Objective: Understand the electrolysis process of aqueous copper sulfate and its application in copper refining.
Electrolyte: Aqueous copper sulfate solution containing:
Copper (II) ions (Cu²⁺)
Sulfate ions (SO₄²⁻)
Hydrogen ions (H⁺)
Hydroxide ions (OH⁻)
Electrodes: Using graphite electrodes which are inert and do not participate in the reaction.
Discharge Reactions:
Cu²⁺ ions and H⁺ ions are attracted to the cathode.
Priority of Discharge: Cu²⁺ is less reactive than H⁺, hence:
Cu²⁺ ions are reduced to copper metal (Cu) by gaining two electrons:
Reaction: Cu²⁺ + 2e⁻ → Cu (s)
Discharge Reactions:
SO₄²⁻ and OH⁻ ions are attracted to the anode.
Priority of Discharge: The sulfate does not discharge; therefore, OH⁻ discharges to produce water and oxygen:
Reaction: 4OH⁻ → 2H₂O + O₂ + 4e⁻
Electrolyte remains the same, but electrodes are now copper instead of graphite.
Cu²⁺ and H⁺ again are present:
Cu²⁺ ions are still reduced to copper metal (Cu), causing the cathode to increase in size as it gets coated with copper.
Oxidation processes include:
Cu can oxidize more readily than SO₄²⁻ or OH⁻:
Reaction: Cu (s) → Cu²⁺ + 2e⁻
As a result, copper metal from anode turns into Cu²⁺ ions, adding copper to the electrolysis solution.
Understanding the Process:
Anode: Copper ore (contains copper) undergoing oxidation.
Cathode: Thin strip of pure copper, facilitating purification.
Chemical Reactions:
At the cathode: Cu²⁺ ions reduce to form pure copper:
Reaction: Cu²⁺ + 2e⁻ → Cu (s)
At the anode: Copper from ore oxidizes to Cu²⁺ ions while remaining impurities (sand, etc.) settle at the bottom.
Outcome:
Constant increase in the size of the pure copper cathode as copper ions deposit, while the copper ore anode diminishes.
Resulting in pure copper metal collected at the cathode and impurities collected as sludge at the bottom.
This process of electrolysis allows for efficient purification of copper, transforming a rock containing copper into pure copper metal.