Work Calculation: [ W = F \cdot d ]
Units: N × m ≡ J (Joule)
Example: Pushing a cart with F = 100 N over 5.00 m results in work done.
James Joule's Contribution:
Proved that the same amount of work results in the same amount of heat.
Only the component of force in the direction of displacement contributes to work done.
If there is no displacement, no work is done.
Units for g:A. mB. NC. m/sD. m/s²E. kg/m/s
Units for Weight:A. mB. NC. m/sD. m/s²E. kg/m/s
Newton Definition:A. m/sB. m/s²C. kgD. kg/m/sE. kg/m/s²
A box weighing 2.0 N lifted 1.0 m requires:
Work: [ W = F \cdot d = 2.0 ext{N} \cdot 1.0 ext{m} = 2.0 J ] - Correct option: C.
Pushing a box with a weight of 2.0 N sideways on a frictionless surface also results in work:
Needed energy (work) is 0.0 J since displacement is not vertical.
If friction of F = 20.0 N acts against a cart that performs 100 J of work:
Distance it could pull = 100 J / 20.0 N = 5.00 m (Correct option: D)
For a 210 N weight held at 1.0 m, the work done is 0 J since there is no displacement.
Comparative Work Example:
A. 400 N to drag a 75 kg log 5.0 m on dirt
B. 400 N to pull a 1200 kg cart on concrete
Compare: Both scenarios require the same amount of work, if friction is negligible.
General Form: [ W \equiv F \cdot d \cdot \cos(\theta) ]
Where ( \theta ) is the angle between force and displacement.
Special Cases: ( \cos(0º) = 1 ) means complete work is done when force is in the same direction as displacement.
Power is the rate of work or energy use: [ P \equiv \frac{W}{t} ] or [ P \equiv \frac{E}{t} ]
Power Units:
[ P = \frac{W}{t} = \text{Joules}/ ext{second} = Watts ]
1 hp = 746 W
Power and energy are distinct:
Power = Rate of energy use
Energy Units: Joules (J)
Power Units: Watts (W) = J/s
Mechanical Energy Types:
Linear kinetic energy, gravitational potential energy, spring potential energy, rotational kinetic energy
Not thermal energy or chemical potential energy
Newton's Third Law of Motion applies:
[ Work_{action} = - Work_{reaction} ]
Energy types can change forms but cannot be created or destroyed.
If no friction, kinetic energy formula: [ E_k = \frac{1}{2} mv^2 ]
Kinetic energy is influenced by mass and velocity:
If you double velocity, kinetic energy quadruples.
A 1.0 kg mass at 1.0 m/s: Calculate its kinetic energy.
A watermelon with 4500 J of kinetic energy, find its speed.
Energy conversion can reveal mass: if 1000 J of heat is released from sliding to stop, find mass if it started at 65 m/s.
Gravitational force work equation: [ W = F imes d ]
Potential energy equation: [ E_p = mgh ]
When measuring height, reference point matters.
Determine potential energy of a 1.0 kg object at 1.0 m.
Analyze a dropped bowling ball or sliding gourd to compare initial motion and final velocity using energy principles.
Energy maintains constant in certain conditions throughout height shift and free-fall scenarios.