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Chapter 6: Random Variables

6.1 Discrete and Continuous Random Variables

Discrete Random Variables:

  • Random Variable represents the possible outcomes of a random process

    • AKA Random Result

    • Ex: X = number of heads in three tosses

    • Always a capital, italic letter (like X or Y)

  • The Probability distribution describes the likelihood of various outcomes (random variables), along with their probabilities.

    • Two Requirements:

    • Every probability pi is a number between 0 and 1, inclusive.

    • The sum of the probabilities is 1: p1 + p2 + p3 + . . . = 1.

  • A discrete random variable has specific, separate, and often whole number values / outcomes

    • Like (1, 2, 3, etc.) on a die

    • Discrete usually counts

      • Digital input in CS

      • Ex: like number of siblings

  • For random variabilities (probability in general), use mean instead of median

    • Mean is represented as mu or μ (usually with a subscript of the random variable)

    • Ex: Random Variable X, mean = μx

Analyzing Discrete Random Variables

  • In a Histogram, analyze: shape, center, and variability

  • Shape Options: Skewed Left/Right & Symmetric

    • Symmetric can be bimodal or unimodal

    • Normal curve is always symmetric unimodal

    • Ex: The graph is roughly symmetric and has a single peak at $600

  • Mean (expected value) of a discrete random variable is the average value in a random process

    • Important Part: Expected Value takes frequency into consideration

      • Don’t take an average of Random Variables (X), since each random variables have different weights / frequencies than others.

    • Formula: μ_x = E(X) = x1p1 + x2p2 + x3p3 + … = xi * pi

    • Ti-Nispire Usage:

      • Spreadsheet → Enter Data into 2 Columns

      • Menu → Statics → Stat Calculations → Two-Variable Statistics

      • Answer is value of ∑ xy

  • Median is when the cumulative probability equals or exceeds 0.5

  • Standard Deviation aka σ (omega)

    • Ti-Nispire Usage:

      • Spreadsheet → Enter Data into 2 Columns

      • Menu → Statics → Stat Calculations → Two-Variable Statistics

      • Answer is value of σx

    • Variance is (Standard Deviation)²

Discrete Random Variable Example Problem:

Continuous Random Variables:

  • A Continuous Random Variable takes any value in an interval on the number line (range)

    • Continuous usually measures

      • Analog input in Computer Science

      • Ex: height of a student or time to run a mile

  • To find its probabilities, use a Density Curve

      • 1/9 × 9 = 1 (Probability always adds to 1)

Continuous Example Problem:

Question: Would it be faster to take the train or walk? Walking takes 4 mins. What is the probability that Selena's train journey time to work is shorter than her walking time, given that her train journey time (Y) follows a uniform distribution from 2 to 5 minutes?

Solution:

  1. Identify Continuous vs Discrete. This situation involves time (measured), so continuous .

  2. Form the density curve: 5.0 - 2.0 = 3 → 3 × 1/3 = 1 (Probability adds to 1)

  3. Calculate Shaded Area: base × height = (4.0 - 2.0 ) × 1/3 = 2/3

  4. → P(Y < 4) = 2/3 = 0.667

  5. Sentence: There is a 66.7% chance that it will be quicker for Selena to take the train to work on a randomly selected day.

Question: The heights of young women can be modeled by a Normal distribution with mean µ = 64 inches and standard deviation σ = 2.7 inches. Suppose we choose a young woman at random and let Y = her height (in inches). Find P(68 ≤ Y ≤ 70). Interpret this value.

TODO: Insert Normal Curve Drawing

Answer: normalCdf(lower: 68, upper: 70, mean: 64, SD: 2.7) = 0.051


6.2 Transforming and Combining Random Variables

  • Adding the same positive number a to (subtracting a from) each value of a random variable:

    • Adds a to (subtracts a from) measures of center and location (mean, median, quartiles, percentiles).

      • Mean of Sum/Difference of Random Variables: μs = μx+-y = μx +- μY

    • Does not change measures of variability (range, IQR, standard deviation).

      • Variance adds (and subtracts), standard deviations do not add / subtract.

    • Does not change the shape of the probability distribution.

  • Multiplying (or dividing) each value of a random variable by the same positive number b:

    • Multiplies (divides) measures of center and location (mean, median, quartiles, percentiles) by b.

