Scalar and Vector Quantities Flashcards
Scalar & Vector Quantities
Scalar Quantities
A scalar is any quantity that has a magnitude but no specified direction.
A scalar quantity can be negative; the minus sign indicates a point on a scale.
Examples of scalar quantities:
A person's height of 1.8 m
1698 kJ of energy per 100 g of sugar
A speed limit of 120 km/h
An average winter temperature of -10ºC in Russia
Vector Quantities
A vector is any quantity with both magnitude and direction.
Examples of vector quantities:
The direction of a vector in one-dimensional motion is given by a plus (+) or minus (−) sign.
Graphically, vectors are drawn as arrows.
An arrow has both a magnitude (length) and a direction (the direction in which the tip is pointing).
Examples:
+3 m east
−2 m west
−1 m west
Vector Examples in 2-D
A = 2.8 km, 45° North of the East axis
B = 3.2 km, 22.5° East of the South axis
C = 2.8 km, 45° North of the East axis
The magnitude is calculated as ((x)2+(y)2).
Examples with coordinates:
Quadrants:
Vector Addition
To add vectors graphically, they must be placed tip to tail.
The resultant vector points from the tail of the 1st vector to the tip of the 2nd vector.
If the direction toward the right is considered positive (+) and left as negative (-).
Resultant vector is the sum of vectors, e.g., 100N=400N+(−300N).
Example: Walking 5m East, 8m North, then 3m West results in a position 8m North and 2m East of the starting point.
The diagonal vector connecting the starting position with the final position is called the resultant vector.
Tip-to-tail technique of vector addition.
Distance, Distance Travelled, & Displacement
Distance is defined as the magnitude or size of displacement between two positions.
Distance travelled is the total length of the path covered between two positions.
Displacement is the change in position relative to a reference point.
∆𝑥 = 𝑥𝑓 − 𝑥𝑖
where ∆𝑥isthedisplacement,and𝑥𝑓and𝑥𝑖arefinalandinitialpositions,respectively.</p></li><li><p>Positioniswheretheobjectisatanyparticulartimewithrespecttoareferencepoint.</p></li></ul><h4id="c6859b99−47ff−481f−9055−ccdc093ee786"data−toc−id="c6859b99−47ff−481f−9055−ccdc093ee786"collapsed="false"seolevelmigrated="true">Example1</h4><ul><li><p>Scenario:Runningfromhometoashopthatis3kmawayandreturninghomein45minutes.</p></li><li><p>Referencepoint:Home</p></li><li><p>(a)Distancetraveledanddisplacementwhileattheshop:</p><ul><li><p>Distancetraveled:3km</p></li><li><p>Distance:3km</p></li><li><p>Displacement:3kmEast</p></li></ul></li><li><p>(b)Distancetravelledanddisplacementafterreturninghome:</p><ul><li><p>Distancetravelled:6km(totaldistancecovered)</p></li><li><p>Distance:0km</p></li><li><p>Displacement:0km(sincethefinalandinitialpositionsarethesame)</p></li></ul></li><li><p>Note:Distancebetweentwopositionsisnotthesameasthedistancetravelledbetweenthem.</p></li></ul><h4id="244ea5bf−d82e−4c9a−ad07−cd0604a6dee8"data−toc−id="244ea5bf−d82e−4c9a−ad07−cd0604a6dee8"collapsed="false"seolevelmigrated="true">Example2</h4><ul><li><p>Anantwalks2metersWest,3metersNorth,and6metersEast.</p></li><li><p>Referencepoint:(0;0)</p></li><li><p>X1=(−2;0)m,X2=(0;3)mandX3=(6;0)m</p></li><li><p>(a)Thenewpositionofanant:</p><ul><li><p>𝑿𝟏 + 𝑿𝟐 + 𝑿𝟑 = (-2 + 0 + 6, 0 + 3 + 0) m = (4; 3) m</p></li><li><p>Thenewpositionis4meterEastand3meterNorth.</p></li></ul></li><li><p>(b)Thedisplacementoftheant:</p><ul><li><p>\sqrt{(4)^2+(3)^2} = 5 m$$
5 m North of the East