The amount of gasoline sold daily at a service station is uniformly distributed between 2,000 and 5,000 gallons.
Find the following probabilities:
a. Probability that daily sales fall between 2,500 and 3,000 gallons.
b. Probability that the service station sells at least 4,000 gallons.
c. Probability that the station sells exactly 2,500 gallons.
The probability density function is: f(x) = \frac{1}{5,000 - 2,000} = \frac{1}{3,000} when 2,000 \le x \le 5,000
a. P(2,500 \le x \le 3,000) = (3,000 - 2,500) * \frac{1}{3,000} = .1667
b. P(x \ge 4,000) = (5,000 - 4,000) * \frac{1}{3,000} = .3333
c. P(x = 2,500) = 0
Given density function:
f(x) = .40 \text{ for } 0 < x < 1
f(x) = .05 \text{ for } 1 < x < 13
a. Graph the density function.
b. Determine the probability that X is less than 8.
c. What is the probability that X lies between .4 and 10? (Homework)
General formulas:
For discrete random variables:
\mu = E[X] = \sum_{\text{all } x} x \cdot p(x)
\sigma^2 = E[(X - \mu)^2] = \sum_{\text{all } x} (x - \mu)^2 \cdot p(x)
For continuous variables:
\mu = E[X] = \int_{-\infty}^{\infty} x \cdot f(x) dx
\sigma^2 = E[(X - \mu)^2] = \int_{-\infty}^{\infty} (x - \mu)^2 \cdot f(x) dx
where f(x) is the probability density function (also denoted as p(x)).
Alternate formula for variance:
\sigma^2 = E[X^2] - \mu^2 = \int_{-\infty}^{\infty} x^2 \cdot f(x) dx - \mu^2
Uniform distribution:
If X \sim \text{Uniform}(a, b), then f(x) = \frac{1}{b-a} for a \le x \le b
\int{-\infty}^{\infty} x \frac{1}{b-a} dx = \frac{1}{b-a} \frac{x^2}{2} \Big|a^b = \frac{1}{b-a} \left( \frac{b^2}{2} - \frac{a^2}{2} \right) = \frac{b+a}{2}
Therefore, \mu = \frac{b+a}{2}
\int{-\infty}^{\infty} x^2 \frac{1}{b-a} dx - \mu^2 = \frac{1}{b-a} \frac{x^3}{3} \Big|a^b - \mu^2 = \frac{1}{b-a} \left( \frac{b^3}{3} - \frac{a^3}{3} \right) - \left( \frac{b+a}{2} \right)^2
= \frac{b-a}{1} \cdot \frac{a^2 + ab + b^2}{3} \cdot \frac{1}{b-a} - \frac{(b+a)^2}{4} = \frac{4(a^2 + ab + b^2) - 3(b^2 + 2ab + a^2)}{12} = \frac{a^2 + b^2 - 2ab}{12} = \frac{(b-a)^2}{12}
The mean (expected value) of x is E(x) = \frac{a + b}{2}.
The variance of x is Var(x) = \frac{(b – a)^2}{12}.
where:
a = smallest value the variable can assume
b = largest value the variable can assume
Max: 5000 gallons
Min: 2000 gallons
The expected value (or mean) of X is
E(X) = \frac{(a + b)}{2} = \frac{(2000 + 5000)}{2} = 3500
The variance of x is
Var(X) = \frac{(b – a)^2}{12} = \frac{(5000 – 2000)^2}{12} = 750000
Most common and useful continuous distribution
Used in a wide variety of applications including:
Heights of people
Amounts of rainfall
Standardized Test scores
Scientific measurements
Widely used in statistical inference.
Sometimes called “Gaussian”
f(x) = \frac{1}{\sqrt{2 \pi \sigma^2}} e^{-\frac{(x-\mu)^2}{2\sigma^2}}
where
\mu = \text{mean}
\sigma = \text{standard deviation}
\pi = 3.14159 \dots
e = 2.71828 \dots
- \infty < x < +\infty
The tails of the normal curve extend to infinity in both directions and theoretically never touch the horizontal axis.
X \sim N(\mu, \sigma^2)
means random variable X is distributed normally with mean \mu and variance \sigma^2 (or X is distributed normally with mean µ and standard deviation σ ).
Random Variable X follows a Normal distribution with mean \mu and standard deviation \sigma
A normal distribution is completely defined by two parameters: Its mean and its variance/standard deviation.
The highest point on the normal curve is at the mean, which is also the median and the mode.
Normal distributions with the same standard deviation and different means: \mu1 and \mu2
FIGURE 6.4 Normal Distributions with Same Standard Deviation and Different Means
Normal distributions with the same mean and different standard deviations: \mu
FIGURE 6.5 Normal Distributions with Same Mean and Different Standard Deviations
\sigma = 5
\sigma = 10
Probabilities for the normal random variable are given by areas under the curve.
The total area under the curve is 1.
Because the distribution is symmetric, the area under the curve to the left of the mean is 0.50 and the area to the right of the mean is 0.5.
A random variable having a normal distribution with a mean µ = 0 and standard deviation σ = 1 (or variance σ^2 = 1) is said to have a standard normal probability distribution.
The letter Z is conventionally used to designate the standard normal random variable.
Z follows a standard normal distribution if Z \sim N(0,1).
Random Variable Z follows a Standard Normal distribution (mean = 0 and standard deviation = 1).
\sigma = 1
\pi and e are constants
To find the probability that a normal random variable is within any specific interval, we must compute the area under the normal curve over the interval.
Probabilities will be based on a table.
f(z) = \frac{1}{\sqrt{2\pi}} e^{-\frac{1}{2}z^2}