When predicting reaction products, first identify the reaction type. Each type has specific rules and patterns to follow.
Definition: Two or more reactants combine to form a single product.
General Formula: A + B → AB
Metal + Nonmetal → Ionic Compound
Example: 2Na+Cl2→2NaCl2Na + Cl_2 → 2NaCl2Na+Cl2→2NaCl
Sodium reacts with chlorine gas to form sodium chloride (table salt).
Nonmetal Oxide + Water → Acid
Example: CO2+H2O→H2CO3CO_2 + H_2O → H_2CO_3CO2+H2O→H2CO3
Carbon dioxide dissolves in water to form carbonic acid.
Metal Oxide + Water → Base (Metal Hydroxide)
Example: CaO+H2O→Ca(OH)2CaO + H_2O → Ca(OH)_2CaO+H2O→Ca(OH)2
Calcium oxide reacts with water to form calcium hydroxide.
🔥 Practice Problem:
Predict the product of the reaction: Mg+O2Mg + O_2Mg+O2
Definition: A single reactant breaks down into two or more simpler substances.
General Formula: AB → A + B
Metal Carbonates → Metal Oxide + CO₂
Example: CaCO3→CaO+CO2CaCO_3 → CaO + CO_2CaCO3→CaO+CO2
Calcium carbonate decomposes into calcium oxide and carbon dioxide.
Metal Hydroxides → Metal Oxide + H₂O
Example: Mg(OH)2→MgO+H2OMg(OH)_2 → MgO + H_2OMg(OH)2→MgO+H2O
Metal Chlorates → Metal Chloride + O₂
Example: 2KClO3→2KCl+3O22KClO_3 → 2KCl + 3O_22KClO3→2KCl+3O2
🔥 Practice Problem:
Predict the products of: H2O2→?H_2O_2 → ?H2O2→?
Definition: A more reactive element replaces a less reactive one in a compound.
General Formula: A + BC → B + AC
Activity Series (Memorize!):
💡 A metal higher on the series will replace a metal lower in a compound.
Most Reactive Metals: Li > K > Ca > Na > Mg > Al > Zn > Fe > Ni > Sn > Pb > H > Cu > Ag > Au
Most Reactive Halogens: F₂ > Cl₂ > Br₂ > I₂
🔥 Practice Problem:
Will this reaction occur?
Cu+HCl→?Cu + HCl → ?Cu+HCl→? (Use the activity series!)
Definition: Two ionic compounds swap ions to form two new compounds.
General Formula: AB + CD → AD + CB
💡 Reaction Occurs If:
✅ A precipitate (solid), gas, or water is formed.
✅ Use Solubility Rules to determine precipitates.
Soluble (Dissolves in Water):
Alkali metals (Na⁺, K⁺, Li⁺)
Nitrates (NO₃⁻), Acetates (C₂H₃O₂⁻), Ammonium (NH₄⁺)
Halides (except Ag⁺, Pb²⁺, Hg₂²⁺)
Sulfates (except Ba²⁺, Pb²⁺, Sr²⁺)
Insoluble (Forms a Precipitate):
Carbonates (CO₃²⁻), Phosphates (PO₄³⁻)
Hydroxides (OH⁻), except with Na⁺, K⁺, NH₄⁺
🔥 Practice Problem:
Predict the products & state whether a precipitate forms:
Na2SO4+BaCl2→?Na_2SO_4 + BaCl_2 → ?Na2SO4+BaCl2→?
Definition: A hydrocarbon reacts with oxygen to produce CO₂ + H₂O.
General Formula: CxHy + O₂ → CO₂ + H₂O
🔥 Practice Problem:
Balance the combustion of propane:
C3H8+O2→CO2+H2OC_3H_8 + O_2 → CO_2 + H_2OC3H8+O2→CO2+H2O
Shows only the reacting ions (removes spectator ions).
Steps to Determine Net Ionic Equation:
Write the balanced equation.
Break aqueous compounds into ions.
Cancel spectator ions.
Write the final net ionic equation.
Example:
Na2SO4+BaCl2→BaSO4(s)+2NaClNa_2SO_4 + BaCl_2 → BaSO_4 (s) + 2NaClNa2SO4+BaCl2→BaSO4(s)+2NaCl
Ionic: 2Na++SO42−+Ba2++2Cl−→BaSO4(s)+2Na++2Cl−2Na^+ + SO_4^{2-} + Ba^{2+} + 2Cl^- → BaSO_4 (s) + 2Na^+ + 2Cl^-2Na++SO42−+Ba2++2Cl−→BaSO4(s)+2Na++2Cl−
Net Ionic: Ba2++SO42−→BaSO4(s)Ba^{2+} + SO_4^{2-} → BaSO_4 (s)Ba2++SO42−→BaSO4(s)
Oxidation: Loss of electrons (LEO = Lose Electrons Oxidation)
Reduction: Gain of electrons (GER = Gain Electrons Reduction)
Pure elements: 0 (e.g., O₂, Na, Cl₂)
Ions: Charge of ion (e.g., Na⁺ = +1)
Oxygen: -2 (except peroxides: -1)
Hydrogen: +1 (except metal hydrides: -1)
Sum in neutral compound = 0, in polyatomic ion = charge of ion
Split into oxidation & reduction half-reactions.
Balance atoms except H & O.
Balance O using H₂O.
Balance H using H⁺ (acidic) or OH⁻ (basic).
Balance charge with electrons.
Multiply half-reactions to equalize electrons.
Add reactions together.
Example (Acidic Solution):
MnO4−+Fe2+→Mn2++Fe3+MnO_4^- + Fe^{2+} → Mn^{2+} + Fe^{3+}MnO4−+Fe2+→Mn2++Fe3+
Balanced:
MnO4−+8H++5Fe2+→Mn2++5Fe3++4H2OMnO_4^- + 8H^+ + 5Fe^{2+} → Mn^{2+} + 5Fe^{3+} + 4H_2OMnO4−+8H++5Fe2+→Mn2++5Fe3++4H2O
🔥 Practice Problem:
Balance in acidic solution:
Cr2O72−+Fe2+→Cr3++Fe3+Cr_2O_7^{2-} + Fe^{2+} → Cr^{3+} + Fe^{3+}Cr2O72−+Fe2+→Cr3++Fe3+