Lesson 3 & 4: Molar Mass & Mass and Number of Entites
Molar mass is the mass of 1 mol of a substance
It could also be thought of as the mass of 6.02 x 10^23 entities
The unit symbol for molar mass is g/mol
The molar mass of elements is the atomic mass -- just change the unit to g/mol
If we had been talking about the mass of one atom then the unit from the periodic table would have been u (atomic mass unit)
Remember that a mol is 6.02 x 1023 entities. So if you know the amount (# of mols) then you can calculate the number of entities.
Mathematically: N (entities) = n (mol) x NA (entities/mol)
Example: a) Determine the number of formula units in 0.563 mol of calcium chloride
b) Determine the number of chloride ions in 0.563 mol of calcium chloride
Given:
n = 0.563 mol
NA = 6.02 x 10^23 ent/mol
N = ?
a)
N = n x NA
N = 0.563 mol x 6.02 x 10^23 fu/mol
N = 3.39 x 1023 fu
b) CaCl2
Every fu of CaCl2 has 2 ions of Cl
Ratio of CaCl2:Cl- is 1:2
NCl- = NCaCl2 x 2
NCl- = 3.39 x 1023 fu x 2 ions/fu
NCl- = 6.78 x 1023 ions of Cl
Molar mass is the mass of 1 mol of a substance
It could also be thought of as the mass of 6.02 x 10^23 entities
The unit symbol for molar mass is g/mol
The molar mass of elements is the atomic mass -- just change the unit to g/mol
If we had been talking about the mass of one atom then the unit from the periodic table would have been u (atomic mass unit)
Remember that a mol is 6.02 x 1023 entities. So if you know the amount (# of mols) then you can calculate the number of entities.
Mathematically: N (entities) = n (mol) x NA (entities/mol)
Example: a) Determine the number of formula units in 0.563 mol of calcium chloride
b) Determine the number of chloride ions in 0.563 mol of calcium chloride
Given:
n = 0.563 mol
NA = 6.02 x 10^23 ent/mol
N = ?
a)
N = n x NA
N = 0.563 mol x 6.02 x 10^23 fu/mol
N = 3.39 x 1023 fu
b) CaCl2
Every fu of CaCl2 has 2 ions of Cl
Ratio of CaCl2:Cl- is 1:2
NCl- = NCaCl2 x 2
NCl- = 3.39 x 1023 fu x 2 ions/fu
NCl- = 6.78 x 1023 ions of Cl