Light inside a high refractive index medium reaches a boundary with lower refractive index medium at angle to normal greater than critical angle. Ray of light completely reflected from boundary back into first medium - no energy refracted out. Critical angle depends on medium.
Critical angle: the angle of incidence at boundary between 2 media which produces an angle of refraction 90degrees.
- We can calculate from Snell’s Law when θ2 = 90degrees
- If media 2 is air, n2=1, therefore n1sinC = 1, sinC = 1/n
- n1sinθ1 = n2sinθ2 (light ray leaving). When θ2 = 90degrees, sinθ2=1, so n1sinθ1=n2, which means θ1is the maximum angle of refraction.
- θ1 = C (critical angle)
- For a light in a medium with refractive index n meeting an air boundary, sinC=1/n
- For different boundaries, equation will be different
- The greater the refractive index, the smaller the C
Measuring refractive index:
- Ray enters semi-circular block at 90degrees to curved boundary so direction doesn’t change.
- Angle to the normal at flat edge is changed till TIR occurs
- Critical angle C is measured and thus calculate n.
TIR uses - optical fibres
- Typically has inner core glass )n=2) and cladding glass layer outside (n=1.5)
- Light in core undergoes TIR at boundary with cladding
- It is NOT a hollow pipe
TIR can happen anywhere waves meet boundary with medium where they travel more quicky.
- E.g. sounds waves in water meeting the side of metal boat (sound travels faster in metal)
/