A scalar is any quantity that has a magnitude but no specified direction.
A scalar quantity can be negative; the minus sign indicates a point on a scale.
Examples of scalar quantities:
A person's height of 1.8 m
1698 kJ of energy per 100 g of sugar
A speed limit of 120 km/h
An average winter temperature of -10ºC in Russia
A vector is any quantity with both magnitude and direction.
Examples of vector quantities:
A velocity of 90 km/h east
A force of 500 newtons north
The direction of a vector in one-dimensional motion is given by a plus (+) or minus (−) sign.
Graphically, vectors are drawn as arrows.
An arrow has both a magnitude (length) and a direction (the direction in which the tip is pointing).
Examples:
+3 m east
−2 m west
−1 m west
A = 2.8 km, 45° North of the East axis
B = 3.2 km, 22.5° East of the South axis
C = 2.8 km, 45° North of the East axis
The magnitude is calculated as (\sqrt{(𝑥)^2+(𝑦)^2}).
Examples with coordinates:
(2;2)
(1;-3)
(2;2)
Quadrants:
(+) (+)
(-) (-)
To add vectors graphically, they must be placed tip to tail.
The resultant vector points from the tail of the 1st vector to the tip of the 2nd vector.
If the direction toward the right is considered positive (+) and left as negative (-).
Resultant vector is the sum of vectors, e.g., 100N = 400N + (-300N).
Example: Walking 5m East, 8m North, then 3m West results in a position 8m North and 2m East of the starting point.
The diagonal vector connecting the starting position with the final position is called the resultant vector.
Tip-to-tail technique of vector addition.
Distance is defined as the magnitude or size of displacement between two positions.
Distance travelled is the total length of the path covered between two positions.
Displacement is the change in position relative to a reference point.
∆𝑥 = 𝑥𝑓 − 𝑥𝑖
where ∆𝑥 is the displacement, and 𝑥𝑓 and 𝑥𝑖 are final and initial positions, respectively.
Position is where the object is at any particular time with respect to a reference point.
Scenario: Running from home to a shop that is 3km away and returning home in 45 minutes.
Reference point: Home
(a) Distance traveled and displacement while at the shop:
Distance traveled: 3 km
Distance: 3 km
Displacement: 3 km East
(b) Distance travelled and displacement after returning home:
Distance travelled: 6 km (total distance covered)
Distance: 0 km
Displacement: 0 km (since the final and initial positions are the same)
Note: Distance between two positions is not the same as the distance travelled between them.
An ant walks 2 meters West, 3 meters North, and 6 meters East.
Reference point: (0;0)
X1 = (-2;0) m, X2 = (0;3) m and X3 = (6;0) m
(a) The new position of an ant:
𝑿𝟏 + 𝑿𝟐 + 𝑿𝟑 = (-2 + 0 + 6, 0 + 3 + 0) m = (4; 3) m
The new position is 4 meter East and 3 meter North.
(b) The displacement of the ant:
\sqrt{(4)^2+(3)^2} = 5 m$$
5 m North of the East