Integration Methods to Know for AP Calculus AB/BC (AP)

What You Need to Know

Integration on AP Calc AB/BC is mostly about recognizing patterns and picking the right method fast. You’re not expected to invent clever antiderivatives from scratch—you’re expected to:

  • Use the Fundamental Theorem of Calculus to evaluate definite integrals.
  • Find antiderivatives with a small toolbox of techniques.
  • Handle definite integrals, improper integrals, and numerical integration correctly.

Core idea: an antiderivative of ff is a function FF such that F(x)=f(x)F'(x)=f(x), and

  • FTC Part 1 (accumulation): If g(x)=axf(t)dtg(x)=\int_a^x f(t)\,dt, then g(x)=f(x)g'(x)=f(x).
  • FTC Part 2 (evaluation): abf(x)dx=F(b)F(a)\int_a^b f(x)\,dx = F(b)-F(a) where F(x)=f(x)F'(x)=f(x).

When you choose a method:

  • If you see “inside function derivative nearby” → use uu-substitution.
  • If you see a product like polynomial ×\times trig/exp/log → try integration by parts.
  • If you see a rational function P(x)Q(x)\frac{P(x)}{Q(x)} → do long division and/or partial fractions.
  • If you see trig powers/products → use trig identities.
  • If it’s not integrable nicely (or asked explicitly) → use Trapezoidal/Simpson’s Rule.

Critical reminder: On FRQs, method + correct setup is often worth a lot even if algebra gets messy.

Step-by-Step Breakdown

1) uu-Substitution (Reverse Chain Rule)

Use when the integrand looks like f(g(x))g(x)f(g(x))g'(x).

  1. Choose u=g(x)u=g(x) (the “inside”).
  2. Compute du=g(x)dxdu=g'(x)\,dx.
  3. Rewrite the integral fully in uu.
  4. Integrate in uu.
  5. Substitute back u=g(x)u=g(x).
  6. If definite, either:
    • change bounds: u(a)=g(a)u(a)=g(a) and u(b)=g(b)u(b)=g(b) (cleanest), or
    • switch back to xx and then plug in.

Mini-example (indefinite):

  • 2xcos(x2)dx\int 2x\cos(x^2)\,dx
  • Let u=x2u=x^2, then du=2xdxdu=2x\,dx.
  • Integral becomes cos(u)du=sin(u)+C=sin(x2)+C\int \cos(u)\,du = \sin(u)+C = \sin(x^2)+C.
2) Integration by Parts

Use for products where substitution doesn’t cleanly work (especially involving lnx\ln x, inverse trig, polynomials with exe^x or trig).

Formula:
udv=uvvdu\int u\,dv = uv - \int v\,du

Steps:

  1. Pick uu (differentiate it) and dvdv (integrate it).
  2. Compute dudu and vv.
  3. Plug into udv=uvvdu\int u\,dv = uv - \int v\,du.
  4. Simplify; sometimes you’ll need to do it twice (common with trig ×\times trig).
  5. If the original integral reappears, solve algebraically.

Mini-example:

  • xexdx\int x e^x\,dx
  • Choose u=xu=x, dv=exdxdv=e^x\,dx. Then du=dxdu=dx, v=exv=e^x.
  • xexdx=xexexdx=xexex+C=ex(x1)+C\int x e^x\,dx = x e^x - \int e^x\,dx = x e^x - e^x + C = e^x(x-1)+C.
3) Rational Functions: Long Division + Partial Fractions (BC-heavy)

When integrating P(x)Q(x)\frac{P(x)}{Q(x)}.

Step A: Long division first if needed

  1. If deg(P)deg(Q)\deg(P)\ge \deg(Q), do polynomial long division:
    P(x)Q(x)=S(x)+R(x)Q(x)\frac{P(x)}{Q(x)} = S(x) + \frac{R(x)}{Q(x)}
  2. Integrate S(x)S(x) easily, then focus on proper fraction R(x)Q(x)\frac{R(x)}{Q(x)}.

Step B: Partial fractions (for proper rational functions)

  1. Factor the denominator Q(x)Q(x) completely (over reals).
  2. Set up the decomposition based on factor types:
    • Distinct linear: Axa\frac{A}{x-a}
    • Repeated linear: A1xa+A2(xa)2+\frac{A_1}{x-a}+\frac{A_2}{(x-a)^2}+\cdots
    • Irreducible quadratic: Ax+Bx2+px+q\frac{Ax+B}{x^2+px+q}
    • Repeated irreducible quadratic: stack powers similarly.
  3. Solve for constants (plug values or match coefficients).
  4. Integrate term-by-term.

