Unit 2B: Thermodynamics

Internal Energy

  • the sum of all the molecular kinetic and potential energies

  • can change by adding heat or doing work

    • w = fdcosθ

Work in thermodynamics

  • consider the volume of a gas in thermodynamics equilibrium:

    • piston does work on the gas

    • w = F(-Δx) = PA(-Δx)

      • work done on the gas by external forces

      • Change in volume: W = P(-ΔV)

      • if a gas expands, ΔV is positive and work done is negative because energy is lost

      • if a gas compresses, ΔV is negative and work is positive because energy is gained

    • W = -Wenv

      • Wenv is the work done by the gas

  • Example: a gas in a cylinder is at pressure 1.01×10^5 Pa and the piston has an area 0.100 m². as energy is slowly added to the gas by heat, the piston is pushed 0.04m. Calculate the work done by expanding the gas on its surroundings, Wenv.

    • W = -PΔV = -(1.01×10^5)(0.100-0.04) = -404 J

  • PV Graph

    • area = work = -PΔV = -P(Vf-Vi)

      • compression: volume shifts left

      • expansion: volume shifts right

First Law of Thermodynamics

  • energy conservation in relation to changes in internal energy, U, due to heat/work

  • changes in state— internal energy: P, T, V

  • ΔU = Uf - Ui = Q + W

    • Q is energy transfer

      • +Q = heat absorbed

      • -Q = heat released

    • W is work done

      • +W = work done on the environment (by the gas)

      • -W = work done on the system

  • Internal Energy of Monatomic Ideal Gas

    • ΔU = 3/2NKBΔT = 3/2nRΔT

    • Cv = 3/2R

      • Cv is the molar-specific heat at constant volume (isovolumetric)

    • ΔU = nCvΔT

    • Diatomic: Cv = 5/2R

4 Basic Types of Thermal Processes

  1. Isobaric - constant pressure

  2. Isovolumetric - constant volume

  3. Isothermal - constant temperature

  4. Adiabatic - no energy transferred by heat

Isobaric Process

  • ΔU = 3/2NKBΔT = 3/2nRΔT = 3/2PΔV

  • Q = ΔU - W = 3/2nRΔT + (+PΔV) = 5/2nRΔT

    • Cp = constant pressure = 5/2R

  • W = -PΔV

Isovolumetric Process

  • ΔU = 3/2NKBΔT = 3/2nRΔT = 3/2ΔPV

  • Q = CU = nCvΔT

    • Cv = 3/2R

  • W = 0

Isothermal Process

  • ΔU = 0

  • Q = - W

  • W = -nRTln(Vf/Vi)

Adiabatic Process

  • ΔU = W

  • Q = 0

  • W = ΔU

    • `P(V)^γ = const.

    • γ = Cp/Cv = adiabatic index

      • monatomic: 5/3

      • diatomic: 7/3

Cyclic Process

  • a system goes through a series of processes to return to the same initial state

  • internal energy = 0

    • ΔU = 0

  • total/net work done in a cyclic process equals the area enclosed in a PV diagram

    • clockwise cycles = -w done on the gas (compression)

    • counterclockwise cycles = +w done on gas (expansion)

  • heat engines

    • takes in energy by heat and converts it to other forms of energy

    • work done by the eng = Weng

    • energy is expelled by the engine by heat to a source at a lower temperature

      • Q = -W

    • |Weng| = |Qh| - |Qc|

      • Qh = heat absorbed

      • Qc = heat lost

      • work done by heat engine = area

  • Thermal Efficiency of Heat Engine

    • e = Weng/|Qh| = 1 - |Qh|/|Qc|

Second Law of Thermodynamics

  • clausius statement: heat flows naturally from a hot object to a cold object but it will not flow spontaneously from a cold object to a hot object

  • kelvin-Planck statement: no process is possible in which the sole result is to transform a given amount of heat completely into work

    • e < 1

    • Some engine is always lost to a cold re4servoir

    • can’t break even

  • reversible processes are an idealization: every state along the path is an equilibrium state, so the system can return to its initial conditions by following this path in reverse

  • Irreversible processes: not possible— most real natural processes

    • if a real process occurs slowly enough, it can be considered to be almost reversible

Carnot Engine/Cycle

  • most efficient → ideal reversible cycle

  • ideal gas contained in a cylinder with a moveable piston at one end

    • the temperature of a gas varies from Th to Tc

  • 2 adiabatic and 2 isothermal reversible processes

  • Carnot’s Theorem: no real engine operating between two energy reservoirs can be more efficient than a Carnot engine operating

  • Tc/Th = Qc/Qh

  • Thermal efficiency: ec = (Th - Tc)/Th = 1 - (Tc/Th)

3rd Law of Thermodynamics

  • ec can only be 1 if Tc = 0k

  • Nernsts Theorem: It is impossible to decrease the temperature of a system tro absolute 0 in a finite number of operations

  • highest multiplicity = highest entropy = highest disorder

Disorder or Multiplicity

  • large amount of chance in natural processes

  • disorderly/random arrangements of objects are more probable than orderly ones

  • isolated systems tend toward greater disorder and entropy is a measure

  • greater probability/multiplicity = more entropy

  • entropy is a measure of multiplicity

Entropy in second law: cyclic processes → increase/remain the same

  • ΔS = Qr/T [J/k]

  • ΔS: change in entropy during any constant temperature between 2 states

  • Qr: energy absorbed/expelled during a reversible, constant temperature process

  • the entropy of the universe increases in all natural processes

    • total entropy of a system and environment increases

    • decreases: gain heat for one object, but will increase for another

  • entropy in a reversible adiabatic process: ΔS = 0

  • defines the direction of time

  • energy available for work decreases → leads to heat death

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