Bronsted-Lowry acid-base theory
Acids are H+ donors.
Bases are H+ acceptors
Alkalis are soluble bases
Conjugate acid-base pairs
Conjugate acid-base pairs are related by the gain or loss of a proton.
e.g. NH4+ + NO3- → NH3+ HNO3
NH4+ (acid) and NH3 (base) are a conjugate acid-base pair.
NO3- (base) and HNO3 (acid) are also a conjugate acid-base pair.
Strong and weak acids and bases
Strong acids fully dissociate in solution.
General equation: HA → H+ + A-
E.g. HCl → H+ + Cl-
Strong bases also fully dissociate in water.
Weak acids partially dissociate in solution.
General equation: HA ⇋ H+ + A-
E.g. CH3COOH ⇋ H+ + CH3COO-
Weak bases also only partially dissociate in solution
pH
pH = -log[H+]
Negative logarithmic scale so that the lowest pH corresponds to the highest [H+].
The equation can be rearranged to find [H+]
[H+] = 10-pH
pH calculations for strong acids
Strong acids dissociate fully so for monoprotic acids [HA] = [H+], for diprotic acids 2[HA] = [H+]…
The concentration can be directly inserted into the pH equation to find pH.
pH of pure water
Pure water dissociates to a small extent. This can be represent by an equilibrium.
H2O ⇋ H+ + OH-
An Kc expression can be written for this equilibrium.
Kc = [H+][OH-]
[H2O] is constant so is not included.
This Kc is referred to as the equilibrium constant of water (Kw)
Kw = [H+][OH-]
Kw at 298K is 1.00 × 10-14 mol2dm-6 (given on the data sheet).
pH of strong bases
Strong bases full dissociate, so for monobasic bases [base] = [OH-], for dibasic bases 2[base] = [OH-]…
To calculate the pH of a strong base, Kw can be used to find the [H+]
Rearrange Kw expression: [H+] = Kw / [OH-]
Once the [H+] has been calculated it can be inserted into the pH equation to find pH.
pH of weak acids
Weak acids do not fully dissociate, so [HA] ≠ [H+]
Because the dissociation of weak acids is an equilibrium, we can define an equilibrium constant.
HA ⇋ H+ + A-
Kc = [H+][A-] / [HA]
This equilibrium constant is referred to as the acid dissociation constant (Ka)
Ka = [H+][A-] / [HA]
Because Ka values are usually so small, they are often converted to pKa values
pKa = -logKa
Ka = 10-pKa
2 assumptions are made when calculating the pH of a weak acid:
At equilibrium, the concentration of HA is effectively unchanged as so little dissociates, so [HA]initial = [HA]equilibrium
[H+] = [A-]
Ka formula can be rearranged so: [H+] = square root of (Ka x [HA])
Then pH can be calculated by inserting the [H+] into the pH equation
pH of mixing acids and bases
Identify which reactant is in excess
If acid, is it strong or weak
For strong acid, use concentration of excess H+
For weak acid, use Ka formula however [H+] ≠ [A-] in this case as HA will react with OH- to form some A-
If base use Kw formula