    • Multiplies (divides) measures of variability (range, IQR, standard deviation) by b.

    • Does not change the shape of the distribution.

  • Linear Transformation: If Y = a+ bX is a linear transformation of the random variable X,

    • The distribution of Y has same shape as the probability distribution of X if b > 0

    • μY = a+ bμX

    • σY = |b|σX (because b could be a negative number)

Adding / Subtracting Example Problem:

Question: Score X of a randomly selected student on a test worth 50 points can be modeled by a Normal distribution with mean 35 and standard deviation 5. Professor decides to add 5 points to
each student’s score. Let Y be the scaled test score of the randomly selected student. Describe the shape, center, and variability of the probability distribution of Y.

Answer:

  • Shape: Approximately Normal

  • Center: µY = µX + 5 = 35 + 5 = 40

  • Variability: σY = σX = 5

Multiplying / Dividing Example Problem:

Question: Student is full-time if taking 12 and 18 units. The number of units X that a randomly selected El Dorado Community College full-time student is taking (see histogram). Mean is µX = 14.65 and the standard deviation is σX = 2.056. Tuition is $50 per unit. If T = tuition charge for a
randomly selected full-time student, T = 50X.

Answer:

  • Shape: Same shape as the probability distribution of X, roughly symmetric with three peaks.

  • Center: µT = 50µX = 50(14.65) = $732.50

  • Variability: σT = 50σX = 50(2.056) = $102.80

Linear Transformation Example Problem:

Question: Let X = the number of passengers on a randomly selected trip at Pete’s Jeep Tours. Let Y = the number of passengers on a randomly selected trip at Erin’s Adventures. What is the sum S = X + Y of the number of passengers Pete and Erin will have on their tours on a randomly selected day?

Answer:

6.3 Binomial and Geometric:

Binomial Random Variables

  • Binomial Setting is when n independent trials are committed with a sauce chance of an outcome (aka success) occurs. Test using BINS

    • Binary? Possible outcomes should be “success” or “failure”

    • Independent? Trials must be independent. Knowing the outcome of one trial can’t determine another trial.

    • Number? The number of trials must be fixed in advance

    • Same Probability? Probability must be of success p on each trial.

  • Binomial Random Variable is the count of successes X in a binomial setting (literally a discrete variable)

  • Binomial Distribution is the probability distribution of X.

    • n trials and probability p of success on each trial.

  • Binomial Coefficient arranges k successes with n trials.

    • (n/k) = (n! / ( k! * (n-k)! ))

  • Binomial Probability Formula uses the Binomial Coefficient

    • Actual formula on equation sheet - P(X = x) = (n / x)…

    • binompdf (n,p,k) computes P(X = k)

    • binomcdf (n,p,k) computes P(X k)

  • Steps to find Binomial Probabilities:

    • State the distribution and the values of interest. Specify a binomial distribution with the number of trials n, success probability p, and the values of the variable clearly identified.

    • Perform the calculations, show calculator steps (or formula)

    • Be sure to answer the question

  • Center & Variability (Only for Binomial Distributions):

    • Mean - μx = E(X) = np

    • SD: σX = root( np * (1 - p) )

  • 10% Rule: A distribution will be approximately binomial when the sample size n is less than 10% of the population (Overrides BINS)

    • # of trials < 0.10 * population

    • Ex: A starburst bag comes with 200 candies. 25% chance one candy is red. This is not independent, and fails BINS. But since there are more than 200 starbursts in the world, the 10% rule applies. This distribution is approximately binomial.

  • Large Counts Condition: probability distribution of X is approximately normal if:

    • np ≧ 10 AND n( 1-p ) ≧ 10

    • AKA: Expected Numbers (mean) of successes and failures is at least 10

Geometric Random Variables

  • Geometric setting exists when the number of trials is unknown. Independent trials are performed until one success is made. Must be independent and p of success must be same.

  • Geometric Random Variable is the number of trials Y it takes to get a success

  • Geometric Probability Formula with Y geometric distribution, p probability of success, k is a specific term/trial

    • Actual formula on equation sheet - P(X = x) = ( 1 - p)…

    • geometpdf (p,k) computes P(X = k)

    • geometcdf (p,k) computes P(X k)

  • Shape: Every Geometric Distribution is skewed right (no exceptions)

  • Center: μx = E(X) = 1/p

  • SD: σX = root( 1 - p) / p

MG

Chapter 6: Random Variables

6.1 Discrete and Continuous Random Variables

Discrete Random Variables:

  • Random Variable represents the possible outcomes of a random process

    • AKA Random Result

    • Ex: X = number of heads in three tosses

    • Always a capital, italic letter (like X or Y)

  • The Probability distribution describes the likelihood of various outcomes (random variables), along with their probabilities.

