Heating Curves and Phase Change Calculations
Heating Curves
- Depict the phase transitions of a substance as heat is added.
Phase Changes
- Heating Curve Stages
- Stage 1: Solid is heating.
- Stage 2: Solid to Liquid (Melting).
- Stage 3: Liquid is heating.
- Stage 4: Liquid to Gas (Vaporizing).
- Stage 5: Gas is heating.
Heat of Fusion
- Formula: Q = m \times H_f
- Q = heat/energy (in Joules)
- m = mass (in grams)
- H_f = Heat of Fusion (J/g)
- Energy required to melt one gram of a specific substance at its melting point.
Example 1: Heat of Fusion Calculation
- Problem: How much energy is required to melt 50.3 grams of H2O at 0°C? (Hf of H_2O = 334 J/g)
- Solution:
- Q = m \times H_f
- Q = 50.3 \times 334
- Q = 16800 Joules
Heat of Vaporization
- Formula: Q = m \times H_v
- Q = heat/energy (in Joules)
- m = mass (in grams)
- H_v = Heat of Vaporization (J/g)
- Energy required to vaporize one gram of a specific substance at its boiling point.
Example 2: Heat of Vaporization Calculation
- Problem: How much energy is needed to vaporize 50.3 grams of H2O at 100°C? (Hv of H_2O = 2260 J/g)
- Solution:
- Q = m \times H_v
- Q = 50.3 \times 2260
- Q = 114000 Joules
Example 3: Multi-Step Calculation
- Problem: How much heat is needed to change 22.0 grams of water from -14.0°C to 77.0°C?
Step-by-Step Calculation
- Heating the solid (ice) from -14.0°C to 0°C:
- Formula: Q = m \times C_{solid} \times \Delta T
- Q = 22.0 \times 2.05 \times (14.0)
- Q = 631 J
- Melting the ice at 0°C:
- Formula: Q = m \times H_f
- Q = 22.0 \times 334
- Q = 7350 J
- Heating the liquid water from 0°C to 77.0°C:
- Formula: Q = m \times C_{liquid} \times \Delta T
- Q = 22.0 \times 4.184 \times (77.0)
- Q = 7090 J
Total Heat Calculation
- Summing the heat from each step:
- Q{total} = Q{solid} + Q{melt} + Q{liquid}
- Q_{total} = 631 + 7350 + 7090
- Q_{total} = 15071 J