Concept is similar to adding half equations, half reactions for redox, and adding equations together when doing equilibria.
Anything on the same side adds up; anything on opposite sides cancels out (like canceling electrons in redox reactions).
The final reaction is provided as the target.
Reactions may need to be flipped to align with the target reaction.
Exothermic and Endothermic Reactions
Exothermic reaction in the forward direction implies the reverse direction is endothermic.
Exothermic (exo) has a negative \Delta H, while endothermic (endo) becomes positive when reversed.
Flipping the reaction changes the sign of \Delta H (positive becomes negative or vice versa).
Based upon the equation: Products - Reactants = \Delta H
If Products - Reactants is negative, products are smaller than reactants.
Flipping it makes Reactants - Products, resulting in a positive value.
Relates to equilibrium: products over reactants for K value, which is inverse of K when equation flips.
Coefficients
Coefficients in this context do not become exponents (unlike equilibrium calculations).
Coefficients are multiplied by the \Delta H value. If you double everything in a reaction, then you double the \Delta H value (energy for the reaction).
Doubling coefficients multiplies the heaps of formation, effectively doubling the number.
Focus on multiply and divide rather than square and root.
Flipping Equations
When flipping an equation, change the sign of \Delta H.
Example 1: Simple Reaction
The C2H6 needs to be on the right side, so flip the second reaction.
Flipping makes \Delta H positive: +1560 instead of -1560.
Calculate the final \Delta H by adding the individual \Delta H values together.
Example 2: More Complex Reaction
Check if components are on the correct sides first, then adjust numbers.
Flip the second equation to get NH3 on the left side, making \Delta H +91.8.
Multiply the first equation by two, doubling its \Delta H (to 361).
Multiply the bottom equation by three to get six waters.
Cancel out components (2 and 2, 6H2 and 6H2, etc).
Add up the three modified \Delta H values to get the final answer.
Hess's Law Problems
Hess' Law problems and thermochemical equations problems involve:
Calculating energy production based on grams of substance (like problem #7).
Textbook Problem 16
Given: one gram releases a certain number of kilojoules.
Given: 7.4 grams of ethanol.
Have conversion factor between grams of ethanol and kilojoules; solve for it like here (48.04).
248 o four
Know the delta t of both the water and the calorimeter.