    • Two Requirements:

    • Every probability pi is a number between 0 and 1, inclusive.

    • The sum of the probabilities is 1: p1 + p2 + p3 + . . . = 1.

  • A discrete random variable has specific, separate, and often whole number values / outcomes

    • Like (1, 2, 3, etc.) on a die

    • Discrete usually counts

      • Digital input in CS

      • Ex: like number of siblings

  • For random variabilities (probability in general), use mean instead of median

    • Mean is represented as mu or μ (usually with a subscript of the random variable)

    • Ex: Random Variable X, mean = μx

Analyzing Discrete Random Variables

  • In a Histogram, analyze: shape, center, and variability

  • Shape Options: Skewed Left/Right & Symmetric

    • Symmetric can be bimodal or unimodal

    • Normal curve is always symmetric unimodal

    • Ex: The graph is roughly symmetric and has a single peak at $600

  • Mean (expected value) of a discrete random variable is the average value in a random process

    • Important Part: Expected Value takes frequency into consideration

      • Don’t take an average of Random Variables (X), since each random variables have different weights / frequencies than others.

    • Formula: μ_x = E(X) = x1p1 + x2p2 + x3p3 + … = xi * pi

    • Ti-Nispire Usage:

      • Spreadsheet → Enter Data into 2 Columns

      • Menu → Statics → Stat Calculations → Two-Variable Statistics

      • Answer is value of ∑ xy

  • Median is when the cumulative probability equals or exceeds 0.5

  • Standard Deviation aka σ (omega)

    • Ti-Nispire Usage:

      • Spreadsheet → Enter Data into 2 Columns

      • Menu → Statics → Stat Calculations → Two-Variable Statistics

      • Answer is value of σx

    • Variance is (Standard Deviation)²

Discrete Random Variable Example Problem:

Continuous Random Variables:

  • A Continuous Random Variable takes any value in an interval on the number line (range)

    • Continuous usually measures

      • Analog input in Computer Science

      • Ex: height of a student or time to run a mile

  • To find its probabilities, use a Density Curve

      • 1/9 × 9 = 1 (Probability always adds to 1)

Continuous Example Problem:

Question: Would it be faster to take the train or walk? Walking takes 4 mins. What is the probability that Selena's train journey time to work is shorter than her walking time, given that her train journey time (Y) follows a uniform distribution from 2 to 5 minutes?

Solution:

  1. Identify Continuous vs Discrete. This situation involves time (measured), so continuous .

  2. Form the density curve: 5.0 - 2.0 = 3 → 3 × 1/3 = 1 (Probability adds to 1)

  3. Calculate Shaded Area: base × height = (4.0 - 2.0 ) × 1/3 = 2/3

  4. → P(Y < 4) = 2/3 = 0.667

  5. Sentence: There is a 66.7% chance that it will be quicker for Selena to take the train to work on a randomly selected day.

Question: The heights of young women can be modeled by a Normal distribution with mean µ = 64 inches and standard deviation σ = 2.7 inches. Suppose we choose a young woman at random and let Y = her height (in inches). Find P(68 ≤ Y ≤ 70). Interpret this value.

TODO: Insert Normal Curve Drawing

Answer: normalCdf(lower: 68, upper: 70, mean: 64, SD: 2.7) = 0.051


6.2 Transforming and Combining Random Variables

  • Adding the same positive number a to (subtracting a from) each value of a random variable:

    • Adds a to (subtracts a from) measures of center and location (mean, median, quartiles, percentiles).

      • Mean of Sum/Difference of Random Variables: μs = μx+-y = μx +- μY

    • Does not change measures of variability (range, IQR, standard deviation).

      • Variance adds (and subtracts), standard deviations do not add / subtract.

    • Does not change the shape of the probability distribution.

  • Multiplying (or dividing) each value of a random variable by the same positive number b:

    • Multiplies (divides) measures of center and location (mean, median, quartiles, percentiles) by b.