Mini-example (distinct linears):

  • 1x21dx=1(x1)(x+1)dx\int \frac{1}{x^2-1}\,dx = \int \frac{1}{(x-1)(x+1)}\,dx
  • 1(x1)(x+1)=Ax1+Bx+1\frac{1}{(x-1)(x+1)}=\frac{A}{x-1}+\frac{B}{x+1}
  • Solve: 1=A(x+1)+B(x1)1=A(x+1)+B(x-1) gives A=12A=\frac{1}{2}, B=12B=-\frac{1}{2}.
  • Integral: 12lnx112lnx+1+C=12lnx1x+1+C\frac{1}{2}\ln|x-1| - \frac{1}{2}\ln|x+1| + C = \frac{1}{2}\ln\left|\frac{x-1}{x+1}\right|+C.
4) Trig Integrals via Identities (not “trig substitution”)

Common AP patterns:

A) Powers of sinx\sin x and cosx\cos x

  1. If one power is odd, peel off one factor and convert the rest using:
    sin2x=1cos2xorcos2x=1sin2x\sin^2 x = 1-\cos^2 x \quad \text{or} \quad \cos^2 x = 1-\sin^2 x
  2. If both are even, use half-angle identities:
    sin2x=1cos(2x)2,cos2x=1+cos(2x)2\sin^2 x = \frac{1-\cos(2x)}{2},\quad \cos^2 x = \frac{1+\cos(2x)}{2}

B) Powers of tanx\tan x and secx\sec x

  • If sec2x\sec^2 x is present, let u=tanxu=\tan x.
  • If secxtanx\sec x\tan x is present, let u=secxu=\sec x.
  • Use identities:
    1+tan2x=sec2x,sec2x1=tan2x1+\tan^2 x = \sec^2 x,\quad \sec^2 x-1=\tan^2 x
5) Improper Integrals (limits)

You have an improper integral if:

  • infinite limit: af(x)dx\int_a^{\infty} f(x)\,dx or bf(x)dx\int_{-\infty}^b f(x)\,dx
  • vertical asymptote/discontinuity in interval, e.g. ab1xcdx\int_a^b \frac{1}{x-c}\,dx with c[a,b]c\in[a,b]

Steps:

  1. Rewrite as a limit:
    af(x)dx=limtatf(x)dx\int_a^{\infty} f(x)\,dx = \lim_{t\to\infty}\int_a^t f(x)\,dx
  2. Evaluate the antiderivative and take the limit.
  3. If the limit is finite → converges; otherwise diverges.
6) Numerical Integration (Calculator-friendly)

If you’re given a table of values or asked to approximate:

Trapezoidal Rule (works on any partition):

  1. Partition [a,b][a,b] into nn equal subintervals of width Δx=ban\Delta x = \frac{b-a}{n}.
  2. Apply:
    Tn=Δx2[f(x0)+2f(x1)+2f(x2)++2f(xn1)+f(xn)]T_n = \frac{\Delta x}{2}\left[f(x_0)+2f(x_1)+2f(x_2)+\cdots+2f(x_{n-1})+f(x_n)\right]

Simpson’s Rule (requires even nn):

  1. Use even number of subintervals nn.
  2. Apply:
    Sn=Δx3[f(x0)+4f(x1)+2f(x2)+4f(x3)++2f(xn2)+4f(xn1)+f(xn)]S_n = \frac{\Delta x}{3}\left[f(x_0)+4f(x_1)+2f(x_2)+4f(x_3)+\cdots+2f(x_{n-2})+4f(x_{n-1})+f(x_n)\right]

If the problem gives unequal subintervals, Simpson’s Rule usually does not apply; Trapezoidal still can.

