝑆𝑂4+8𝐻2𝑆𝑂4→𝐾2𝑆𝑂4+5𝐹𝑒2(𝑆𝑂4)3+2𝑀𝑛𝑆𝑂4+8𝐻2𝑂
Steps:
Divide the complete reaction into two half-reactions, one representing oxidation and the other representing reduction.
First, balance other than ‘O’ and ‘H’ atoms.
In an acidic or neutral medium, balance oxygen atoms by adding H2O molecules and balance H-atoms by adding H+ ions.
In an alkaline medium, the oxygen atom is balanced by adding an H2O molecule, and an equal number of
𝑂𝐻Θ
ions are added on the opposite side, H+ atoms still unbalanced add OH–
Balance the charges by the addition of electrons.
Multiply with a suitable integer such that the number of electrons gets cancelled.
Add both the half-reactions, similar terms are subtracted, and the final equation is written.
Example 1: Balance the following redox reaction in the acid medium by the ion-electron method.
A redox reaction can be defined as a chemical reaction in which electrons are transferred between two reactants participating in it. This transfer of electrons can be identified by observing the changes in the oxidation states of the reacting species.
An illustration detailing the electron transfer between two reactants in a redox reaction is provided below.
In the illustration provided below, it can be observed that the reactant, an electron, was removed from reactant A, and this reactant is oxidized. Similarly, reactant B was handed an electron and was, therefore, reduced.
The loss of electrons and the corresponding increase in the oxidation state of a given reactant is called oxidation. The gain of electrons and the corresponding decrease in the oxidation state of a reactant is called reduction.
Electron-accepting species which tend to undergo a reduction in redox reactions are called oxidizing agents. An electron-donating species which tends to hand over electrons can be referred to as a reducing agent. These species tend to undergo oxidation. It can be noted that any redox reaction can be broken down into two half-reactions, namely, the oxidation half-reaction and the reduction half-reaction.
When writing these half-reactions separately, each of them must be balanced in a way that all the electrons are accounted for.
The different types of redox reactions are
Decomposition Reaction
Combination Reaction
Displacement Reaction
Disproportionation Reactions
This kind of reaction involves the breakdown of a compound into different compounds. Examples of these types of reactions are
2NaH → 2Na + H2
2H2O → 2H2 + O2
Na2CO3 → Na2O + CO2
All the above reactions result in the breakdown of smaller chemical compounds in the form of AB → A + B
But, there is a special case that confirms that all the decomposition reactions are not redox reactions.
For example, CaCO3 → CaO + CO2
Also Read: Types of Reactions
These reactions are the opposite of decomposition reactions and hence, involve the combination of two compounds to form a single compound in the form of A + B → AB. For example,
H2 + Cl2 → 2HClC+O2→CO2
4Fe+ 3O2→2Fe2O3
In this kind of reaction, an atom or an ion in a compound is replaced by an atom or an ion of another element. It can be represented in the form of X + YZ → XZ + Y. Further displacement reactions can be categorised into
Metal displacement reaction
Non-metal displacement reaction
In this type of reaction, a metal present in the compound is displaced by another metal. These types of reactions find their application in metallurgical processes where pure metals are obtained from their ores.
For example, CuSO4+Zn→Cu+ZnSO4
In this type of reaction, we can find a hydrogen displacement and, sometimes, rarely occurring reactions involving oxygen displacement.
Disproportionation reactions are known as reactions in which a single reactant is oxidized and reduced.
For example, P4 + 3NaOH + 3H2O → 3NaH2PO2 + PH3
A few examples of redox reactions, along with their oxidation and reduction half-reactions, are provided in this subsection.
In the reaction between hydrogen and fluorine, the hydrogen is oxidized, whereas the fluorine is reduced. The reaction can be written as follows.
H2 + F2 → 2HF
The oxidation half-reaction is: H2 → 2H+ + 2e–
The reduction half-reaction is: F2 + 2e– → 2F–
The hydrogen and fluorine ions go on to combine in order to form hydrogen fluoride.
This is a type of metal displacement reaction in which copper metal is obtained when zinc displaces the Cu2+ion in the copper sulphate solution, as shown in the reaction below.
Zn (s) + CuSO4 (aq) → ZnSO4 (aq) + Cu (s)
The oxidation half-reaction can be written as Zn → Zn2+ + 2e–
The reduction half-reaction can be written as Cu2+ + 2e– → Cu
Thus, copper is displaced from the copper sulphate solution by zinc in a redox reaction.
Fe2+ is oxidized to Fe3+ by hydrogen peroxide when an acid is present. This reaction is provided below.
2Fe2+ + H2O2 + 2H+ → 2Fe3+ + 2H2O
Oxidation half-reaction: Fe2+ → Fe3+ + e–
Reduction half-reaction: H2O2 + 2e– → 2 OH–
Thus, the hydroxide ion formed from the reduction of hydrogen peroxide combines with the proton donated by the acidic medium to form water.
In order to understand redox reactions, let us first deal with oxidation and reduction reactions individually.
Oxidation may be defined as the loss of electrons from a substance; the other definition of oxidation reactions states that the addition of oxygen or the more electronegative element or removal of hydrogen or the more electropositive element from a substance is called an oxidation reaction.
Following are some examples of oxidation reactions:
2S(s) + O2 (g) → SO2 (g) CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l)
Like oxidation reactions, reduction reactions are defined as the gain of electrons. Any substance that gains electrons during a chemical reaction gets reduced.
In other forms, the reduction reaction is stated as the addition of hydrogen or a more electropositive element or the removal of a more electronegative element or oxygen from a substance.
