The teacher recaps the weekend and shares personal experiences such as working on the exam and grading notebooks.
Announces the upcoming final mid-term assessment on Friday.
Format: 25 questions, 24 questions worth 9 points, and 1 question worth 5 points.
Informing students about revisiting two questions from the previous midterm.
Discussion on regulating gene expression at different levels:
Transcriptional Regulation: Control of whether a gene is transcribed.
Importance of controlling gene expression to save resources.
Positive Influence on Gene Expression:
Positive regulators bind near a promoter to enhance transcription.
Examples of positive regulators discussed.
Negative Influence on Gene Expression:
Negative regulators bind to DNA to turn off transcription.
Example: The lac repressor in E. Coli and its role in lactose utilization.
Lactose Utilization Mechanism:
Genes ZYA encode enzymes for lactose metabolism (lactose is a disaccharide of glucose and galactose).
Operator: A binding site for transcription factors.
Promoter (P lac): The site for regulator binding, upstream of ZYA.
Repressor (I gene): Encodes a transcriptional repressor that negatively regulates transcription when lactose is absent.
Lactose Absent:
Lac repressor binds operator, blocking RNA polymerase.
Prevents transcription and conserves resources.
Lactose Present:
Allolactose (isomer of lactose) binds to the lac repressor at the allosteric site.
Positive regulation occurs: repressor releases from operator; RNA polymerase can then transcribe ZYA genes.
Experiment Observations: E. Coli uses glucose first, even when lactose is present.
Cyclic AMP and CRP:
CRP (Cyclic AMP Receptor Protein) binds low glucose levels represented by high cyclic AMP.
This binding activates transcription of lactose genes when glucose levels are low.
The presence of glucose inhibits the activation of lactose utilization genes via low cyclic AMP levels.
Importance of understanding positive and negative regulation mechanisms.
Need to be able to reason through the logic behind gene regulation based on environmental signals.
A cohesive understanding rather than memorization of truth tables for situations like the lac operon.
Genotype: Sequence of nucleotides (As, Gs, Cs, Ts) in an organism's genome.
Phenotype: Any measurable characteristic other than the genotype, e.g., height, color, enzyme production.
Mutant genotypes represent different variants from the wild type.
Types of Mutations:
Point mutations, frameshift mutations, and mutations in promoters.
Mutations can either disrupt transcription or alter the function of resultant proteins.
Promoter Mutations: Can result in loss or decrease of transcription efficiency.
Discussion on different chromosome copy numbers (haploid, diploid, etc.) and significance in genetics.
Haploid: One copy of chromosomes.
Diploid: Two copies (one from each parent).
Terms: Wild type (most common variant) and alleles (variations of genes).
Example of two yeast versions (Mating types): haploid and diploid conditions.
Exploration of how mating leads to genetic diversity and study of phenotypic expression.
Conclusion: Reproduction strategies are chosen based on environmental stability or variability.
Brief overview of pathways leading to nucleotide synthesis.
Example of Gene Function: ADD2 gene's role in synthesizing a compound related to phenotypic expression.
Effects of mutations: Knockout of ADD2 leads to accumulation of red pigment due to oxidative reactions.