Event space vs. sample space
Sample space S: all possible outcomes of six coin flips
Event space E: subset of S we care about (e.g., X = number of heads)
For fair coins, each outcome has equal probability
In six flips, |S| = 2^6 = 64, total outcomes
Counting outcomes for six flips
Fundamental counting principle: each flip has 2 outcomes; over 6 flips: |S| = 2^6 = 64
Number of ways to get exactly k heads: inom{6}{k}
Examples: inom{6}{3} = 20, inom{6}{0} = 1, inom{6}{1} = 6
Therefore, exactly 3 heads: 20 outcomes; not exactly 3 heads: 64 − 20 = 44 outcomes
Exact vs not exactly three heads
P(X = 3) = rac{20}{64} = 0.3125
P(X ≠ 3) = 1 − P(X = 3) = rac{44}{64} = 0.6875
Complements: P(E) + P(E^c) = 1; P(E^c) = 1 − P(E)
Probability notation and definitions
P(E): probability that event E occurs
E can be {X = 3} or {X ≠ 3}; X is a random variable, here "number of heads"
If you write P(X = 3), that is the probability that the random variable X equals 3
Keep fractions unsimplified when that preserves information (e.g., 20/64 instead of 5/16)
Probabilities lie in the interval 0 \le P(E) \le 1
Impossible event: P(E) = 0; Certain event: P(E) = 1
Random variable and common examples
Let X = ext{number of heads in 6 flips}
Then the event space examples: ext{E}1 = {X = 3}, ext{E}2 = {X \neq 3}
The sample space is the same across events: all 64 outcomes
Quick observations and intuition
Distribution of heads in 6 flips is symmetric around 3; the most likely exact count is 3 heads
The phrasing of probability questions matters (exact vs not, complementary events, etc.)
For binomial-type problems with a fair coin, the distribution is binomial with parameters n = 6, p = \tfrac{1}{2}
Quick course logistics (open-note quiz context)
Quiz is described as open-note and open-neighbor; you can consult with others
Access via the Mathematize portal; may require creating an account
Cost to access platform mentioned; plan accordingly if needed
Deadline noted for the initial quiz window (check current syllabus for updates)
Key formulas to remember
Number of outcomes: |S| = 2^n for n coin flips
Exactly k heads: ext{ways} = inom{n}{k}
Probability of exactly k heads: P(X = k) = rac{inom{n}{k}}{2^n} for a fair coin
Complement rule: P(E^c) = 1 - P(E) and P(E) + P(E^c) = 1
Exact vs not exactly three heads
P(X = 3) = \frac{20}{64} = 0.3125
P(X \neq 3) = 1 \text{
} P(X = 3) = \frac{44}{64} = 0.6875
Complements: P(E) + P(E^c) = 1
P(E^c) = 1 \text{
} P(E)
Probability notation and definitions
P(E): probability that event E occurs
E can be {X = 3} or {X \neq 3}; X is a random variable, here "number of heads"
If you write P(X = 3), that is the probability that the random variable X equals 3
Keep fractions unsimplified (\text{e.g., } \frac{20}{64} \text{ instead of } \frac{5}{16})
Probabilities lie in the interval 0 \le P(E) \le 1
Impossible event: P(E) = 0; Certain event: P(E) = 1
Random variable and common examples
Let X = \text{number of heads in 6 flips}
Then the event space examples: \text{E}1 = {X = 3}, \text{E}2 = {X \neq 3}
The sample space is the same across events: all 64 outcomes
Quick observations and intuition
Distribution of heads in 6 flips is symmetric around 3; the most likely exact count is 3 heads
The phrasing of probability questions matters (exact vs not, complementary events, etc.)
For binomial-type problems with a fair coin, the distribution is binomial with parameters n = 6, p = \frac{1}{2}
Quick course logistics (open-note quiz context)
Quiz is described as open-note and open-neighbor; you can consult with others
Access via the Mathematize portal; may require creating an account
Cost to access platform mentioned; plan accordingly if needed
Deadline noted for the initial quiz window (check current syllabus for updates)
Key formulas to remember
Number of outcomes: \left|S\right| = 2^n for n coin flips
Exactly k heads: \text{ways} = \binom{n}{k}
Probability of exactly k heads: P(X = k) = \frac{\binom{n}{k}}{2^n} for a fair coin
Complement rule: P(E^c) = 1 \text{
} P(E) and P(E) + P(E^c) = 1