Solutions Chemistry Notes

Solutions

Objectives

  • Describe energy changes during the solution process (solute-solute, solvent-solvent, solute-solvent attractive forces) and the role of disorder.
  • Define mass percentage, parts per million, mole fraction, molarity, and molality.
  • Calculate concentrations using these units.
  • Define solution-related terms: solvent, solute, hydration, miscible, saturated, etc.
  • Convert between concentration units (given solution density).
  • Determine if a mixture is saturated, supersaturated, or unsaturated, and calculate undissolved solid amount.
  • Relate solubility to molecular structures and intermolecular forces; predict relative solubility in specific solvents.
  • Describe effects of pressure and temperature on solubility of solids and gases, including Henry's Law.
  • Describe effects of dissolved particle concentration on vapor pressure, boiling point, freezing point, and osmotic pressure; calculate colligative properties from concentration data.
  • Estimate the van't Hoff i factor from a compound's formula.
  • Determine concentration and molar mass of nonvolatile nonelectrolytes or electrolytes from colligative properties.
  • Predict the lowest/highest freezing or boiling point among compounds (including electrolytes) given their molality.

Solution Vocabulary

  • Solution: Solute + Solvent
  • A uniform or homogenous mixture.
Examples of Different Types of Solutions
  • Solid in solid: Brass (zinc and copper mixture)
  • Solid in liquid: Sugar water
  • Liquid in solid: Mercury in silver (dental amalgam)
  • Liquid in liquid: Gasoline (hydrocarbon mixture)
  • Gas in solid: Hydrogen in platinum
  • Gas in liquid: Carbonated soft drinks (CO₂ in water)
  • Gas in gas: Air (O₂ in N₂)

\"Like Dissolves Like\"

  • Solvents dissolve solutes with similar Intermolecular Forces (IMFs).
    • Polar solvents dissolve ionic and polar solutes (permanent charges).
    • Nonpolar solvents dissolve nonpolar solutes (instantaneous charges).

Choosing the Best Solvent

  • Examples:
    • Ammonia (NH₃) - Water (H₂O)
    • Hexane (C₆H₁₄) - C₈H₁₈
    • CaCl₂ - Water

Saturation Vocabulary Roundup

  • Unsaturated: Less than the maximum solute amount is dissolved.
  • Saturated: The maximum solute amount is dissolved; solid remains at the bottom. Equilibrium exists.
  • Supersaturated: More than the maximum solute amount is dissolved; unstable.

Thermodynamics of Solution Formation

  • Steps:
    1. Break solvent-solvent interactions.
    2. Break solute-solute interactions.
    3. Form solute-solvent interactions.
  • Pure solute and solvent → Solution
  • ΔH<em>solution=ΔH</em>1+ΔH<em>2+ΔH</em>3ΔH<em>{solution} = ΔH</em>1 + ΔH<em>2 + ΔH</em>3
  • ΔSΔS is so large that ΔG<0ΔG < 0 even when ΔH>0ΔH > 0.
Supersaturated Solutions
  • Unstable; created by \"tricking\" the solution via heating to dissolve more solute.
  • Crystallization is induced by a seed crystal or tapping.

More Solution Vocabulary

  • Miscible: Two liquids completely soluble in each other (similar IMFs), e.g., acetic acid and water (hydrogen bonding).
  • Immiscible: Two liquids not soluble (dissimilar IMFs), e.g., oil and water (London dispersion forces and hydrogen bonding).

Solubility and Temperature

  • Graphs show the solubility of different compounds at different temperatures.
  • Solubility is expressed as grams of solute per 100 g of water.
  • Example compounds: KNO<em>3KNO<em>3, sucrose (C</em>12H<em>22O</em>11C</em>{12}H<em>{22}O</em>{11}), NaNO<em>3NaNO<em>3, CaCl</em>2CaCl</em>2, NaClNaCl, KBrKBr, KClKCl, KClO<em>3KClO<em>3, K</em>2Cr<em>2O</em>7K</em>2Cr<em>2O</em>7, Ce<em>2(SO</em>4)3Ce<em>2(SO</em>4)_3
Solids vs. Gases
  • Solids: Solubility generally increases with increasing temperature.
  • Gases: Solubility generally decreases with increasing temperature.
    • Gases include methane, oxygen, carbon monoxide, nitrogen, helium.

Solubility and Pressure

  • Solids: Solubility is generally not affected by pressure.
  • Gases: Solubility generally increases with increasing pressure.

Henry's Law

  • The linear relationship between pressure and gas solubility:
    • S<em>g=kP</em>gS<em>g = kP</em>g
    • SgS_g = solubility of the gas in the solution
    • PgP_g = partial pressure of the gas over the solution
    • kk = Henry's law constant (varies with each solute-solvent pair)
  • As pressure doubles, solubility doubles.
Example: Henry's Law
  • A sealed carbonated soda has a CO₂ partial pressure of 4.0 atm at 25°C; the CO₂ concentration is 0.14 M.
    • Calculate Henry's Law constant for CO₂ in water at 25°C.
    • Find the CO₂ concentration after opening when it equilibrates at a partial pressure of 3.0×10−43.0 × 10^{-4} atm.

Curve Fitting

  • Scientific data often match a standard curve shape (line, parabola, exponential, or logarithmic).
  • Historically, lines were easiest to work with; data would be mathematically manipulated to convert curves to lines.
  • The slope of the line often has meaning.

