3.3.2 Rules of Differentiation
Slope of a Tangent Line (Finding where the derivative equals a prescribed value)
Problem statement
- Given f(x)=2x^3-15x^2+24x, find all x-values where the tangent line to the graph has slope 6.
- "Slope of the tangent" = value of the first derivative f'(x) at the desired point.
Differentiate with basic rules
- Power Rule (d/dx)[x^n]=nx^{n-1} and Constant Multiple Rule apply.
- Compute
\begin{aligned}
f'(x) &= (d/dx)(2x^3) - (d/dx)(15x^2) + (d/dx)(24x)\
&= 3\cdot 2x^{3-1} - 2\cdot 15x^{2-1} + 24\
&= 6x^2 - 30x + 24.
\end{aligned}
Set derivative equal to target slope
6x^2 - 30x + 24 = 6.- Subtract 6 from both sides: 6x^2 - 30x + 18 = 0.
- Factor out common 6: 6(x^2 - 5x + 3)=0 \Rightarrow x^2 - 5x + 3 = 0.
Quadratic Formula
- General form ax^2+bx+c=0 \Rightarrow x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}.
- Here a=1,\;b=-5,\;c=3:
x = \frac{-(-5) \pm \sqrt{(-5)^2-4(1)(3)}}{2(1)}
= \frac{5 \pm \sqrt{25-12}}{2}
= \frac{5 \pm \sqrt{13}}{2}. - Decimal approximations (useful for graphing or intuition):
\frac{5-\sqrt{13}}{2} \approx 0.697, \qquad \frac{5+\sqrt{13}}{2} \approx 4.303.
Interpretation/Significance
- At x \approx 0.697 and x \approx 4.303, the curve is rising with slope 6.
- In applications this process finds where a system meets a given rate-of-change requirement (e.g.
economics: marginal cost = given value, physics: velocity equals specific value, etc.).
Higher-Order Derivatives (Concept & Notation)
Idea
- "Higher order" means differentiating repeatedly.
- Notation:
- First derivative: f'(x) or \frac{dy}{dx}.
- Second derivative: f''(x) = \frac{d^2y}{dx^2} — captures concavity/acceleration.
- Third derivative: f'''(x) = \frac{d^3y}{dx^3} — appears in physics as "jerk" (rate of change of acceleration).
- n-th derivative: f^{(n)}(x).
Why care?
- Analyze curvature, inflection points, motion (position→velocity→acceleration→jerk→…).
- Used in Taylor series, differential equations, control systems.
Example 1 — Polynomial (Find the third derivative)
Reconstructed original function (deduced from derivative steps in the video):
g(x)=3x^3-5x+12.Step-by-step differentiation
- First derivative
g'(x)=9x^2-5 (since (d/dx)(3x^3)=9x^2, (d/dx)(-5x)=-5, constant 12 vanishes). - Second derivative
g''(x)=(d/dx)(9x^2-5)=18x. - Third derivative
g'''(x)=(d/dx)(18x)=18.
- First derivative
Observations
- The third derivative of a cubic polynomial is always constant.
- Physical analogy: a constant jerk implies linearly increasing acceleration.
Example 2 — Mixed Linear & Exponential (Find up to third derivative)
Function
y(t)=3t+2e^{t}.Notation reminder
- Using Leibniz form \frac{dy}{dt},\;\frac{d^2y}{dt^2},\;\frac{d^3y}{dt^3}.
Derivatives
- First derivative
\frac{dy}{dt}=3+2e^{t}, because (d/dt)(3t)=3 and (d/dt)(e^{t})=e^{t}. - Second derivative
\frac{d^2y}{dt^2}=2e^{t} (derivative of constant 3 is 0; 2e^{t} remains unchanged). - Third derivative
\frac{d^3y}{dt^3}=2e^{t} (exponential function differentiates to itself indefinitely).
- First derivative
Pattern insight
- For ae^{t}, every derivative is still ae^{t}.
- Linear terms vanish after first differentiation.
Quick Reference: Rules Employed & Their Significance
- Power Rule: \frac{d}{dx}(x^{n}) = nx^{n-1} (foundation for differentiating polynomials).
- Constant Multiple Rule: \frac{d}{dx}[c\,f(x)] = c\,f'(x).
- Sum/Difference Rule: differentiate term-by-term.
- Derivative of e^{x}: remains e^{x} — makes exponentials pivotal in modeling continuous growth/decay.
- Quadratic Formula: universal method when factoring fails; discriminant b^2-4ac signals number/nature of roots.
Broader Connections & Practical Takeaways
- Tangent‐slope problems illustrate how derivatives convert geometric questions into algebraic ones.
- Higher-order derivatives underpin concavity testing, optimization (via second derivative test), and series approximations (Taylor/Maclaurin).
- Exponentials’ self-replicating derivatives explain their ubiquity in differential equations (e.g.
Newton’s law of cooling, population models). - Recognizing when to switch from factoring to quadratic formula saves time and prevents errors.
Suggested Practice / Next Steps
- Re-work the tangent‐slope example with a different target slope (e.g.
m=10) to reinforce the derivative-to-algebra transition. - Compute 4th and 5th derivatives of the exponential example to verify the pattern.
- Sketch f(x)=2x^3-15x^2+24x and mark the points where the slope equals 6 to internalize the geometric meaning.
- Read ahead on the second derivative test for local maxima/minima to see higher-order derivatives in action.