Hess’ Law = The enthalpy change for a chemical reaction is the same regardless of the route from reactants to products
Standard enthalpy of formation = The enthalpy change of one mole of a compound is formed from its elements under standard conditions and standard states
Standard enthalpy of combustion = The enthalpy change of one mole of a compound burned completely in oxygen in standard conditions when all reactants and products are in their standard states (EXOTHERMIC)
Standard enthalpy of Atomisation = The enthalpy change of one gaseous atom formed from its element in standard state (ENDOTHERMIC)
First Ionisation Enthalpy = The standard enthalpy change of one mole of electrons is removed from one mole of gaseous atoms to give the atom a positive charge (ENDOTHERMIC)
Second Ionisation Enthalpy = The standard enthalpy change when one mole of electrons is removed from a +1 gaseous ion to make a gaseous ion with 2+ charge (ENDOTHERMIC)
First Electron Affinity = The standard enthalpy change of one mole of gaseous ions is converted to a gaseous ion with -1 charge under standard conditions (EXOTHERMIC)
Second Electron Affinity = The standard enthalpy change of one mole of electrons is added to a gaseous ion with a single -1 charge to form an ion with 2- charge
Lattice Formation Enthalpy = The standard enthalpy of one mole of solid ionic compound is formed from its gaseous ions (EXOTHERMIC)
Lattice Dissociation Enthalpy = The standard enthalpy change when one mole of solid ionic compound dissociates into gaseous ions (ENDOTHERMIC)
Standard Enthalpy of Hydration = The standard enthalpy change of mole of gaseous ions converted into one mole of aqueous ions (EXOTHERMIC)
Standard Enthalpy of Solution = The standard enthalpy change of one mole of solute dissolves in solvent to form a solution where the ions are too far to interact
Mean Bond Enthalpy(Bond Dissociation Enthalpy) = The enthalpy change when one mole of gaseous molecules break a covalent bond to form two free radicals (ENDOTHERMIC)
Rules:
The direction of the arrows (^) = POSITIVE (v) = NEGATIVE
Each step should be balanced
Must include state symbols
Each Cycle starts with Enthalpy Change of Formation of the ionic compound
Like NaCl → INTO NA + CI
Then both elements → Standard enthalpy of Atomisation
Na(s) → Na(g)
Cl(s) → Cl(g)
Then the First Ionisation energy enthalpy
Na → Na + e
Then lastly the First Electron Affinity Ionisation of Cl
Cl gains the e- from Ionisation of the other element
Standard Enthalpy of Atomisation = Bond Dissociation / 2
More Negative Standard Enthalpy of Lattice Formation = Stronger Ionic Bonds
Hydration Enthalpies:
The Size of the atoms (Ionic Radius)
The Charge of the atoms
Charge is more important than size during comparisons
Stronger attraction of ions to water will result in a more exothermic hydration enthalpy
Charge : As charge increases attraction increases
Radius : As size decreases attraction increases
“Perfect Ionic Model” refers to compounds which displays purely ionic bonding with no covalent character
Ions act as point charges
Ions are perfect spheres which cannot be distorted
Ions shows purely ionic bonding with no covalent character
The theoretical Standard Enthalpy of Formation calculated by the perfect ionic model is equal to the Born-Haber Standard Enthalpy of Formation calculated by the experimental model.
If there is a covalent character in the ionic compound then :
The theoretical Standard enthalpy of formation calculated by the perfect ionic model is less exothermic than the born-Haber standard enthalpy of formation calculated by the experimental model
Factors which determine whether a chemical reaction is feasible or not :
Temperature
Enthalpy - EXOTHERMIC REACTIONS ARE MORE FEASIBLE THAN ENDOTHERMIC
ENTROPY = IS THE AMOUNT OF DISORDER WITHIN A SYSTEM WHICH IS ‘S’ AND IS ALWAYS POSITIVE BUT ENTHALPY OF ENTROPY = POSITIVE AND NEGATIVE ( JK-1mol-1) and converted to (kJK-1mol-1) by /1000
Gases = Highest Entropies (more +)
Solids = Lowest Entropies (least +)
At 0K substances have 0 entropy and there is no disorder as particles are stationary
Enthalpy of G = Enthalpy of H - Temperature and Entropy change
A REACTION IS FEASIBLE IF THE ENTHALPY OF GIBBS FREE-ENERGY IS EQUAL OR LESS THAN 0