Key topics:
Rotational Kinematics
Rotational Dynamics; Torque and Moment of Inertia
References: 9-1, 2, 3, 4, 5
In rotational motion, points on the object move in circles around the axis of rotation (O).
Radius (R) of the circles is significant; all points along a line through the axis move through the same angle in the same time.
Angle (θ) in radians is defined as:
θ = l/R (where l is the arc length)
Sign convention:
for Counter-Clockwise (CCW)
for Clockwise (CW)
Relationship for one revolution:
l = 2πR (encodes 360° rotation)
Angular Displacement (Δθ): Δθ = θ2 - θ1
Average Angular Velocity (ω): ω = Δθ / Δt
Instantaneous Angular Velocity: ω = lim (Δθ/Δt) as Δt approaches 0
Frequency (f) is the number of complete revolutions per second (unit: Hertz).
Period (T) is the time taken for one complete revolution.
Angular Velocity (ω in rad/sec): ω = 2πf (since there are 2π radians in a revolution).
Average Angular Acceleration (α): α = (ω2 - ω1) / Δt
Instantaneous Angular Acceleration: α = lim (dω/dt) as dt approaches 0
Points further from the axis of rotation move faster than those closer to the axis.
Rotation relationship as angles measured in radians.
Changing angular velocity leads to tangential acceleration:
Tangential acceleration (at) = αR (R is radius)
Centripetal acceleration (
Centripetal acceleration (ac): ac = v^2/R
Total linear acceleration (a): a = √(at^2 + ac^2) (vector sum)
A carousel has constant angular acceleration α = 0.060 rad/s² starting from rest for 8.0 s.
(a) Angular velocity (ω): ω = ω0 + αΔt = 0 + (0.060)(8.0) = 0.48 rad/s
(b) Linear velocity (v) of a child at R = 2.5 m: v = ωR = 0.48 × 2.5 = 1.2 m/s
(c) Tangential acceleration (at): at = αR = (0.060)(2.5) = 0.15 m/s²
(d) Centripetal acceleration (ac): ac = v²/R = (1.2²/2.5) = 0.58 m/s²
(e) Total linear acceleration (a): a = √(at² + ac²) = √(0.15² + 0.58²) = 0.60 m/s²
Equations of motion for constant angular acceleration parallel those for linear motion, substituting angular quantities in.
Initial position is taken as zero.
Centrifuge accelerated from rest to 20,000 rpm in 30 s.
(a) Average angular acceleration (α): α = Δω / Δt = (20000 RPM to rad/s: 20000 × 2π/60) / 30
(b) Revolutions made (θ) during acceleration:
θ = ω0t + 0.5αt², using Δω and Δt for calculation.
Importance of long lever arms in rotating objects: a force is needed to initiate rotation.
Torque (τ) is defined as the force applied at a distance (lever arm) from the axis of rotation:
Lever arm = perpendicular distance from the axis to the force line.
Example: Lever arms for different forces (FA, FD, FC) in a rotational system.
Importance of the location of force: Forces not shifted in free-body diagrams (FBD).
Torque formula:
τ = R F⊥ = RF sin(θ)
Where F⊥ = F sin(θ) and R is the distance from the axis of rotation.
Two disk-shaped wheels (RA = 30 cm, RB = 50 cm) | Forces of 50 N acting on each.
Calculate net torque using τ = - (FR_A sin θ_A + FR_B sin θ_B)
Tangential component of Newton’s second law applied to rotational systems.
Equation: τ = Iα, where I = moment of inertia (I = mR²).
Moment of inertia (I) = ∑ mR², an object's resistance to rotational motion.
Distribution of mass affects resistance, even with same mass.
Summary of Newton’s Law for rotation: ∑τ = Iα
Importance of mass distribution and axis of rotation in the calculation of rotational inertia.
Overview of common moments of inertia for various shapes:
Thin cylindrical shells, thin rods, solids, hollow cylinders, etc.
Atwood machine setup with masses mA and mB connected by a pulley with moment of inertia (I).
Derivation for acceleration of masses.
Forces acting on the masses and the relationship with torque and rotational motion derived from Newton's laws.