Concentration calculations require only one missing variable in a problem.
Types of concentration questions include:
What is the concentration when ...?
How many grams or moles are needed to...?
How many liters or kg of solvent are needed to...?
Different ways to express concentration:
Molarity (M):
Formula: M = mol solute / L solution
Mass Percent (%m/m & w/w):
Formula: %mass = (mass component / mass solution) × 100%
Volume Percent (%v/v):
Formula: %vol = (volume component / volume solution) × 100%
Mass/Volume Percent (%m/v or w/v):
Formula: m/v % = (mass component / volume solution) × 100%
Parts per million (ppm):
Formula: ppm = (mass solute / mass solution) × 10^6
Parts per billion (ppb):
Formula: ppb = (mass solute / mass solution) × 10^9
Mole Fraction (Χi):
Formula: Χ𝑖 = 𝑛𝑛𝑖𝑖 / 𝑛𝑛𝑡𝑡𝑡𝑡
Molality (m):
Formula: m = moles of solute / kg of solvent
Solutions can be represented in various ways, yielding the same concentration values across different units.
Example 1: Dissolving 0.790 mol KCl in 0.4975 kg of water:
Calculation: m = 0.790 mol / 0.4975 kg = 1.59 m
Example 2: Dissolving 0.790 mol KCl in 500.0 mL of water (density = 0.995 g/cm³):
Calculation involves converting volume to mass and then to kg.
Example 3: Dissolving 58.89 g KCl in 0.4975 kg of water:
Calculation: m = (58.89 g / 74.55 g/mol) / 0.4975 kg = 1.59 m
Example 4: Dissolving 58.89 g KCl in 500.0 mL of water Requires conversion of volume to mass.
How many moles of KCl to prepare 1.59 m solution in:
500.0 mL water (density = 0.995 g/cm³): 0.790 moles required.
How many grams of KCl to prepare 1.59 m solution in:
Calculation derived from moles needed and molecular weight.
Calculation to find water required for desired molality:
Given m = 1.59 m, KCl mass conversions determine solvent mass.
Convert the numerator and denominator using appropriate conversion factors.
Divide to get the new concentration unit.
Given:
6.08 M KCl with density of solution = 1.104 g/mL.
Procedure:
Calculate mass of solvent from volume of solution.
Convert concentration to molality.
The moles remain constant, conversion of units considers density.