Gases are one of the four phases of matter.
Key characteristics of gases include:
Expand to fill their container.
Exert pressure on container surfaces and objects within.
Essential for everyday life (e.g., air as a mixture of O2 and N2).
Pressure (P) is defined as the force (F) exerted over a given area (A).
Formula: 𝑃 = 𝐹 / 𝐴.
Forces exerted by gases contribute to pressure, including atmospheric pressure.
Units:
Force is measured in Newtons (N).
Pressure is measured in Pascals (Pa).
Conversion: 1 Pa = 1 kg/m·s² = 1 N/m².
On the moon, with a mass of 68 kg:
Weight on the moon due to gravity (1.6 m/s²): (673 N = 68 kg imes 1.6 m/s²).
Area standing on: (0.5 m \times 0.5 m = 0.25 m²).
Pressure exerted: (P = \frac{670 N}{0.25 m²} = 2700 Pa).
High pressure under stiletto heels can cause pain due to small surface area.
The most relatable pressure experienced daily is atmospheric pressure.
Measurement tools:
Manometer for measuring gas pressure.
Barometer for measuring atmospheric pressure (mm Hg unit).
Standard atmospheric pressure:
1 atm = 101,325 Pa = 760 mm Hg = 760 torr.
Derived by Boyle, Charles, and Avogadro:
Boyle’s Law: Pressure is inversely proportional to volume (at constant temperature).
Formula: 𝑃𝑉 = 𝑘 or (P_1V_1 = P_2V_2).
Charles’s Law: Volume of a gas is directly proportional to its temperature (in Kelvins) at constant pressure.
Formula: ( \frac{V}{T} = b ) or ( V = bT ), (V_1/T_1 = V_2/T_2).
Avogadro’s Law: Volume is directly proportional to the number of moles of a gas at constant temperature and pressure.
Formula: ( V = an ), (V_1/n_1 = V_2/n_2).
Boyle's Law Example:
Given: 1.3 atm, 27 L → What is the volume at 3.9 atm?
Prediction: Increasing pressure will decrease volume.
Calculation: (1.3 atm (27 L) = 3.9 atm (V_2)) → (V_2 = 9.0 L).
Charles's Law Example:
Given: Volume 0.842 L at 30°C, find volume at 60°C.
Conversion to K: T1 = 303 K, T2 = 333 K.
Calculation: (V_2 = \frac{0.842 L \cdot 333 K}{303 K} = 0.925 L).
Avogadro's Law Example:
Given: 5.20 L with 0.436 moles, if an additional 1.27 moles is added at the same conditions, find new volume.
Total moles = 1.706, predicting volume increase to: (V_2 = 20.3 L).
Combines Boyle’s, Charles’s, and Avogadro’s laws.
Expresses state of a gas: (PV = nRT), where:
P = pressure (atm)
V = volume (L)
n = number of moles
R = 0.08206 (L atm)/(K mol)
T = temperature (Kelvin).
Given: 0.614 moles, 12.0°C, volume 12.9 L; find pressure.
Conversion: T = 285 K.
Use ideal gas equation: (P = \frac{(n)(R)(T)}{V} = 1.11 atm).
Molar Volume: Volume of 1 mole of gas at STP (0 °C, 1 atm): (22.42 L).
Use molar volume and gas laws for calculations.
Molar mass can be determined using density: (MM = \frac{dRT}{P}).
Reaction: 2H2(g) + O(g) → 2H2O(g).
0.500 L H2 reacts with 0.600 L O at STP;
Need to determine limiting reactant.
Calculate volume of H2O produced: Result = 1.14 L.
States total pressure = sum of partial pressures of individual gases: (P_{total} = P_1 + P_2 + ... + P_n).
Mole fraction: Ratio relating number of moles of component to total moles; (χ_i = \frac{n_i}{n_{total}} = \frac{P_i}{P_{total}}).
Calculating total pressure after adding He to a vessel containing N2:
Concluded partial pressures and total pressure both calculated and verified.
Postulates:
Gas particle volume is negligible.
Particles are in constant motion; collisions create pressure.
Particles exert no forces on one another.
Average kinetic energy relates directly to Kelvin temperature.
Formula for average KE: (KE_{average} = \frac{3}{2}RT) or (KE = \frac{1}{2}mv^2).
Root Mean Square Velocity:
(u_{rms} = \sqrt{\frac{3RT}{M}}).
Diffusion: Mixing of gases.
Effusion: Gas passage through an orifice.
Graham’s Law: Rate of effusion inversely proportional to mass of gas.
Adjusted ideal gas equation: Van der Waals equation includes corrections for pressure and volume.