Redox Chemistry
Some redox reactions involve the transfer of electrons between reactant species to yield ionic products
It is helpful to split the overall reaction into individual equations called half-reactions.
In the balanced equation, electrons lost must = electrons gained.
Oxidation: loss of electrons
Reduction: gain of electrons
Reducing agent: is oxidized; LOSES electrons, and its charge goes up.
Oxidizing agent: is reduced; gains electrons, and its charge goes DOWN.
Oxidation number (or oxidation state) of an element in a compound: the charge its atoms would possess if the compound was ionic.
The oxidation number of an atom in an elemental substance is zero.
The oxidation number of a monatomic ion is equal to the ion’s charge. ( Group 1 metals are always +1, group 2 always +2)
Oxidation numbers for common nonmetals are usually assigned as follows:
Hydrogen:
+1 when combined with nonmetals
−1 when combined with metals
Oxygen:
−2 in most compounds
Sometimes −1 (so-called peroxides, O22−)
Very rarely − ½ (so-called superoxides, O2−)
Positive values when combined with F (values vary)
Halogens:
−1 for F always
−1 for other halogens except when combined with oxygen or other halogens (positive oxidation numbers in these cases, varying values)
The sum of the oxidation numbers for all atoms in a molecule must be zero.
The sum of the oxidation number in a polyatomic ion equals the charge on the ion.
The oxidation number of an element in a polyatomic ion is always the same, whether that ion is in a compound or not
Single-displacement (replacement) reactions: redox reactions in which an ion in solution is displaced (or replaced) via the oxidation of a metallic element.
Write the two individual half-reactions: the oxidation and the reduction.
Balance all elements except oxygen and hydrogen. (most often forgotten, leading to tragic results! )
Balance oxygen atoms by adding H2O molecules.
Balance hydrogen atoms by adding H+ ions.
Balance charge by adding electrons.
If necessary, multiply each half-reaction’s coefficients by the smallest possible integers to yield equal numbers of electrons in each.
Add the balanced half-reactions together and simplify by removing species that appear on both sides of the equation
For reactions occurring in basic media (excess hydroxide ions), carry out these additional steps:
Add OH− ions to both sides of the equation in numbers equal to the number of H+ ions.
On the side of the equation containing both H+ and OH− ions, combine these ions to yield water molecules.
Simplify the equation by removing any redundant water molecules.
Finally, check to see that the number of atoms and the total charge are balanced.
Some redox reactions involve the transfer of electrons between reactant species to yield ionic products
It is helpful to split the overall reaction into individual equations called half-reactions.
In the balanced equation, electrons lost must = electrons gained.
Oxidation: loss of electrons
Reduction: gain of electrons
Reducing agent: is oxidized; LOSES electrons, and its charge goes up.
Oxidizing agent: is reduced; gains electrons, and its charge goes DOWN.
Oxidation number (or oxidation state) of an element in a compound: the charge its atoms would possess if the compound was ionic.
The oxidation number of an atom in an elemental substance is zero.
The oxidation number of a monatomic ion is equal to the ion’s charge. ( Group 1 metals are always +1, group 2 always +2)
Oxidation numbers for common nonmetals are usually assigned as follows:
Hydrogen:
+1 when combined with nonmetals
−1 when combined with metals
Oxygen:
−2 in most compounds
Sometimes −1 (so-called peroxides, O22−)
Very rarely − ½ (so-called superoxides, O2−)
Positive values when combined with F (values vary)
Halogens:
−1 for F always
−1 for other halogens except when combined with oxygen or other halogens (positive oxidation numbers in these cases, varying values)
The sum of the oxidation numbers for all atoms in a molecule must be zero.
The sum of the oxidation number in a polyatomic ion equals the charge on the ion.
The oxidation number of an element in a polyatomic ion is always the same, whether that ion is in a compound or not
Single-displacement (replacement) reactions: redox reactions in which an ion in solution is displaced (or replaced) via the oxidation of a metallic element.
Write the two individual half-reactions: the oxidation and the reduction.
Balance all elements except oxygen and hydrogen. (most often forgotten, leading to tragic results! )
Balance oxygen atoms by adding H2O molecules.
Balance hydrogen atoms by adding H+ ions.
Balance charge by adding electrons.
If necessary, multiply each half-reaction’s coefficients by the smallest possible integers to yield equal numbers of electrons in each.
Add the balanced half-reactions together and simplify by removing species that appear on both sides of the equation
For reactions occurring in basic media (excess hydroxide ions), carry out these additional steps:
Add OH− ions to both sides of the equation in numbers equal to the number of H+ ions.
On the side of the equation containing both H+ and OH− ions, combine these ions to yield water molecules.
Simplify the equation by removing any redundant water molecules.
Finally, check to see that the number of atoms and the total charge are balanced.