Lecture 6
An indefinite integral represents a family of functions and is denoted mathematically as:
[ \int f(x) , dx + C = F(x) ]
Where:
F(x): Represents the antiderivative of f(x).
C: A constant representing that there are infinitely many antiderivatives, differing by constant values.
Therefore, ( F'(x) = f(x) ) indicates the relationship of differentiation to the integral.
The definite integral of a function f(x) over the interval [a, b] gives the net area between the function and the x-axis and is expressed as:
[ \int_{a}^{b} f(x) , dx = F(b) - F(a) ]
This calculation uses the Fundamental Theorem of Calculus, showing the relationship between differentiation and integration.
A uniform probability distribution describes a situation where all outcomes are equally likely, resulting in a constant probability across a defined range.
Let's consider the scenario of a salad quantity taken by customers, which is uniformly distributed between 5 oz and 15 oz.
To find the probability of a customer taking between 12 oz and 15 oz, calculate the area under the probability density function (pdf) for this interval:
[ P(12 < X < 15) = \int_{12}^{15} f(x) , dx = \frac{3}{10} = 0.3 ]
Where:
X: Represents the random variable of salad quantity.
f(x): The probability density function across the defined range.
In this uniform distribution scenario:
The normal distribution, often referred to as the Gaussian distribution, is a fundamental concept in probability and statistics, frequently encountered in various statistical analyses and natural phenomena.
Mean (μ): The average of the distribution, determining its center.
Standard Deviation (σ): Measures the spread or dispersion of the distribution around the mean.
The formula for the normal distribution is: [ f(x) = \frac{1}{\sigma \sqrt{2\pi}} e^{-\frac{(x - \mu)^2}{2\sigma^2}} ] Where:
e: The base of the natural logarithm (approximately equal to 2.71828).
x: The variable for which the probability is being calculated.
The total area under the curve equals 1, confirming that the sum of probabilities of all outcomes is complete.
The mean, median, and mode are all equal in a normal distribution, signifying its symmetry.
Approximately 68.26% of data falls within one standard deviation (μ ± σ).
About 95.44% falls within two standard deviations (μ ± 2σ).
Nearly 99.72% lies within three standard deviations (μ ± 3σ).
Assuming demand for a product is normally distributed with a mean of 15 gallons and a standard deviation of 6 gallons, we seek the probability of a stockout when the stock is 20 gallons.
Convert to z-score using the formula: [ z = \frac{x - \mu}{\sigma} = \frac{20 - 15}{6} = 0.83 ]
Find [ P(z \leq 0.83) = 0.7967 ]
The probability of stockout is therefore: [ 1 - P(z \leq 0.83) = 0.2033 ]
The exponential probability distribution is mainly used for modeling the time until an event occurs, such as the waiting time before a Poisson process. The mean and standard deviation are equal in this distribution, creating a significant relationship between these two measures.
The probability density function is expressed as: [ f(x) = \frac{1}{\mu} e^{-\frac{x}{\mu}} ] Where:
μ: The mean or expected value of the distribution.
The cumulative distribution function is given by: [ P(X \leq x) = 1 - e^{-\frac{x}{\mu}} ]
Consider Al’s establishment, which experiences an average mean time of 3 minutes between customer arrivals.
To find the probability that a car arrives in 2 minutes or less, use the cumulative function to determine the corresponding threshold for this scenario.
To find the time after which the probability of arrival equals 0.6, solve: [ P(X \leq x) = 0.6 ] resulting in [ x = 2.75 ] minutes.
An indefinite integral represents a family of functions and is denoted mathematically as:
[ \int f(x) , dx + C = F(x) ]
Where:
F(x): Represents the antiderivative of f(x).
C: A constant representing that there are infinitely many antiderivatives, differing by constant values.
Therefore, ( F'(x) = f(x) ) indicates the relationship of differentiation to the integral.
The definite integral of a function f(x) over the interval [a, b] gives the net area between the function and the x-axis and is expressed as:
[ \int_{a}^{b} f(x) , dx = F(b) - F(a) ]
This calculation uses the Fundamental Theorem of Calculus, showing the relationship between differentiation and integration.
A uniform probability distribution describes a situation where all outcomes are equally likely, resulting in a constant probability across a defined range.
Let's consider the scenario of a salad quantity taken by customers, which is uniformly distributed between 5 oz and 15 oz.
To find the probability of a customer taking between 12 oz and 15 oz, calculate the area under the probability density function (pdf) for this interval:
[ P(12 < X < 15) = \int_{12}^{15} f(x) , dx = \frac{3}{10} = 0.3 ]
Where:
X: Represents the random variable of salad quantity.
f(x): The probability density function across the defined range.
In this uniform distribution scenario:
The normal distribution, often referred to as the Gaussian distribution, is a fundamental concept in probability and statistics, frequently encountered in various statistical analyses and natural phenomena.
Mean (μ): The average of the distribution, determining its center.
Standard Deviation (σ): Measures the spread or dispersion of the distribution around the mean.
The formula for the normal distribution is: [ f(x) = \frac{1}{\sigma \sqrt{2\pi}} e^{-\frac{(x - \mu)^2}{2\sigma^2}} ] Where:
e: The base of the natural logarithm (approximately equal to 2.71828).
x: The variable for which the probability is being calculated.
The total area under the curve equals 1, confirming that the sum of probabilities of all outcomes is complete.
The mean, median, and mode are all equal in a normal distribution, signifying its symmetry.
Approximately 68.26% of data falls within one standard deviation (μ ± σ).
About 95.44% falls within two standard deviations (μ ± 2σ).
Nearly 99.72% lies within three standard deviations (μ ± 3σ).
Assuming demand for a product is normally distributed with a mean of 15 gallons and a standard deviation of 6 gallons, we seek the probability of a stockout when the stock is 20 gallons.
Convert to z-score using the formula: [ z = \frac{x - \mu}{\sigma} = \frac{20 - 15}{6} = 0.83 ]
Find [ P(z \leq 0.83) = 0.7967 ]
The probability of stockout is therefore: [ 1 - P(z \leq 0.83) = 0.2033 ]
The exponential probability distribution is mainly used for modeling the time until an event occurs, such as the waiting time before a Poisson process. The mean and standard deviation are equal in this distribution, creating a significant relationship between these two measures.
The probability density function is expressed as: [ f(x) = \frac{1}{\mu} e^{-\frac{x}{\mu}} ] Where:
μ: The mean or expected value of the distribution.
The cumulative distribution function is given by: [ P(X \leq x) = 1 - e^{-\frac{x}{\mu}} ]
Consider Al’s establishment, which experiences an average mean time of 3 minutes between customer arrivals.
To find the probability that a car arrives in 2 minutes or less, use the cumulative function to determine the corresponding threshold for this scenario.
To find the time after which the probability of arrival equals 0.6, solve: [ P(X \leq x) = 0.6 ] resulting in [ x = 2.75 ] minutes.