intermolecular forces (imf’s): attractive forces between molecules that hold substances in condensed states (liquid or solid).
depends on imf strength (aka polarity + molar mass) !!
high imf = liquid or solid @ room temp.
low imf = gas @ room temp.
intramolecular force: attractive forces within molecules like metallic, covalent, or ionic bonding.
holds a compound together !!
melting point / boiling point: ↑ bp and ↑ mp = ↑ imf (more energy is required to overcome imf’s going from solid to liquid).
substances w/ bp’s LESS THAN 23°C are GASES at room temp.
substances w/ bp’s BETWEEN 23°C — 100°C are LIQUIDS at room temp.
the IMF forces !!
ion-ion (intramolecular force)
VERY strong.
ionic… salt… ALWAYS solid @ room temp.
ion-dipole
occurs when an ionic substance is mixed with a polar (covalent) substance
aka. salt dissolution
hydrogen bonding
polar molecules containing hydrogen DIRECTLY bond to ↑ electronegative atoms N, O, or F.
creates a “super” dipole-dipole force where the hydrogen atom acts as a “bridge” between two NOF atoms.
substances Hbonding capable tend to have ↑’er boiling points / melting points than comparable substances that aren’t Hbond capable.
Hbonds aren’t true chem. bonds but rather intermolecular associations
dipole-dipole
ALL polar molecules have permanent dipoles and ↑’er IMF’s than comparably sized non polar molecules
determines solubility… “like dissolves like”…
london dispersion forces (ldf’s)
present between ALL molecules, most significant in non-polar substances.
results from fluctuations in electron distributions of each electron cloud.
strength is determined by how polarizable it’s electron cloud is…
larger cloud = more polarizable = stronger LDF
neopentane vs. pentane
neopentane has a lower electron cloud surface area and is “bulky”
pentane has a higher electron cloud surface area and is “long”
↑ imf’s = ↑ bp (liq.) + ↑ mp (sol.) because more thermal energy is required to break the attractive forces BETWEEN the molecules in their condensed states.
surface tension: the energy required to raise surface area - ↑’s with increasing IMF strength.
ex. h2o droplets form spheres because h2o has a tendency to minimize surface area to lower inherent molecular potential energy.
molecules @ liquid surface have ↑’er potential energy than interior molecules as the exterior ones have fewer “neighbors” to interact with… therefore making them less stable… therefore giving them higher potential energies.
spherical shapes have the LOWEST surface energy to volume ratio of any shape.
viscosity: the resistance of a liquid to flow.
vapor pressure + dynamic equilibrium
dynamic equilibrium is when the ratio of condensation and the ratio of vaporization becomes equal. the pressure of a gas in dynamic equilibrium with it’s liquid is it’s vapor pressure. the vapor pressure of a liquid depends on the imf’s present in the liquid and the temperature of the system.
↑ imf’s = ↓ vapor pressure
↑ vapor pressure = ↑ vaporization rate
vaporization (liquid to gas)
thermal energy overcomes imf’s to produce a state/phase change. molecules are in constant motion due to thermal energy and ↑’er temperature = ↑’er average kinetic energy of the collection of molecules. molecules @ the surface of a liquid are held less tightly than they are in the interior due to fewer “neighbor” interactions. therefore, some break free of liquid phase and become a gas.
volatility of liquids:
volatile liquids have WEAK imf’s, therefore evaporate at higher rates @ room temp.
nonvolatile liquids have STRONG imf’s, therefore vaporize slower @ room temp.
condensation: the reverse process of vaporization… exothermic change
enthalpy of vaporization: the amount of heat required to vaporize or condense ONE mole of a liquid to a gas.
use q = mC△T for temperature change !!
q = heat
m = mass
C = specific heat capacity
(how much energy is needed to raise temp. of single mole of a specific substance by a single celsius
△T = final(T) - initial(T)
use q = n△H for a phase change
q = heat
n = moles
(△H = q / n)
segment 1 (+ slope)
temp△ NOT a phase△
Csice = 2.09J / g • °C
q = 1.5E3J = 1.5KJ
segment 2 (0 slope)
heat added doesn’t temp△ because the heat is absorbed by the phase△
Hfus = 6.02kJ / mole
q = 6.02kJ
segment 3 (+ slope)
calculate heat
CsH2o = 4.18J / g • °C
q = 7.52kJ
segment 4 (0 slope)
phase△ liquid to gas needs △Hvap enthalpy of vaporization.
△HvapH2o = 4.07kJ / mole
q = 4.07kJ
parts of a phase diagram:
sublimation curve > fusion curve (vertical between) > vaporization curve
solid to the left of fusion curve
liquid to the right of fusion curve
fusion curve doesn’t continue past triple point