(4) Algebra: Linear equations 1 | Linear equations | Algebra I | Khan Academy

Introduction to Linear Equations

  • Understanding basic linear equations and their solution methods.

Problem 1: 5x = 20

  • The equation can be rephrased as: 5 times question mark = 20.

  • This implies 5 multiplied by the variable x equals 20.

Systematic Solution Methods

  • Commonly, one can deduce that 5 times 4 = 20 without much thought.

  • However, to solve systematically:

    • Divide both sides by 5:

      • Left-hand side: 5x / 5 = x

      • Right-hand side: 20 / 5 = 4

      • Result: x = 4

    • Alternatively, multiply by the reciprocal (1/5):

      • This gives: x = 20 × 1/5, yielding x = 4.

Problem 2: -3/4 x = 10/13

  • A more complex problem where we solve for x algebraically.

Steps to Solve

  1. Identify the Coefficient:

    • The coefficient of x is -3/4.

  2. Multiply by the Reciprocal:

    • The reciprocal of -3/4 is -4/3.

    • Multiply both sides by -4/3:

      • Left-hand side:

        • (-4/3) × (-3/4) = 1, leaving x.

      • Right-hand side:

        • (10/13) × (-4/3) = -40/39.

  3. Result:

    • x = -40/39.

    • Alternate form: x = -1 and 1/39 (mixed number).

Verification of Solution

  • Substitute back into the equation: (-3/4) × (-40/39) should equal 10/13.

    • Adjusting fractions gives:

      • -3 �d7 -40 = 120.

      • Followed by adjustments: 120 / 156 becomes 30/39 = 10/13 after simplification.

Problem 3: -5/6 x = 7/8

  • Let's apply similar steps:

Steps to Solve

  1. Identify the Coefficient:

    • The coefficient is -5/6.

  2. Multiply by the Reciprocal:

    • The reciprocal of -5/6 is -6/5.

    • Multiply both sides by -6/5:

      • Left-hand side:

        • (-6/5) × (-5/6) = 1, resulting in x.

      • Right-hand side:

        • (7/8) × (-6/5) = -42/40.

  3. Result:

    • Simplifying gives x = -21/20.

Verification of Solution

  • Substitute back into the equation to ensure the correctness:

    • Calculation proceeds as: (-5/6) × (-21/20) results in 7/8 after correct adjustments.

Conclusion

  • Effective methods to solve linear equations using division or multiplication by reciprocals.

  • Encourage practice with various linear equations for mastery.

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