These are used to designate the amount of solute dissolved in a given quantity of solvent or quantity of solution.
In a solution, we have solute and solvent.
The solute is the one found in the smallest amount in the solution.
The solvent is the one found in the biggest amount in the solution.
Chemistry requires the concentration of solutions expressed quantitatively:
M = moles of solute / volume of solution in liters
m = moles of solute / kg of solvent
XX = moles of solute / total moles of solution
mass of solute / total mass of solution *100
volume of solute / total volume of solution *100
mass of solute (mg) / total mass of solution (Kg)
mass of solute (μg) / total mass of solution (Kg)
A solution is prepared by dissolving 4.35 g of glucose (C6H12O6) in 25,0 mL of water. Calculate the molality of glucose in the solution. Water has a density of 1,00 g/mL
m = moles of solute/ kg of solvent
Glucose’s molar mass → 180,15 g/mol
we need to transform 4,35 g into moles
4,35 g / 180,15g/mol = 0,02414 moles of glucose
we need to transform 25 mL into L to obtain Kg because L=Kg
25mL/1000mL = 0,025 L → 0,025 Kg
now we substitute our values in the formula
0,02414 moles of glucose / 0,025 Kg = 0,9656m