The power supplied by a battery is:
P = I \cdot V
The units of power are Joules per second (J/s) or Watts (W).
The power dissipated by a resistor is:
P = I^2 \cdot R
Or, in terms of the potential drop across the resistor:
P = \frac{V^2}{R}
Student Question: When asking about brightness, it's talking about power, right? But why on the last question of this week's practical it says the brightness only depends on the current I?
Student Question: So is the power how much energy it "gives" to the lightbulb?