Chemistry: Solutions and Solubility

Vitamin Solubility

  • Vitamin C

    • Has four hydroxyl (OH) groups.

    • These OH groups make the molecule highly polar.

    • Vitamin C can also engage in hydrogen bonding with water.

    • Conclusion: Vitamin C is water-soluble.

    • Key Reasoning Factors:

      • Water acts as a polar solvent, which solubilizes polar substances.
      • As fats consist primarily of nonpolar molecules, they are not effective at dissolving polar molecules like Vitamin C.
  • Vitamin K3

    • Contains two carbonyl (C=O) groups that are polar; however, the geometric symmetry of the molecule leads to cancellation of the dipole moments.

    • Conclusion: Vitamin K3 is fat-soluble.

    • Key Reasoning Factors:

      • Again, the molecular characteristics imply that fat is largely comprised of nonpolar molecules, which can dissolve other nonpolar substances more effectively than polar ones like water.

Solubility Checklist

  • Evaluating Solubility:
    • Identify polar/ionic regions versus nonpolar regions within a molecule.
    • Look for hydrogen-bond donors and acceptors within the molecular structure.
    • Evaluate the symmetry of the molecule to understand cancellation of dipoles.
    • Apply the principle of “like dissolves like”.
    • Decide the solubility status:
    • Water-soluble?
    • Fat-soluble?
    • Both?

The Clausius-Clapeyron Equation

  • Purpose:

    • Provides a relationship for estimating vapor pressure at different temperatures based on the known vapor pressure at a specific temperature and the enthalpy of vaporization.
  • Definition:

    • The equation is often not applicable when discussing normal boiling points, as at the normal boiling point, the vapor pressure is defined to be 1 atm (or 760 mmHg).

Learning Objectives (Chapter 11a)

  1. Describe the basic properties of solutions and how they form.
  2. Predict the formation of a solution based on the molecular properties of its components.
  3. Calculate the concentration of a solution using:
    • Molarity
    • Molality
    • Mole Fraction
    • Percent by mass
  4. Discuss the effects of temperature and pressure on the solubility of different substances.

Examples of Solutions

  • Air:

    • Solute: Gas (oxygen, argon, etc.)
    • Solvent: Gas (nitrogen)
    • Description: Mixture of gases in nitrogen.
  • Humidity:

    • Solute: Liquid (water vapor)
    • Solvent: Gas (air)
    • Description: Water vapor dispersed in air.
  • Camphor in Air:

    • Solute: Solid (camphor)
    • Solvent: Gas (air)
    • Description: Sublimation of solid camphor into the atmosphere.
  • Soda Water:

    • Solute: Gas (carbon dioxide)
    • Solvent: Liquid (water)
    • Description: CO2 gas dissolved in water under pressure.
  • Vinegar:

    • Solute: Liquid (acetic acid)
    • Solvent: Liquid (water)
    • Description: Acetic acid dissolved in water.
  • Saltwater:

    • Solute: Solid (sodium chloride)
    • Solvent: Liquid (water)
    • Description: NaCl crystals dissolved in water.

Solution Concentration

Molarity (M)

  • Definition: Moles of solute per liter of solution.
  • Importance:
    • Describes the number of molecules of solute in one liter of solution.
  • Example:
    • If the concentration of a sugar solution is 2.0 M, then:
      • 1 liter contains 2.0 moles of sugar.
      • 2 liters contain 4.0 moles of sugar.
      • 0.5 liters contain 1.0 mole of sugar.

Molality (m)

  • Definition: Moles of solute per kilogram of solvent.
  • Characteristics:
    • Defined based on the amount of solvent rather than the total solution.
    • Does not change with temperature due to being based on mass, not volume.

Concentration Units

  1. Percent by Mass:
    • Formula: ext{% by mass} = \frac{\text{mass of solute}}{\text{mass of solute} + \text{mass of solvent}} \times 100\%
  2. Mole Fraction (X):
    • Formula:
    • X_A = \frac{\text{moles of A}}{\text{sum of moles of all components}}

Practice Problems

Molarity Example Problem:

  • Calculate the molarity of a solution made by dissolving 34.0 g of NH3 in 2000 mL of solution (MM_NH3 = 17.04 g/mol).

Detailed Problems Steps:

  • Check Units:
    • M = mol/L
    • 1 mol NH3 = 17.04 g
    • 1 mL = 0.001 L
  • Conceptual Plan: Relationships:
    • Given: 34.0 g NH3, 2000 mL solution
    • Find: M, given g NH3 to mol NH3 to mL solution to L solution

Molality Example Problem:

  • Calculate the molality of a solution prepared by mixing 17.2 g of C2H6O2 with 0.500 kg of H2O (MM_C2H6O2 = 62.07 g/mol) to make 515 mL of solution.

Practice with NH3:

  • Calculate the molality of a solution made by dissolving 34.0 g of NH3 in 2000 mL of water, given the density of water is 1.00 g/mL.

More Terms

  • Unsaturated:

    • Description: More solute can dissolve; concentration is less than the solubility limit.
  • Saturated:

    • Description: Contains the maximum concentration possible for a given temperature and pressure.
  • Supersaturated:

    • Description: Concentration exceeds solubility, representing a nonequilibrium state where crystals may grow.

Temperature Dependence of Solubility of Solids in Water

  • General Observations:

    • Solubility is provided in grams of solute that dissolve in 100 g of water.
    • For most solid solutes, solubility increases as temperature rises when the dissolution process (\Delta H_{solution}) is endothermic.
  • Solubility Curves:

  • Used to predict the classification of a solution based on solute concentration:

    • Saturated: On the line.
    • Unsaturated: Below the line.
    • Supersaturated: Above the line.

Solubility Curves Details

  • Graph Depiction:
    • A graph displaying temperature (°C) on the X-axis against solubility (g solute in 100 g H2O) on the Y-axis.

Solubility of Gases in Water at Various Temperatures

  • Observation:
    • The solubility of gases in water tends to decrease with increasing temperature.

Solubility of Gases in Water at Various Pressures (temp = 20°C)

  • Observation:
    • Higher pressures generally increase the solubility of gases in liquids (such as CO2 in carbonated drinks).

Conclusive Remarks

  • Learning Objectives Summary:
    • Understanding the properties of solutions, predicting outcomes based on molecular interactions, and calculating concentrations are essential for grasping the behavior of solutions in chemistry.
  • The effects of temperature and pressure on solubility are vital for various applications in practical scenarios such as solution preparation and gas solubility in liquids.