Statistics Lecture Review
Introduction
Overview of statistics application regarding a cereal company.
Importance of calculating specific statistics such as mean (XBAR) and standard deviation (s).
Finding Key Statistical Values
Concept of mean: XBAR is calculated from sample data.
Concept of standard deviation: s assists in understanding variability in data.
Example values presented:
XBAR = 14.05
s = 0.34
Hypothesis Testing Setup
Claims and Hypothesis
Claim regarding mean weight: The mean weight (mu) of the pack is at least 14 ounces.
Formulation of null hypothesis (H0): ( H_0: \mu = 14 )
Formulation of alternate hypothesis (H1): ( H_1: \mu < 14 )
Calculation of t-Score
Formula for t-score calculation:
[ t = \frac{\text{XBAR} - \mu}{s / \sqrt{n}} ]Substituting known values:
( t = \frac{14.05 - 14}{0.346 / \sqrt{8}} )
Computation results in ( t = 0.408 )
Statistical Significance
Level of significance set at ( \alpha = 0.01 )
Identification of test type: Left-tail test (since we're testing if the mean is less than a certain value).
Critical value for one-tailed test at 0.01 significance level: -2.998
Conclusion of the Test
Because the calculated t-score (0.408) is within the fail-to-reject region relative to -2.998:
Decision made: Fail to reject the null hypothesis.
Implication: Insufficient evidence to claim the mean is less than 14 ounces.
Understanding Different Hypothesis Tests
Types of Tests
Hypothesis Testing with Known Standard Deviation (σ):
Utilization of z-scores.
Formula: [ z = \frac{p_{hat} - p}{\sqrt{\frac{pq}{n}}} ]
Hypothesis Testing with Unknown Standard Deviation:
Utilizes t-scores as described above.
Hypothesis Testing for Proportions:
Important concepts include:
p_hat (sample proportion), p (population proportion), and q (1 - p).
Example of Proportion Testing
Problem scenario: University of Michigan believes that more than 600 students support online reprogramming.
Survey conducted on a sample of 200 students yielding 132 favorable responses.
Hypothesis setup:
Claim: ( p > 0.60 )
Null hypothesis: ( p = 0.60 )
Alternate hypothesis: ( p < 0.60 )
Calculation of Test Statistic for Proportions
Determination of p and p_hat:
p = 0.60 (the belief from the claim).
p_hat = ( \frac{132}{200} = 0.66 )
q would be ( 1 - 0.60 = 0.40 )
Plugging values into the proportion test formula yields:
[ z = \frac{0.66 - 0.60}{\sqrt{0.60 * 0.40 / 200}} ]
Reporting Test Findings
Test statistic calculated as ( 1.732 )
Comparing this z-score to table values to determine critical z-value for right-tail test at ( \alpha = 0.05 ): z critical = 1.645.
Conclusion: Since 1.732 > 1.645, we reject the null hypothesis, indicating supporting evidence for the claim that more than 60% support online programming.
Summary on Test Result Interpretation
Importance of carefully identifying null and alternate hypotheses.
Analysis of test statistics to ensure correct conclusion about the population based on sample data.
Notes on reviewing calculation steps to avoid errors.
Recommendations for further stat tests: past papers, and problem sets.
Homework Assignments and Review
Assignment of Chapter Practice Numbers to reinforce concepts discussed.
Example: Chapter 11 practice number three, focusing on hypothesis testing fundamentals.