Review of Quadratic Functions and Graphs
Unit 2: Understanding Parabolas and Quadratic Functions
Writing Vertex Form Equations of Parabolas
1. Equation: y = x² + 16x + 71
Transformations:
Complete the square to rewrite in vertex form.
The vertex form is given by:
y = a(x-h)² + k
where (h, k) is the vertex.
Vertex Calculation:
To complete the square, use the formula: h = -\frac{b}{2a}, here, b = 16 and a = 1.
Thus, h = -\frac{16}{2(1)} = -8.
Substitute back to find k:
k = (-8)^2 + 16(-8) + 71 = 71 - 128 + 64 = 7.Vertex: (-8, 7)
Axis of Symmetry:
Line of symmetry: x = -8
2. Equation: y = x² - 2x - 5
Transformations:
Complete the square.
Vertex Calculation:
h = -\frac{-2}{2(1)} = 1.
Substitute back:
k = (1)^2 - 2(1) - 5 = 1 - 2 - 5 = -6.Vertex: (1, -6)
Axis of Symmetry:
Line of symmetry: x = 1
3. Equation: y = -x² - 14x - 59
Transformations:
Complete the square.
Vertex Calculation:
h = -\frac{-14}{2(-1)} = -7.
Substitute back:
k = -(-7)² - 14(-7) - 59 = -49 + 98 - 59 = -10.Vertex: (-7, -10)
Axis of Symmetry:
Line of symmetry: x = -7
4. Equation: y = 2x² + 36x + 170
Transformations:
Complete the square.
Vertex Calculation:
h = -\frac{36}{2(2)} = -9.
Substitute back:
k = 2(-9)² + 36(-9) + 170 = 162 - 324 + 170 = 8.Vertex: (-9, 8)
Axis of Symmetry:
Line of symmetry: x = -9
Sketching the Graph
For each parabola, visualize the U-shape where:
If a > 0, the parabola opens upwards.
If a < 0, it opens downwards.
Locate and plot the vertex and draw the axis of symmetry accordingly.
Factorization
Factor the following polynomials:
Polynomial: 2x² - 5x - 3
To factor: Look for two numbers that multiply to: 2 * (-3) = -6 and add to: -5.
Factors: 2x + 1 and x - 3.
Factored form: (2x + 1)(x - 3).
Polynomial: 3x² + 10x - 8
Find numbers that multiply to: 3 * (-8) = -24 and add to: 10.
Factors: 12 and -2.
Factored form: (3x - 2)(x + 4).
Polynomial: 2n² - 3n - 14
To factor: Numbers that multiply to: 2 * (-14) = -28 and add to: -3.
Factored form: (2n + 7)(n - 2).
Polynomial: 5n² + 2n + 7
This polynomial is prime as it has no real roots.
Motion and Height Functions
Jason’s Cliff Jumping Scenario
Function: h(t) = -16t² + 16t + 480
Maximum Height Time Calculation:
Time to max height: t = -\frac{b}{2a} = -\frac{16}{2(-16)} = 0.5 seconds.
Maximum Height:
Substitute into h(t):
h(0.5) = -16(0.5)² + 16(0.5) + 480 = 4 + 8 + 480 = 492 feet.
Total Time to Hit Water:
Find roots of h(t) = 0; set -16t² + 16t + 480 = 0.
Use the quadratic formula:
t = \frac{-b ± \sqrt{b² - 4ac}}{2a} gives the time it takes to hit the water.Roots are calculated as follows.
Grappling Hook Release
Function: h(t) = -16t² + 32t + 5
Maximum Height Calculation:
Time to max height:
t = -\frac{32}{2(-16)} = 1 second.Substitute t = 1 into h(t):
h(1) = -16(1)² + 32(1) + 5 = 21 feet.
Ledge Height Comparison:
Compare height of hook (21 feet) to ledge height (20 feet): Yes, you can reach the ledge.
Solving Quadratic Equations
Solve by Factoring:
Equation: x² - 8x + 16 = 0
This factors to (x - 4)(x - 4) = 0.
Thus, the solution is: x = 4.
Solve by Taking Square Roots:
Equation: -8 - 5n² = -88
Rearranging gives: 5n² = 80, leading to n² = 16.
Solutions: n = ±4.
Solve using the Quadratic Formula:
Equation: 4v² + 7v - 7 = 0
Using quadratic formula:
v = \frac{-7 ± \sqrt{(7)² - 4(4)(-7)}}{2(4)}.Thus, calculate the discriminant and continue solving.
Equation: 2n² - 18n + 40 = 0
Use quadratic formula as above.
Equation: 4 - 2a² = -7
Rearrange to standard form before applying the quadratic formula.
Equation: -8b² - 3b + 22 = 0
Apply quadratic formula to solve for b.