Trigonometric functions relate angles to ratios and have a graphical representation.
Function to graph: ( f(x) = -2 \cos(4x) + 2 )
Involves multiple transformations of the cosine function.
Begin with the graph of ( \cos(x) ):
Oscillates between 1 and -1.
Has a period of ( 2\pi ).
Find ( \cos(4x) ):
The period is given by ( \frac{2\pi}{b} ), where ( b = 4 ).
Therefore, the period of ( \cos(4x) ) is ( \frac{2\pi}{4} = \frac{\pi}{2} ).
It completes four periods in the interval ( [0, 2\pi] ).
Scaling by -2:
Flips the graph of ( \cos(4x) ) across the x-axis.
Oscillation range changes from between -1 and 1 to between -2 and 2, maintaining the period of ( \frac{\pi}{2} ).
Add a vertical shift of +2:
Final function oscillates between 0 and 4.
Midline shifts to ( y = 2 ).
Final function is: ( f(x) = -2 \cos(4x) + 2 )
Key features:
Amplitude: 2
Period: ( \frac{\pi}{2} )
Midline: ( y = 2 )
Graph shown; need to identify the function.
Look for:
Amplitude: 1
Midline: ( y = 0 )
Period: 2\pi;
Crest of the wave starts at ( -\frac{\pi}{4} ) and ends at ( \frac{7\pi}{4} ).
Can be modeled as either:
Cosine function: ( \cos(x + \frac{\pi}{4}) )
Phase shift: ( \frac{\pi}{4} ) to the left.
Sine function: ( \sin(x + \frac{3\pi}{4}) )
Phase shift: ( \frac{3\pi}{4} ) to the left.
Analyzing another graph, focus again on key features:
Amplitude: 3
Midline: ( y = 0 )
Determine period:
Full rotation observed, period is 2.
Initially, assume a sine function: ( 3 \sin(a \cdot x) )
Relate period with the coefficient: ( \text{If period is 2, then } \frac{2\pi}{b} = 2. )
Solve for b:
( b = \pi. )
Function modeled as ( 3 \sin(\frac{\pi}{2} x) ) or other suitable transformations satisfied.