(40) GCSE Chemistry Revision "Avogadro's Constant 2"
Understanding Avogadro's Constant
Avogadro's constant is defined as 6.02 x 10^23, representing the number of atoms, ions, or molecules contained in one mole of a substance.
Moles and Calculations
Calculation of Moles
To calculate the number of moles from mass:
Formula: Number of moles = Mass (in grams) / Relative atomic mass
Example 1: Magnesium
Given: 48 grams of magnesium
Relative atomic mass of magnesium = 24
Number of moles: 48g / 24 = 2 moles
Total number of atoms:
2 moles x Avogadro's constant (6.02 x 10^23) = 1.204 x 10^24 atoms
Example 2: Lithium
Given: 28 grams of lithium
Relative atomic mass of lithium = 7
Number of moles: 28g / 7 = 4 moles
Total number of atoms:
4 moles x Avogadro's constant = 2.408 x 10^24 atoms
Calculating Atoms in Compounds
Example 3: Calcium Oxide (CaO)
Given: 56 grams of calcium oxide
Relative formula mass is calculated as follows:
Calcium (Ca): relative atomic mass = 40
Oxygen (O): relative atomic mass = 16
Relative formula mass = 40 + 16 = 56
Number of moles:
56g / 56 = 1 mole
Total number of molecules:
1 mole x Avogadro's constant = 6.02 x 10^23 molecules
Total number of atoms:
Each molecule contains 2 atoms (1 Ca + 1 O)
6.02 x 10^23 molecules x 2 = 1.204 x 10^24 atoms
Example 4: Water (H2O)
Given: 54 grams of water
Relative formula mass is calculated as follows:
Hydrogen (H): relative atomic mass = 1
Oxygen (O): relative atomic mass = 16
Water contains 2 H and 1 O, therefore:
Relative formula mass = (2 x 1) + 16 = 18
Number of moles:
54g / 18 = 3 moles
Total number of molecules:
3 moles x Avogadro's constant = 1.806 x 10^24 molecules
Total number of atoms:
Each water molecule contains 3 atoms (2 H + 1 O)
1.806 x 10^24 molecules x 3 = 5.418 x 10^24 atoms
Practice
Additional practice problems can be found in the vision workbook associated with this video.