Below are some examples of reduction reactions:
2CH2CH2 (g) + H2 (g) → CH3CH3 (g)
2FeCl3 (aq) + H2 (g) → 2FeCl2 (aq) + 2HCl (aq)
Now, if we closely examine the above reaction, we would find that all the reactions above have both reduction and oxidation reactions.
The reaction in which FeCl3 is getting reduced as electronegative element chlorine is being removed from it. At the same time, hydrogen is getting oxidized due to the addition of chlorine, an electronegative element, in the same reaction.
The substance (atom, ion and molecule) that gains electrons and is thereby reduced to a low valency state is called an oxidising agent.
The substance that loses electrons and is thereby oxidised to a higher valency state is called a reducing agent.
Molecules are made up of electronegative elements. Eg: O2, O3, and X2 (halogens)
Compounds containing an element that is in the higher oxidized state. Eg: KMnO4, K2Cv2O7, HNO3, KClo3
Oxides of metals and non-metals. Eg: MgO, CuO, CrO3, P4O10
Fluorine is the strongest oxidizing agent.
All metals, for example, Na, Zn, Fe, Al
A few non-metals, such as C, Hydrogen, S, P
Hydracids, for example, HCl, HBr, HI, H2S
A few compounds contain an element in the lower oxidation state. Examples include, FeCl2, FeSo4, SnCl2, Hg2Cl2
Metallic hydrides, including NaH, LiH, CaH2, etc.
Organic compounds like HCOOH
Lithium is the strongest reducing agent in the solution, and caesium is the strongest reducing agent in the absence of water. The substances which act as oxidizing as well as reducing agents are H2O2, SO2, H2SO3, HNO2 and NaNO2
Each half-reaction that makes up a redox reaction has a standard electrode potential. This potential equals the voltage produced by an electrochemical cell in which the cathode reaction is the half-reaction considered, whereas the anode is a standard hydrogen electrode.
This voltage produced by the half-reactions is called their reduction potentials (denoted by E0red). The value of the reduction potential of a half-reaction is positive for the oxidizing agents that are stronger than H+ and negative for the weaker ones.
Examples of the reduction potentials of some species are +2.866 V for F2 and -0.763 V for Zn2+.
If an element is in its higher possible oxidation state in a compound, it can function as an oxidising agent. Eg: KMnO4, K2Cr2O7, HNO3, H2SO4 and HClO4
If an element is in its possible lower oxidation state in a compound, it can function as a reducing agent. Eg: H2S, H2C2O4, FeSO4 and SnCl2
The compound will act as an oxidising agent if a highly electronegative element is in its highest oxidation state.
The compound acts as a reducing agent if a highly electronegative element is in its lowest oxidation state.
There are two ways of balancing the redox reaction. One method is by using the change in oxidation number of oxidizing agent and the reducing agent, and the other method is based on dividing the redox reaction into two half reactions-one of reduction and another of oxidation.
Example 1: Write the balanced redox equation when ferrous sulphate is treated with acidified (H2SO4) Potassium Permanganate.
Step I
𝐾𝑀𝑛𝑂4+𝐻2𝑆𝑂4+𝐹𝑒𝑆𝑂4→𝐾2𝑆𝑂4+𝑀𝑛𝑆𝑂4+𝐹𝑒2(𝑆𝑂4)3+𝐻2𝑂
Step II
Thus, here Mn+7 is reduced to Mn+2
This method is based on the fact that the number of electrons gained during the reduction reaction equals the number of electrons lost in oxidation.
Fe2+ is oxidised to Fe3+ oxidation:
2𝐹𝑒2+→𝐹𝑒2+3+2𝑒−[𝑜𝑥𝑖𝑑𝑎𝑡𝑖𝑜𝑛]
Reduction:
𝑀𝑛+7+5𝑒−→𝑀𝑛+2[𝑅𝑒𝑑𝑢𝑐𝑖𝑡𝑜𝑛]
Multiply the oxidation reaction by 5 and the reduction reaction by 2.
By substituting coefficient
2𝐾𝑀𝑛𝑂4+10𝐹𝑒𝑆𝑂4+𝐻2𝑆𝑂4→𝐾2𝑆𝑂4+5𝐹𝑒2(𝑆𝑂4)3+2𝑀𝑛𝑆𝑂4+𝐻2𝑂
𝐵𝑎𝑙𝑎𝑛𝑐𝑒 𝑆𝑂4−2 𝑏𝑦 𝑚𝑢𝑙𝑡𝑖𝑝𝑙𝑦𝑖𝑛𝑔 𝑤𝑖𝑡ℎ 8
⇒
2𝐾𝑀𝑛𝑂4+10𝐹𝑒𝑆𝑂4+8𝐻2𝑆𝑂4→𝐾2𝑆𝑂4+5𝐹𝑒2(𝑆𝑂4)3+2𝑀𝑛𝑆𝑂4+8𝐻2𝑂
Steps:
Divide the complete reaction into two half-reactions, one representing oxidation and the other representing reduction.
First, balance other than ‘O’ and ‘H’ atoms.
In an acidic or neutral medium, balance oxygen atoms by adding H2O molecules and balance H-atoms by adding H+ ions.
In an alkaline medium, the oxygen atom is balanced by adding an H2O molecule, and an equal number of
𝑂𝐻Θ
ions are added on the opposite side, H+ atoms still unbalanced add OH–
Balance the charges by the addition of electrons.
Multiply with a suitable integer such that the number of electrons gets cancelled.
Add both the half-reactions, similar terms are subtracted, and the final equation is written.
Example 1: Balance the following redox reaction in the acid medium by the ion-electron method.