Spring 2025 Intro to Material Sci & Engr (ENGR-2210-001, ENGR-2210-002, ENGR-2210-003, ENGR-2210-004)
Introduction
Review of crystal structures: Simple Cubic and Body-Centered Cubic (BCC)
Importance of unit cell in crystallography
Simple Cubic Structure
Definition
Consists of atoms at each corner of the cube.
Key Assumptions
Pure metals with identical atoms and spherical shape.
Atoms are in contact with nearest neighbors.
Coordination Number
Coordination number is 6, indicating the number of nearest neighbors.
Equivalent Number of Atoms
Each corner atom is shared by 8 unit cells:
1 atom contribution per unit cell: 8 corners x 1/8.
Radius and Lattice Parameter
Radius (r) relates to unit cell length (a): Formula: r = a/2.
Atomic Packing Fraction
Volume of sphere: V = (4/3)πr³
Total volume = a³, where a is the unit cell edge.
Atomic packing fraction = (Volume occupied by atoms / Total volume).
APF for simple cubic = 0.52 (52% packing efficiency, 48% void space).
Body-Centered Cubic (BCC)
Structure
Additional atom at the center of the cube, 8 corner atoms unchanged.
Coordination Number
Coordination number is 8, accounting for corners and center atom interactions.
Equivalent Number of Atoms
Calculation: 2 atoms per unit cell (8 corner atoms x 1/8 + 1 center atom).
Radius and Lattice Parameter
Atoms do not touch on edge; diagonal plane method used for calculation:
Based on geometry, derived as: r = (√3a)/4.
Atomic Packing Fraction
APF calculated as: Pi√3/8
Gives an APF of approximately 0.68 (68% packing efficiency).
Face-Centered Cubic (FCC)
Structure
Atoms are located at each corner and at the center of each face.
Coordination Number
Coordination number is 12. Atom touches 4 in the same plane, 4 in the layer above, and 4 in the layer below.
Equivalent Number of Atoms
4 atoms per unit cell (8 corner atoms x 1/8 + 6 face-centered atoms x 1/2).
Radius and Lattice Parameter
Radius relation: r = (√2a)/4, where all corner atoms touch face-centered atoms on any given face.
Atomic Packing Fraction
Calculation involves:
Number of atoms = 4,
Volume of sphere = (4/3)πr³,
Total volume = a³,
Resulting APF = (Pi√2)/6 = 0.74 (approximately 74% packing efficiency).
Hexagonal Close-Packed (HCP)
Structure
Two-dimensional hexagonal base with alternating layers (ABAB structure).
Coordination Number
Same as FCC: Coordination number is 12.
Equivalent Number of Atoms
Total number of atoms = 6 per unit cell (based on corner and layered contributions).
Radius and Lattice Parameter
Radius to edge (a) relation: r = a/2.
Theoretical Density Calculation
Density formulas explored:
𝜌 = nA/VcNa,
n = number of atoms per unit cell,
A = atomic weight,
Vc = volume of unit cell,
Na = Avogadro's number.
Numerical Example
Example Problem
Calculate theoretical density of Copper (FCC) given:
Atomic weight = 63.54 g/mol,
Atomic radius = 0.1278 nm,
Steps involve finding lattice parameter from radius and substituting values into density formula.
Conclusion
Importance of atomic arrangement in determining material properties.
Encourage students to understand calculations and physical implications for exams.