Key Formulas, Rules & Facts

Integration method “trigger table”
MethodWhat you seeTemplate / Key moveNotes
Basic antiderivativesstandard formsxndx=xn+1n+1+C\int x^n\,dx=\frac{x^{n+1}}{n+1}+C for n1n\ne -1Don’t forget constant CC for indefinite integrals
Log rule1x\frac{1}{x}1xdx=lnx+C\int \frac{1}{x}\,dx = \ln|x|+CAlso: f(x)f(x)dx=lnf(x)+C\int \frac{f'(x)}{f(x)}\,dx=\ln|f(x)|+C
Exponentialsekxe^{kx} or akxa^{kx}ekxdx=1kekx+C\int e^{kx}\,dx=\frac{1}{k}e^{kx}+C; akxdx=1klnaakx+C\int a^{kx}\,dx=\frac{1}{k\ln a}a^{kx}+CWatch the 1k\frac{1}{k} factor
uu-sub“inside + derivative”Let u=g(x)u=g(x)For definite integrals, changing bounds prevents back-sub errors
By partsproduct (esp. poly ×\times trig/exp/log)udv=uvvdu\int u\,dv=uv-\int v\,duChoose uu using LIATE as a heuristic
Trig identitiespowers/products of triguse sin2x,cos2x\sin^2x,\cos^2x half-angle; or peel odd powerConvert to substitution-friendly form
Rational functionsP(x)Q(x)\frac{P(x)}{Q(x)}Long division if needed; then partial fractionsBC loves these
Partial fractionsfactored denominatorsums of linear/quadratic termsIrreducible quadratic gives arctan-type or log after completing square
Improper integrals\infty bounds or discontinuityrewrite as a limitConvergence is a must-mention
Symmetryinterval [a,a][-a,a]even: 20a2\int_0^a; odd: 00Only works if integrand is even/odd and integral is proper
Numericaltable/approx promptTnT_n or SnS_nSimpson requires even nn
Handy trig/identity list (high-yield)
  • Pythagorean:
    sin2x+cos2x=1\sin^2 x+\cos^2 x=1
    1+tan2x=sec2x1+\tan^2 x=\sec^2 x
    1+cot2x=csc2x1+\cot^2 x=\csc^2 x
  • Half-angle:
    sin2x=1cos(2x)2,cos2x=1+cos(2x)2\sin^2 x=\frac{1-\cos(2x)}{2},\quad \cos^2 x=\frac{1+\cos(2x)}{2}
  • Basic trig antiderivatives:
    cosxdx=sinx+C\int \cos x\,dx=\sin x + C
    sinxdx=cosx+C\int \sin x\,dx=-\cos x + C
    sec2xdx=tanx+C\int \sec^2 x\,dx=\tan x + C
    csc2xdx=cotx+C\int \csc^2 x\,dx=-\cot x + C
    secxtanxdx=secx+C\int \sec x\tan x\,dx=\sec x + C
    cscxcotxdx=cscx+C\int \csc x\cot x\,dx=-\csc x + C
Definite integral properties you actually use
  • Linearity:
    ab(cf+g)=cabf+abg\int_a^b (cf+g)=c\int_a^b f + \int_a^b g
  • Reversal:
    abf(x)dx=baf(x)dx\int_a^b f(x)\,dx = -\int_b^a f(x)\,dx
  • Additivity:
    abf=acf+cbf\int_a^b f = \int_a^c f + \int_c^b f
  • Symmetry on [a,a][-a,a]:
    • If ff is even: aaf(x)dx=20af(x)dx\int_{-a}^a f(x)\,dx = 2\int_0^a f(x)\,dx
    • If ff is odd: aaf(x)dx=0\int_{-a}^a f(x)\,dx = 0

Examples & Applications

Example 1: Definite integral with uu-sub (change bounds)

Compute 016x(3x2+2)4dx\int_0^1 6x(3x^2+2)^4\,dx.

  • Let u=3x2+2u=3x^2+2, so du=6xdxdu=6x\,dx.
  • Change bounds: when x=0x=0, u=2u=2; when x=1x=1, u=5u=5.
  • Then 016x(3x2+2)4dx=25u4du=u5525=55255\int_0^1 6x(3x^2+2)^4\,dx = \int_2^5 u^4\,du = \left.\frac{u^5}{5}\right|_2^5 = \frac{5^5-2^5}{5}.

Key exam insight: changing bounds avoids back-sub and is often cleaner.

Example 2: By parts with lnx\ln x (classic)

Compute lnxdx\int \ln x\,dx.

  • Write lnxdx=1lnxdx\int \ln x\,dx = \int 1\cdot \ln x\,dx.
  • Choose u=lnxu=\ln x, dv=dxdv=dx. Then du=1xdxdu=\frac{1}{x}dx, v=xv=x.
  • lnxdx=xlnxx1xdx=xlnx1dx=xlnxx+C\int \ln x\,dx = x\ln x - \int x\cdot \frac{1}{x}\,dx = x\ln x - \int 1\,dx = x\ln x - x + C.

Key exam insight: inverse trig and logs almost always scream “parts.”

Example 3: Partial fractions with repeated factor

Compute 1x(x1)2dx\int \frac{1}{x(x-1)^2}\,dx.

  • Setup:
    1x(x1)2=Ax+Bx1+C(x1)2\frac{1}{x(x-1)^2}=\frac{A}{x}+\frac{B}{x-1}+\frac{C}{(x-1)^2}
  • Multiply through by x(x1)2x(x-1)^2:
    1=A(x1)2+Bx(x1)+Cx1=A(x-1)^2+Bx(x-1)+Cx
  • Plug convenient values:
    • x=0x=0: 1=A(1)A=11=A(1)\Rightarrow A=1
    • x=1x=1: 1=CC=11=C\Rightarrow C=1
  • Use another value (say x=2x=2):
    1=112+B21+121=1+2B+2B=11=1\cdot 1^2 + B\cdot 2\cdot 1 + 1\cdot 2 \Rightarrow 1=1+2B+2 \Rightarrow B=-1
  • Integrate:
    (1x1x1+1(x1)2)dx=lnxlnx11x1+C\int \left(\frac{1}{x}-\frac{1}{x-1}+\frac{1}{(x-1)^2}\right)dx = \ln|x| - \ln|x-1| - \frac{1}{x-1}+C

Key exam insight: repeated factors require a whole stack of terms.

