CHEM 99D: Introduction to Chemistry
CHEM 99D: Introduction to Chemistry
Basic Chemistry Concepts
Introduction to Key Elements:
Rutherfordium (Rf) - Atomic number 104
Dubnium (Db) - Atomic number 105
Seaborgium (Sg) - Atomic number 106
Technetium (Tc) - Atomic number 43
Rhenium (Re) - Atomic number 75
Bohrium (Bh) - Atomic number 107
Mass of Different Elements
Reaction Examples
Sodium Azide Reaction:
Chemical Reaction: 2 ext{NaN}3(s) ightarrow 2 ext{Na}(s) + 3 ext{N}2(g)
Airbags: This reaction is used to rapidly inflate airbags by releasing nitrogen gas (N2).
Calculation: If we start with 6.00 g of sodium azide (NaN3), calculate the grams of nitrogen gas (N2) produced.
Photosynthesis Equation:
Overall Reaction: 6 ext{CO}2 + 6 ext{H}2 ext{O}
ightarrow ext{C}6 ext{H}{12} ext{O}6 + 6 ext{O}2Calculation: Amount of glucose ($ ext{C}6 ext{H}{12} ext{O}6$) produced from 4.40 g of carbon dioxide ($ ext{CO}2$).
Phosphorus and Oxygen Reaction:
Reaction: ext{P} + 5 ext{O}2 ightarrow 2 ext{P}2 ext{O}_5
Objective: If we require 45.0 grams of $ ext{P}2 ext{O}5$, calculate grams of oxygen needed in excess phosphorus.
Xenon Tetrafluoride Reaction:
Reaction: ext{XeF}4 + 2 ext{H}2 ext{O}
ightarrow ext{Xe} + 4 ext{HF} + ext{O}_2Calculation: Determine the mass of xenon tetrafluoride ($ ext{XeF}_4$) necessary to react completely with 1.000 g of water.
Worked Example on Titanium Tetrachloride Preparation
Reaction: ext{TiO}2 (s) + 4 ext{C} (s) + 6 ext{Cl}2 (g)
ightarrow 3 ext{TiCl}4 (l) + 2 ext{CO}2 (g) + 2 ext{CO} (g)Parameters:
Amounts reacted: 2.3 grams of TiO2, 0.45 grams of carbon (C), and 4.3 grams of chlorine gas.
Density of TiCl4: 1.73 g/mL
Calculation: Find the yield of TiCl4 in mL based on the given quantities of reactants.
Yield Calculations
Definitions of Yield:
Theoretical Yield: The maximum product based on the limiting reactant.
Actual Yield: The amount of product that is actually formed. Influenced by incomplete reactions and lab techniques.
Percent Yield Formula: ext{Percent Yield} = rac{ ext{actual yield}}{ ext{theoretical yield}} imes 100
Example:
Theoretical yield: 22 g of $ ext{H}3 ext{PO}3$
Actual yield: 18 g of $ ext{H}3 ext{PO}3$
ext{Percent Yield} = rac{18 g}{22 g} imes 100 = 81.82 ext{ %}
Percent Excess:
Formula: ext{Percent Excess} = rac{ ext{amount leftover}}{ ext{amount used up}} imes 100
Calculation example: From 0.7 mol of water, 0.41 mol used, ext{Percent Excess} = rac{0.7 - 0.41}{0.41} imes 100 = 171 ext{%}
Chemical Reaction Problem Examples
Lead Compounds Reaction:
Reaction: ext{PbO}2 + ext{Pb} + 2 ext{H}2 ext{SO}4 ightarrow 2 ext{PbSO}4 + 2 ext{H}_2O
Calculation: Given 1.45 g of Pb, 1.93 g of PbO2, and 100 mL of 0.15 M H2SO4, find the grams of PbSO4 produced and percent yield if 1.7 g of PbSO4 is formed.
Hydrocarbon Combustion:
Given: Combine 43.0 g of propane ($ ext{C}3 ext{H}8$) with 54.0 g of oxygen, find grams of carbon dioxide ($ ext{CO}_2$) produced and starting materials remaining.
Additional Reaction Calculations:
Assess reactions related to specific masses given various reactants, such as generating products from reactions involving silicon, magnesium, lead compounds, and more.
Calculating Grams Precipitated
Mixing Criteria:
To calculate precipitate of lead(II) iodide ($ ext{PbI}2$) formed by mixing 25.0 mL of 0.150 M potassium iodide ($ ext{KI}$) with 15.0 mL of 0.175 M lead(II) nitrate ($ ext{Pb(NO}3 ext{)}_2$).
Practical Safety Measures in Chemistry
Mustard Gas Reaction:
Chemical Reaction: (HO-CH2CH2)2S + ext{PCl}3 ightarrow (Cl-CH2CH2)2S + ext{P(OH)}3
Context: Challenge regarding labeling all chemicals and its importance for safety in laboratory environments.
Calculation: How many liters and molecules of mustard gas can be formed from a specific volume of reactants with known densities:
Thiodiglycol: density of 1.22 g/cm3
Phosphorus trichloride: density 1.597 g/cm3