    • Multiplies (divides) measures of variability (range, IQR, standard deviation) by b.

    • Does not change the shape of the distribution.

  • Linear Transformation: If Y = a+ bX is a linear transformation of the random variable X,

    • The distribution of Y has same shape as the probability distribution of X if b > 0

    • μY = a+ bμX

    • σY = |b|σX (because b could be a negative number)

Adding / Subtracting Example Problem:

Question: Score X of a randomly selected student on a test worth 50 points can be modeled by a Normal distribution with mean 35 and standard deviation 5. Professor decides to add 5 points to
each student’s score. Let Y be the scaled test score of the randomly selected student. Describe the shape, center, and variability of the probability distribution of Y.

Answer:

  • Shape: Approximately Normal

  • Center: µY = µX + 5 = 35 + 5 = 40

  • Variability: σY = σX = 5

Multiplying / Dividing Example Problem:

Question: Student is full-time if taking 12 and 18 units. The number of units X that a randomly selected El Dorado Community College full-time student is taking (see histogram). Mean is µX = 14.65 and the standard deviation is σX = 2.056. Tuition is $50 per unit. If T = tuition charge for a
randomly selected full-time student, T = 50X.

Answer:

  • Shape: Same shape as the probability distribution of X, roughly symmetric with three peaks.

  • Center: µT = 50µX = 50(14.65) = $732.50

  • Variability: σT = 50σX = 50(2.056) = $102.80

Linear Transformation Example Problem:

Question: Let X = the number of passengers on a randomly selected trip at Pete’s Jeep Tours. Let Y = the number of passengers on a randomly selected trip at Erin’s Adventures. What is the sum S = X + Y of the number of passengers Pete and Erin will have on their tours on a randomly selected day?

Answer:

6.3 Binomial and Geometric:

Binomial Random Variables

  • Binomial Setting is when n independent trials are committed with a sauce chance of an outcome (aka success) occurs. Test using BINS

    • Binary? Possible outcomes should be “success” or “failure”

    • Independent? Trials must be independent. Knowing the outcome of one trial can’t determine another trial.

    • Number? The number of trials must be fixed in advance

    • Same Probability? Probability must be of success p on each trial.

  • Binomial Random Variable is the count of successes X in a binomial setting (literally a discrete variable)

  • Binomial Distribution is the probability distribution of X.

    • n trials and probability p of success on each trial.

  • Binomial Coefficient arranges k successes with n trials.

    • (n/k) = (n! / ( k! * (n-k)! ))

  • Binomial Probability Formula uses the Binomial Coefficient

    • Actual formula on equation sheet - P(X = x) = (n / x)…

    • binompdf (n,p,k) computes P(X = k)

    • binomcdf (n,p,k) computes P(X k)

  • Steps to find Binomial Probabilities:

    • State the distribution and the values of interest. Specify a binomial distribution with the number of trials n, success probability p, and the values of the variable clearly identified.

    • Perform the calculations, show calculator steps (or formula)

    • Be sure to answer the question

  • Center & Variability (Only for Binomial Distributions):

    • Mean - μx = E(X) = np

    • SD: σX = root( np * (1 - p) )

  • 10% Rule: A distribution will be approximately binomial when the sample size n is less than 10% of the population (Overrides BINS)

    • # of trials < 0.10 * population

    • Ex: A starburst bag comes with 200 candies. 25% chance one candy is red. This is not independent, and fails BINS. But since there are more than 200 starbursts in the world, the 10% rule applies. This distribution is approximately binomial.

  • Large Counts Condition: probability distribution of X is approximately normal if:

    • np ≧ 10 AND n( 1-p ) ≧ 10

    • AKA: Expected Numbers (mean) of successes and failures is at least 10

Geometric Random Variables

  • Geometric setting exists when the number of trials is unknown. Independent trials are performed until one success is made. Must be independent and p of success must be same.

  • Geometric Random Variable is the number of trials Y it takes to get a success

  • Geometric Probability Formula with Y geometric distribution, p probability of success, k is a specific term/trial

    • Actual formula on equation sheet - P(X = x) = ( 1 - p)…

    • geometpdf (p,k) computes P(X = k)

    • geometcdf (p,k) computes P(X k)

  • Shape: Every Geometric Distribution is skewed right (no exceptions)

  • Center: μx = E(X) = 1/p

  • SD: σX = root( 1 - p) / p

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