Focuses on derivatives, building on concepts from Unit 1 (limits and continuity).
Key foundational rules for Units 3-5 will be introduced.
Emphasis on memorization of derivative formulas for quicker exam responses.
Average Rate of Change: Calculated using the difference quotient.
Can be expressed as:
( \frac{f(a + h) - f(a)}{h} )
or ( \frac{f(x) - f(a)}{x - a} )
Instantaneous Rate of Change: Derivative at a specific point, transitioning from average rate of change.
Achieved by narrowing the interval between two points until they are infinitesimally close.
Graphically represented by the slope of the tangent line at that point.
Example to calculate average rate of change between two points
Given points (1, 3) and (9, 6):
Using the formula ( \frac{f(x) - f(a)}{x - a} ): ( \frac{6 - 3}{9 - 1} = \frac{3}{8} )
Interpretation: For every horizontal unit, vertical movement is ( \frac{3}{8} ) units.
Found by applying limits to the difference quotient formulas:
( f'(a) = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h} ) or ( f'(a) = \lim_{x \to a} \frac{f(x) - f(a)}{x - a} )
Both forms show how to find the instantaneous rate of change.
Common forms: ( f'(x) ), ( y' ), ( \frac{dy}{dx} ).
All forms represent the first derivative and are interchangeable.
For ( f(x) = x^2 + 1 ) at ( a = 3 ):
Derive using the definition: ( f'(3) = \lim_{x \to 3} \frac{f(x) - f(3)}{x - 3} )
Calculates to give an instantaneous rate of change of 6.
Estimation from graphs or tables of values:
Example: Estimating derivative at ( x=3 ) using values around it.
Use difference quotient with points on either side:
Example Calculation: ( f(4) = 5.2 ) and ( f(2) = 3.5 )
Yielded a derivative estimate of -0.85.
If a function is differentiable at a point, then it is continuous at that point.
A continuous function is not necessarily differentiable.
If a function is discontinuous at a point, it is not differentiable at that point.
Smoothness is necessary for differentiability — non-smooth points (e.g., cusps) imply non-differentiability.
Examining piecewise functions to determine differentiability.
Sketch the function accurately according to given conditions.
Identify points of continuity and smoothness.
The simplest rule for derivatives:
For traditional power functions: ( rac{d}{dx} x^n = nx^{n-1} )
Example: For ( 3x^4 ): ( f'(x) = 12x^3 )
Applies similarly for negative exponents.
Derivative of a Constant: Always zero.
Derivative of a Polynomial: Derivative of each term computed separately.
Example: ( f(x) = x^3 + 3x^2 + 1 ) yields ( 3x^2 + 6x ).
Important derivatives to memorize for the AP exam:
( \frac{d}{dx} \sin(x) = \cos(x) )
( \frac{d}{dx} \cos(x) = -\sin(x) )
Continue the pattern of derivatives of sine and cosine with respect to fluctuations in signs.
Exponential function derivative: ( \frac{d}{dx} e^x = e^x )
Logarithmic function derivative: ( \frac{d}{dx} \ln(x) = \frac{1}{x} )
Formula to find the derivative of a product of functions:
( (f imes g)' = f'g + fg' )
Example: For ( 6x ext{sin}(x) ): ( f' = 6 ) and ( g' = \cos(x) )
Result: ( 6 ext{sin}(x) + 6x ext{cos}(x) )
Used when differentiating a rational function:
Formula: ( \frac{d}{dx} \left( \frac{f}{g} \right) = \frac{f'g - fg'}{g^2} )
Example: For ( \frac{x^2}{\ln(x)} ): Leading to the simplification of ( \frac{2x\ln(x)-x}{\ln(x)^2} )
Extend differentiation rules for tangent, cotangent, secant, and cosecant.
Can often simplify complex derivatives using base definitions of functions.
Understanding average vs. instantaneous rates of change is crucial.
Know definitions of derivatives and can apply limits to difference quotients.
Ensure familiarity with derivative notations and formulas, particularly for key functions and rules (product and quotient).
Ability to relate smoothness and continuity to differentiability is vital for problem-solving.