Confidence Level and Confidence Interval
For a variable with a known distribution, we define the confidence level and confidence interval.
Given a random variable X with a known cumulative distribution function (CDF) F(x) and parameter \alpha where 0 \leq \alpha \leq 1.
We want to find an interval [a, b] where the probability of X falling within this interval is 1 - \alpha, expressed as:
P(a \leq X \leq b) = 1 - \alpha.
This interval is called the confidence interval corresponding to the confidence level A, where A = 100(1 - \alpha)\%.
Typically, small \alpha values (e.g., \alpha \approx 0.01) and high A values (e.g., A \approx 100\%) are sought, implying most values of X can be found in the interval.
Solving Confidence Interval Initial Setup
The solution of the probability equation P(a \leq X \leq b) = 1 - \alpha is non-unique without knowing how to distribute remaining probabilities.
For bounds P(a \leq X \leq b) = F(b) - F(a), we consider intervals [a, b] and [c, d] corresponding to the same confidence level.
Finding Boundaries of Confidence Interval
To compute confidence interval boundaries, solve equations:
P(a \leq X) = F(a) = P, \quad P(b \geq X) = F(b) = P.
To find a unique solution, symmetry can be introduced with P(a) = \frac{\alpha}{2} and P(b) = 1 - \frac{\alpha}{2}, valid mainly for symmetric distributions like the normal distribution.
For non-symmetrical distributions, choosing P(a) and P(b) is less straightforward.
Cumulative Distribution Function Requirement
Effective interval estimation relies on knowing the cumulative distribution function (CDF), marking it as distinct from point estimation, which is not dependent on the distribution's form.
An example using a normal variable, where we possess a known mean \mu and standard deviation \sigma, entails finding a 100(1 - \alpha)\% symmetric confidence interval using standard normal distributions (solving for Z).
Using Standard Normal Variable
Introduce the standardized normal variable:
Z = \frac{X - \mu}{\sigma}.
The CDF of Z implies probabilities can be evaluated through the solutions of specified equations leveraging symmetry due to the properties of normal distributions.
Calculation Example
Example value: if \alpha = 0.05, then z_{\alpha/2} = 1.96 so the 95% confidence interval is given by \mu \pm 1.96\sigma.
Note that this example does not involve actual data sample values, as distribution parameters \mu and \sigma are assumed known for theoretical background.
Practical Impact of Unknown Parameters
In practice, \mu and \sigma are often unknown, complicating the calculation of confidence intervals, which necessitate approximation based on sample data.
Foundational Concepts
For large samples, where N o \infty, variables that are means \bar{X} converge towards normal distributions due to the Central Limit Theorem (CLT).
Mean Confidence Interval Calculation
Use properties of large samples to express the confidence interval for the mean \mu, as
P\left(\bar{X} - z{\alpha/2}\frac{s}{\sqrt{N}} \leq \mu \leq \bar{X} + z{\alpha/2}\frac{s}{\sqrt{N}} \right) = 1 - \alpha,
where s represents the sample standard deviation.
Desired Confidence Level and Sample Size Dynamics
A significant aspect is balancing between confidence level and required sample size; increasing confidence levels can rapidly inflate bounds across intervals.
Sample size determines width w of the interval
w = 2z_{\alpha/2}\frac{\sigma}{\sqrt{N}},
Thus, N must also be adjusted accordingly with respect to desired bounds on confidence level.
Interpretation of Confidence Intervals
A established confidence interval P(X \in [L, U]) = 1 - \alpha broadly signifies that with numerous repeats of the sampling method, average probability of capturing the true parameter \mu across intervals matches the defined confidence rate.
Problem Statement
This section considers finding confidence interval limits under situations where N is small, and the Central Limit Theorem is not functional.
Formula:
P \left( T \leq \mu \leq T \right),
with critical values derived from Student's t-distribution if the underlying data conforms to normality.
Understanding Student's T-distribution
T established as T = \frac{X - \mu}{S/\sqrt{N}} conforms to a t-distribution with N - 1 degrees of freedom, characterized by additional spread as opposed to standard deviations.
Finding Exact Confidence Intervals
Establish critical t-values through F(t_{\alpha/2, N-1}) = 1 - \alpha/2 leading to exact confidence intervals calculated critically aligned with sample estimates.
Sample Size Considerations
Maintain flexibility across sample value sizes; the approach remains exact for any sample size under the assumption of normality.
Computational Steps for Estimation
1. Compute critical t-value via CDF
2. Establish mean \bar{X}
3. Calculate sample standard deviation s
4. Establish final bounds for the confidence interval through critical formulations.
This section encapsulates theoretical background, pragmatics of interval estimation highlighting significant factors influencing confidence bounds across different data scenarios.