Conditions for Dissolving Maximum Solute

  • Gases: Low temperature, high pressure
  • Solids: High temperature, pressure doesn't matter

Concentration Units

  • Molarity (M)
  • Molality (m)
  • Percent
  • ppm (parts per million)
  • ppb (parts per billion)
  • Normality
  • Osmolarity
  • Mole Fraction
Molarity (M)
  • M=moles of soluteliters of solutionM = \frac{moles \ of \ solute}{liters \ of \ solution}
Molarity Example
  • How many grams of glucose (C<em>6H</em>12O6C<em>6H</em>{12}O_6, molar mass 180.18 g/mol) are needed to make 250 mL of 0.15 M aqueous solution?
Molality (m)
  • m=moles of solutekilograms of solventm = \frac{moles \ of \ solute}{kilograms \ of \ solvent}
  • Needed for freezing point depression lab.
Molality Example
  • How many grams of glucose (C<em>6H</em>12O<em>6C<em>6H</em>{12}O<em>6) are needed to dissolve in 563 grams of ethanol (C</em>2H5OHC</em>2H_5OH) to prepare a 0.0240 m solution?
Percent by Mass
  • mass%=mass of solutetotal mass of solution×100mass \% = \frac{mass \ of \ solute}{total \ mass \ of \ solution} × 100
Mole Fraction (X)
  • X=moles of solutetotal moles of solutionX = \frac{moles \ of \ solute}{total \ moles \ of \ solution}
Example: Mole Fraction, Mass Percent
  • A solution contains 0.100 mol NaCl in 8.60 mol water. Find the mole fraction and mass percent of NaCl (molar mass of NaCl = 58.44 g).
Density of Solution
  • D=mass of solutionvolume of solutionD = \frac{mass \ of \ solution}{volume \ of \ solution}

Concentration Conversions

  • Convert concentration from one set of units to another (e.g., molarity to molality); density is often given.
  • Look at the denominator unit (not density). Pick an "easy" amount to work with based on this.
  • Perform calculations based on this amount.
    • Molarity: 1 L of solution
    • Molality: 1 kg of solvent
    • Mass %: 100 g of solution
  • Some problems give a fixed amount to begin with (mass of solute and solvent) instead of concentration. In this case, you don't need to make assumptions.
3-2-1 Table for Conversions
  • 3 Masses: Mass of solute, mass of solvent, mass of solution
  • 2 Moles: Moles of solute, moles of solvent
  • 1 Volume: Volume of solution
  • Fill in any pieces of the table that you can to find a clear path from given information to the target concentration unit.
Conversion Example
  • An 8.00 mass % aqueous solution of ammonia has a density of 0.9651 g/mL. Calculate the molality, molarity, and mole fraction.

Colligative Properties

  • Depend on the concentration of solution, not the nature of the solute or solvent.
    • Freezing point depression
    • Boiling point elevation
    • Vapor pressure lowering
    • Osmotic pressure
Freezing Point Depression
  • ΔT<em>f=T</em>f,solvent−T<em>f,solution=iK</em>fmΔT<em>f = T</em>{f,solvent} - T<em>{f,solution} = iK</em>fm
    • ii = van't Hoff factor
    • KfK_f = freezing point depression constant
    • mm = molality
Van't Hoff i Factor
  • i=Moles of particles in solutionMoles of solute dissolvedi = \frac{Moles \ of \ particles \ in \ solution}{Moles \ of \ solute \ dissolved}
  • Examples:
    • Glucose C<em>6H</em>12O6(s)→i=1C<em>6H</em>{12}O_6(s) \rightarrow i = 1
    • NaCl(s)→i=2NaCl(s) \rightarrow i = 2
    • BaCl2(s)→i=3BaCl_2(s) \rightarrow i = 3
    • AlCl3(s)→i=4AlCl_3(s) \rightarrow i = 4
KfK_f
  • Freezing point depression constant depends on the solvent, not the solute.
Boiling Point Elevation
  • ΔT<em>b=T</em>b,solution−T<em>b,solvent=iK</em>bmΔT<em>b = T</em>{b,solution} - T<em>{b,solvent} = iK</em>bm
    • Boiling point works in the opposite direction from freezing point. Add ΔT<em>bΔT<em>b to T</em>bT</em>b.
    • The biggest i×mi×m has the highest boiling point.
Example: Freezing and Boiling Points
  • What are the boiling point and freezing point of a solution made by dissolving 1000 grams of ethylene glycol (antifreeze, C<em>2H</em>6O2C<em>2H</em>6O_2) in a car radiator containing 4450 grams of water?
    • KfK_f (water) = 1.86 °C/m
    • KbK_b (water) = 0.52 °C/m
Comparing Freezing Points
  • Which aqueous solution will have the lowest freezing point?
    • Pure water
    • 0.2 m sucrose
    • 0.2 m NaCl
    • 0.15 m K<em>2SO</em>4K<em>2SO</em>4

Molar Mass by Freezing Point Depression

  • MM=mass of unknown (g)×K<em>fmass of solvent (kg)×ΔT</em>fMM = \frac{mass \ of \ unknown \ (g) × K<em>f}{mass \ of \ solvent \ (kg) × ΔT</em>f}
Example: Molar Mass
  • 1.22 g of a white solid (suspected pure cocaine) is dissolved in 15.60 g of benzene; the freezing point is lowered by 1.32 °C. Calculate the molar mass of the solid (Kf for benzene = 5.12 °C/m).