Example 4: Trig power integral

Compute sin3xdx\int \sin^3 x\,dx.

  • Peel off one sinx\sin x:
    sin3xdx=sin2xsinxdx=(1cos2x)sinxdx\int \sin^3 x\,dx = \int \sin^2 x\sin x\,dx = \int (1-\cos^2 x)\sin x\,dx
  • Let u=cosxu=\cos x, du=sinxdxdu=-\sin x\,dx.
  • Integral becomes:
    (1u2)du=(uu33)+C=cosx+cos3x3+C-\int (1-u^2)\,du = -\left(u-\frac{u^3}{3}\right)+C = -\cos x + \frac{\cos^3 x}{3}+C

Key exam insight: odd power of sin\sin or cos\cos usually means “save one, convert the rest.”

Common Mistakes & Traps

  1. Forgetting dudu (or not matching it)

    • Wrong: letting u=g(x)u=g(x) but not converting dxdx terms correctly.
    • Fix: after substitution, the integral must be entirely in uu (including dudu).
  2. Not changing bounds on definite uu-sub (then mixing variables)

    • Wrong: switching to uu but still plugging in x=a,bx=a,b.
    • Fix: either change bounds to u(a),u(b)u(a),u(b) or revert back to xx before evaluating.
  3. Dropping absolute values in log answers

    • Wrong: writing ln(x)\ln(x) instead of lnx\ln|x|.
    • Fix: for indefinite integrals, default to ln\ln|\cdot| unless domain is explicitly restricted.
  4. Using integration by parts when uu-sub is simpler (or vice versa)

    • Wrong: forcing parts on something like 2xcos(x2)dx\int 2x\cos(x^2)dx.
    • Fix: always check for inside-derivative structure first.
  5. Skipping long division before partial fractions

    • Wrong: trying PF when deg(P)deg(Q)\deg(P)\ge\deg(Q).
    • Fix: divide first; PF only applies cleanly to proper rational functions.
  6. Incorrect partial fraction form (especially repeats/quadratics)

    • Wrong: for 1(x1)2\frac{1}{(x-1)^2} writing only Ax1\frac{A}{x-1}.
    • Fix: repeated linear factors require A1xa+A2(xa)2+\frac{A_1}{x-a}+\frac{A_2}{(x-a)^2}+\cdots; irreducible quadratics need Ax+BAx+B on top.
  7. Simpson’s Rule with odd nn or unequal spacing

    • Wrong: applying Simpson when nn is odd or the table step size changes.
    • Fix: Simpson requires equal spacing and even nn. Otherwise use trapezoids.
  8. Improper integrals: evaluating at the asymptote instead of using limits

    • Wrong: plugging in the discontinuity like it’s a normal endpoint.
    • Fix: rewrite with a limit; you must state convergence/divergence.

Memory Aids & Quick Tricks

Trick / mnemonicWhat it helps you rememberWhen to use it
“Inside + derivative” checkSpot uu-sub quicklyComposite functions like sin(x2)\sin(\,x^2\,) with 2x2x nearby
LIATE (Log, Inverse trig, Algebra, Trig, Exponential)Heuristic for choosing uu in partsProducts that suggest by parts
“Divide then decompose”Long division before partial fractionsRational integrals with big numerator degree
Odd-even trig ruleOdd power → peel one; even-even → half-anglesinmxcosnxdx\int \sin^m x\cos^n x\,dx
“Simpson = 1-4-2-4-…-1”Coefficient pattern in Simpson’s RuleNumerical integration with even nn
Even/odd symmetrySave time on [a,a][-a,a]Definite integrals over symmetric intervals

Quick Review Checklist

  • You can apply FTC: find FF then compute F(b)F(a)F(b)-F(a).
  • You can spot and execute uu-sub, including changing bounds for definite integrals.
  • You know integration by parts and can pick uu using LIATE.
  • You can integrate rational functions: long division first, then partial fractions.
  • You can set up partial fractions for distinct/repeated linear and irreducible quadratic factors.
  • You can handle trig power integrals using identities (odd/even strategy).
  • You can evaluate improper integrals using limits and state converge/diverge.
  • You can approximate with Trapezoidal and Simpson’s Rule (and know Simpson needs even nn).

You’ve got enough tools—your job is just picking the right one quickly and executing cleanly.