Chemistry: Solutions and Solubility
Vitamin Solubility
Vitamin C
Has four hydroxyl (OH) groups.
These OH groups make the molecule highly polar.
Vitamin C can also engage in hydrogen bonding with water.
Conclusion: Vitamin C is water-soluble.
Key Reasoning Factors:
- Water acts as a polar solvent, which solubilizes polar substances.
- As fats consist primarily of nonpolar molecules, they are not effective at dissolving polar molecules like Vitamin C.
Vitamin K3
Contains two carbonyl (C=O) groups that are polar; however, the geometric symmetry of the molecule leads to cancellation of the dipole moments.
Conclusion: Vitamin K3 is fat-soluble.
Key Reasoning Factors:
- Again, the molecular characteristics imply that fat is largely comprised of nonpolar molecules, which can dissolve other nonpolar substances more effectively than polar ones like water.
Solubility Checklist
- Evaluating Solubility:
- Identify polar/ionic regions versus nonpolar regions within a molecule.
- Look for hydrogen-bond donors and acceptors within the molecular structure.
- Evaluate the symmetry of the molecule to understand cancellation of dipoles.
- Apply the principle of “like dissolves like”.
- Decide the solubility status:
- Water-soluble?
- Fat-soluble?
- Both?
The Clausius-Clapeyron Equation
Purpose:
- Provides a relationship for estimating vapor pressure at different temperatures based on the known vapor pressure at a specific temperature and the enthalpy of vaporization.
Definition:
- The equation is often not applicable when discussing normal boiling points, as at the normal boiling point, the vapor pressure is defined to be 1 atm (or 760 mmHg).
Learning Objectives (Chapter 11a)
- Describe the basic properties of solutions and how they form.
- Predict the formation of a solution based on the molecular properties of its components.
- Calculate the concentration of a solution using:
- Molarity
- Molality
- Mole Fraction
- Percent by mass
- Discuss the effects of temperature and pressure on the solubility of different substances.
Examples of Solutions
Air:
- Solute: Gas (oxygen, argon, etc.)
- Solvent: Gas (nitrogen)
- Description: Mixture of gases in nitrogen.
Humidity:
- Solute: Liquid (water vapor)
- Solvent: Gas (air)
- Description: Water vapor dispersed in air.
Camphor in Air:
- Solute: Solid (camphor)
- Solvent: Gas (air)
- Description: Sublimation of solid camphor into the atmosphere.
Soda Water:
- Solute: Gas (carbon dioxide)
- Solvent: Liquid (water)
- Description: CO2 gas dissolved in water under pressure.
Vinegar:
- Solute: Liquid (acetic acid)
- Solvent: Liquid (water)
- Description: Acetic acid dissolved in water.
Saltwater:
- Solute: Solid (sodium chloride)
- Solvent: Liquid (water)
- Description: NaCl crystals dissolved in water.
Solution Concentration
Molarity (M)
- Definition: Moles of solute per liter of solution.
- Importance:
- Describes the number of molecules of solute in one liter of solution.
- Example:
- If the concentration of a sugar solution is 2.0 M, then:
- 1 liter contains 2.0 moles of sugar.
- 2 liters contain 4.0 moles of sugar.
- 0.5 liters contain 1.0 mole of sugar.
- If the concentration of a sugar solution is 2.0 M, then:
Molality (m)
- Definition: Moles of solute per kilogram of solvent.
- Characteristics:
- Defined based on the amount of solvent rather than the total solution.
- Does not change with temperature due to being based on mass, not volume.
Concentration Units
- Percent by Mass:
- Formula: ext{% by mass} = \frac{\text{mass of solute}}{\text{mass of solute} + \text{mass of solvent}} \times 100\%
- Mole Fraction (X):
- Formula:
- X_A = \frac{\text{moles of A}}{\text{sum of moles of all components}}
Practice Problems
Molarity Example Problem:
- Calculate the molarity of a solution made by dissolving 34.0 g of NH3 in 2000 mL of solution (MM_NH3 = 17.04 g/mol).
Detailed Problems Steps:
- Check Units:
- M = mol/L
- 1 mol NH3 = 17.04 g
- 1 mL = 0.001 L
- Conceptual Plan: Relationships:
- Given: 34.0 g NH3, 2000 mL solution
- Find: M, given g NH3 to mol NH3 to mL solution to L solution
Molality Example Problem:
- Calculate the molality of a solution prepared by mixing 17.2 g of C2H6O2 with 0.500 kg of H2O (MM_C2H6O2 = 62.07 g/mol) to make 515 mL of solution.
Practice with NH3:
- Calculate the molality of a solution made by dissolving 34.0 g of NH3 in 2000 mL of water, given the density of water is 1.00 g/mL.
More Terms
Unsaturated:
- Description: More solute can dissolve; concentration is less than the solubility limit.
Saturated:
- Description: Contains the maximum concentration possible for a given temperature and pressure.
Supersaturated:
- Description: Concentration exceeds solubility, representing a nonequilibrium state where crystals may grow.
Temperature Dependence of Solubility of Solids in Water
General Observations:
- Solubility is provided in grams of solute that dissolve in 100 g of water.
- For most solid solutes, solubility increases as temperature rises when the dissolution process (\Delta H_{solution}) is endothermic.
Solubility Curves:
Used to predict the classification of a solution based on solute concentration:
- Saturated: On the line.
- Unsaturated: Below the line.
- Supersaturated: Above the line.
Solubility Curves Details
- Graph Depiction:
- A graph displaying temperature (°C) on the X-axis against solubility (g solute in 100 g H2O) on the Y-axis.
Solubility of Gases in Water at Various Temperatures
- Observation:
- The solubility of gases in water tends to decrease with increasing temperature.
Solubility of Gases in Water at Various Pressures (temp = 20°C)
- Observation:
- Higher pressures generally increase the solubility of gases in liquids (such as CO2 in carbonated drinks).
Conclusive Remarks
- Learning Objectives Summary:
- Understanding the properties of solutions, predicting outcomes based on molecular interactions, and calculating concentrations are essential for grasping the behavior of solutions in chemistry.
- The effects of temperature and pressure on solubility are vital for various applications in practical scenarios such as solution preparation and gas solubility in liquids.