Normal Distribution

Normal Distribution

Introduction to Normal Distribution

This module covers the normal distribution, a fundamental concept in statistics, including how transformations affect its parameters, properties of its density curve, the empirical rule, z-scores, and the use of the standard normal table for probability calculations, as well as graphical assessment using Q-Q plots.

Shifting vs. Scaling

These are transformations applied to data that affect its statistical properties:

  • Shifting (Center and Position): Adding or subtracting a constant value to each data point.

    • Effect on Mean: The mean changes by the amount of the constant added or subtracted.

    • Effect on Standard Deviation: The standard deviation (and thus spread) remains unchanged.

    • Example (Bonus Marks): If XX is the original mark and a bonus of 55% (interpreted as 55 percentage points) is given, making the new mark S=X+5S = X + 5. The new mean score will be μ<em>S=μ</em>X+5\mu<em>S = \mu</em>X + 5, while the standard deviation will remain the same, σ<em>S=σ</em>X\sigma<em>S = \sigma</em>X.

  • Scaling (Spread and Shape): Multiplying or dividing each data point by a constant value.

    • Effect on Mean: The mean is multiplied or divided by the same constant.

    • Effect on Standard Deviation: The standard deviation is also multiplied or divided by the absolute value of the same constant.

    • Effect on Variance: The variance is multiplied or divided by the square of the constant.

    • Formulas provided for standard deviation and variance when scaling by a factor dd:

      • New standard deviation: s<em>new=s</em>original×ds<em>{new} = s</em>{original} \times d

      • New variance: s<em>new2=s</em>original2×d2s<em>{new}^2 = s</em>{original}^2 \times d^2

    • Example (Scaling Marks): If XX is the original mark and each mark is scaled up by 55%, meaning S=1.05×XS = 1.05 \times X. The new mean score will be μ<em>S=1.05×μ</em>X\mu<em>S = 1.05 \times \mu</em>X, and the new standard deviation will be σ<em>S=1.05×σ</em>X\sigma<em>S = 1.05 \times \sigma</em>X. For example, if a student got 6060%, their new mark would be 60×1.05=6360 \times 1.05 = 63%.

Density Curve

A density curve is a graphical representation of the distribution of a continuous variable. It must satisfy specific conditions:

  • Non-negativity: A density curve is always on or above the horizontal axis (i.e., its values are never negative, f(x)0f(x) \ge 0).

  • Total Area: The total area between the horizontal axis and under the density curve must equal 11 (or 100100%), representing the total probability or proportion of observations.

  • Probability as Area: The probability of an observation falling within an interval (a,b)(a, b), denoted as P(a < x < b), is equal to the area under the curve between aa and bb. This also represents the percentage of observations that will fall in that interval.

  • Continuous Variables Properties: For continuous variables, certain probability statements hold:

    • The probability of a single exact value is zero: P(x=a)=0P(x = a) = 0.

    • The inclusion or exclusion of endpoints does not change the probability for an interval: P(a < x < b) = P(a \le x \le b) = P(a < x \le b) = P(a \le x < b).

  • Example (Density Curve from Page 5):

    • Verification of Area = 1 (by geometry): Assuming a uniform distribution from 00 to 22 with a height (density) of 0.50.5. The area is Base×Height=(20)×0.5=2×0.5=1Base \times Height = (2 - 0) \times 0.5 = 2 \times 0.5 = 1.

    • Probability that XX is less than 11: P(X < 1) is the area from 00 to 11. Area=(10)×0.5=1×0.5=0.5Area = (1 - 0) \times 0.5 = 1 \times 0.5 = 0.5.

    • Probability that XX is greater than 1.51.5: P(X > 1.5) is the area from 1.51.5 to 22. Area=(21.5)×0.5=0.5×0.5=0.25Area = (2 - 1.5) \times 0.5 = 0.5 \times 0.5 = 0.25.

Empirical Rule (68-95-99.7% Rule)

This rule applies specifically to data that follows a normal distribution, describing the approximate percentage of observations that fall within a certain number of standard deviations from the mean:

  • Approximately 6868% of observations fall within 11 standard deviation (±1σ\pm 1\sigma) of the mean (μ\mu).

  • Approximately 9595% of observations fall within 22 standard deviations (±2σ\pm 2\sigma) of the mean (μ\mu).

  • Approximately 99.799.7% of observations fall within 33 standard deviations (±3σ\pm 3\sigma) of the mean (μ\mu).

  • Example (Standardized Exam Completion Time):

    • Given: Mean (μ=70\mu = 70 minutes), Standard Deviation (σ=10\sigma = 10 minutes).

    • Percentage of students completing the exam in under an hour (6060 minutes):

      • 6060 minutes is one standard deviation below the mean (7010=6070 - 10 = 60).

      • According to the empirical rule, 6868% of students complete between 6060 and 8080 minutes (μ±1σ\mu \pm 1\sigma).

      • The remaining 100%68%=32%100\% - 68\% = 32\% are outside this range, split equally below 6060 and above 8080. So, 32%/2=16%32\% / 2 = 16\% complete in under 6060 minutes.

    • Percentage of students completing the exam between 6060 and 7070 minutes:

      • This interval is from one standard deviation below the mean to the mean (μσ\mu - \sigma to μ\mu).

      • This represents exactly half of the 6868% interval: 68%/2=34%68\% / 2 = 34\%.

    • Time interval for the central 9595% of students:

      • The central 9595% of observations fall within 22 standard deviations of the mean (μ±2σ\mu \pm 2\sigma).

      • The interval is 70±(2×10)=70±2070 \pm (2 \times 10) = 70 \pm 20.

      • Therefore, the central 9595% of students would be found between 5050 and 9090 minutes.

Standardized Score / z-score

The z-score is a measure of relative standing that indicates how many standard deviations an observation is away from the mean.

  • Relative Standing: It positions a data point relative to the rest of the distribution.

  • No Units: Z-scores are unitless, allowing comparison across different distributions.

  • Interpretation: A z-score tells