VA

Heating Curves and Phase Change Calculations

Heating Curves

  • Depict the phase transitions of a substance as heat is added.

Phase Changes

  • Heating Curve Stages
    • Stage 1: Solid is heating.
    • Stage 2: Solid to Liquid (Melting).
    • Stage 3: Liquid is heating.
    • Stage 4: Liquid to Gas (Vaporizing).
    • Stage 5: Gas is heating.

Heat of Fusion

  • Formula: Q = m \times H_f
    • Q = heat/energy (in Joules)
    • m = mass (in grams)
    • H_f = Heat of Fusion (J/g)
    • Energy required to melt one gram of a specific substance at its melting point.

Example 1: Heat of Fusion Calculation

  • Problem: How much energy is required to melt 50.3 grams of H2O at 0°C? (Hf of H_2O = 334 J/g)
  • Solution:
    • Q = m \times H_f
    • Q = 50.3 \times 334
    • Q = 16800 Joules

Heat of Vaporization

  • Formula: Q = m \times H_v
    • Q = heat/energy (in Joules)
    • m = mass (in grams)
    • H_v = Heat of Vaporization (J/g)
    • Energy required to vaporize one gram of a specific substance at its boiling point.

Example 2: Heat of Vaporization Calculation

  • Problem: How much energy is needed to vaporize 50.3 grams of H2O at 100°C? (Hv of H_2O = 2260 J/g)
  • Solution:
    • Q = m \times H_v
    • Q = 50.3 \times 2260
    • Q = 114000 Joules

Example 3: Multi-Step Calculation

  • Problem: How much heat is needed to change 22.0 grams of water from -14.0°C to 77.0°C?

Step-by-Step Calculation

  1. Heating the solid (ice) from -14.0°C to 0°C:
    • Formula: Q = m \times C_{solid} \times \Delta T
    • Q = 22.0 \times 2.05 \times (14.0)
    • Q = 631 J
  2. Melting the ice at 0°C:
    • Formula: Q = m \times H_f
    • Q = 22.0 \times 334
    • Q = 7350 J
  3. Heating the liquid water from 0°C to 77.0°C:
    • Formula: Q = m \times C_{liquid} \times \Delta T
    • Q = 22.0 \times 4.184 \times (77.0)
    • Q = 7090 J

Total Heat Calculation

  • Summing the heat from each step:
    • Q{total} = Q{solid} + Q{melt} + Q{liquid}
    • Q_{total} = 631 + 7350 + 7090
    • Q_{total} = 15071 J