A student collects twelve groundwater samples from a well.
Measures dissolved oxygen concentration in six samples:
Values (mg/L): 8.8, 3.1, 4.2, 6.2, 7.6, 3.6
Sample mean calculation:
( x = \frac{8.8 + 3.1 + 4.2 + 6.2 + 7.6 + 3.6}{6} = 5.6 \text{ mg/L} )
Formula: ( SD = \sqrt{\frac{\sum (x - \bar{x})^2}{n-1}} )
Calculation Steps:
Differences:
8.8 - 5.6 = 3.2 (9.84)
3.1 - 5.6 = -2.5 (6.25)
4.2 - 5.6 = -1.4 (1.96)
6.2 - 5.6 = 0.6 (0.36)
7.6 - 5.6 = 2.0 (4.00)
3.6 - 5.6 = -2.0 (4.00)
Sum of squares: 26.81
( SD = \sqrt{\frac{26.81}{5}} = 2.3 \text{ mg/L} )
( SEM = \frac{SD}{\sqrt{n}} = \frac{2.3}{\sqrt{6}} = 0.95 \text{ mg/L} )
Sample concentration values: 5.2, 8.6, 6.3, 1.8, 6.8, 3.9
Grand average calculation of all twelve samples:
Mean: ( x = \frac{8.8 + 3.1 + 4.2 + 5.2 + 8.6 + 6.3 + 1.8 + 6.8 + 3.9}{12} = 5.5 )
Standard deviation for combined twelve observations:
Calculation of deviations and their squares:
Repeat similar steps to find deviations from mean for each sample.
Final SD: 2.2 mg/L
For 95% confidence:
Degrees of freedom: 11
Using t-distribution with 0.025 (two-tailed, 95%): ( t_{0.025} = 2.201 )
Confidence interval: ( 5.5 \pm (2.201 \times 0.65) )
Yielding limits: 4.1 to 6.9 mg/L
Suggests increasing sample size reduces error
Used to determine if outliers should be rejected from datasets:
Example values: 4.3, 4.1, 4.0, 3.2
Calculation of Q for 3.2:
( Q = \frac{3.2 - 4.0}{4.3 - 3.2} = 0.727 )
Compare with Q critical values to determine acceptance
Compares variances of two sample sets
Example standard deviations: ( S_A = 0.210, S_B = 0.641 )
F statistic calculation: 9.4
Comparison against critical thresholds for significance
Higher sample quantity decreases confidence intervals
Assessment of reliability and accuracy in measurements
Important for data modeling and prediction in spectroscopic analysis
Relationship of dependent and independent variables analyzed through regression equation.