Chemistry Vocabulary Flashcards - CHM 101 Notes (Chapter 1)
Chapter 1: Matter, Energy & Measurement — Objectives (Pages 7–8, 22, 63)
1) Classify matter by composition and state
2) Explain how chemical and physical properties describe/classify matter
3) Define kinetic and potential energy in chemical systems
4) Describe the metric system and the use of significant figures in reporting measurements
5) Convert measurements correctly using dimensional analysis
Matter: Substances and Mixtures (Pages 9–15)
Definitions
Matter: anything that has mass and takes up space
Pure substance: distinct properties; composition does not vary sample to sample
Subtypes of pure substances
Element: cannot be decomposed into simpler substances; Atoms are the building blocks; Atoms of an element are identical
Molecule: two or more atoms bound in a specific shape
Some molecules contain only atoms of one element
Compound: composed of two or more elements; Molecules contain atoms of more than one element
Law of Constant Composition (Definite Proportions)
The elemental composition of a compound is always the same
Example: one molecule of methane gas has exactly one carbon atom and four hydrogen atoms
Mixture: two or more substances combined; Components retain chemical properties
Homogeneous mixtures (solutions): uniform throughout
Heterogeneous mixtures: not uniform
Pure Substances, Substances Summary (Page 15–16)
Visual schematic: atoms, molecules, compounds, mixtures
Homogeneous vs heterogeneous classification in a decision flow
Classification of Matter by Composition (Page 17)
Decision tree outline
Matter > Is it uniform throughout?
YES: Homogeneous
If contains more than one kind of atom? YES → Compound; NO → Element or Homogeneous substance
NO: Heterogeneous mixture
Labels: Pure substance, Element, Compound, Mixture, Homogeneous, Heterogeneous
States of Matter (Pages 18–21)
Three states: Gas, Liquid, Solid
Gas
No fixed shape or volume
Fills container; can be expanded or compressed
Atoms/molecules moved rapidly and are far apart
Liquid
Definite volume, no fixed shape
Fills portion of container; not easily compressed
Molecules packed loosely but move quickly
Solid
Definite shape and volume
Not compressible; molecules locked in place
Properties of Matter (Page 23)
Physical properties: observed without changing composition
Examples: boiling point, density, mass, volume, odor, hardness
Chemical properties: observed when a substance changes into another substance
Examples: flammability, corrosiveness, reactivity with acid
Changes to Matter (Pages 24–25)
Physical changes: do not change the composition
Examples: phase changes, temperature changes, volume changes
Chemical changes: form new substances
Examples: combustion (with oxygen), oxidation (rusting), decomposition
Physical Change Example (Page 25)
Ice melting or water evaporating are physical changes; composition (H2O) remains the same: two H atoms and one O atom per molecule
Chemical Change Example (Page 26)
In a chemical reaction, reactants are converted to new substances; hydrogen and oxygen combine to form water
Determining Chemical Changes (Page 27)
Which of the following are chemical changes?
I. Burning wood – Yes (chemical change)
II. Pulverizing rock salt – No (physical change)
III. Dissolving sugar in tea – No (physical change, unless reaction occurs)
IV. Melting a popsicle – No (physical change)
Answer choices provided: A B C D (correct option would be the one corresponding to I only, if presented)
Intensive vs Extensive Properties (Page 28)
Intensive properties: independent of amount of substance
Examples: color, density, boiling point
Extensive properties: depend on amount of substance
Examples: mass, volume, energy
Energy in Chemical Processes (Page 30)
Energy: the ability to transfer heat or to do work
Kinetic energy: energy of motion; Ek = rac{1}{2} m v^2
where m = mass, v = velocity (speed)
Potential energy: stored energy due to position
Scientific Notation and Number Representation (Pages 32–38)
Scientific notation: number written as a product where the first factor is between 1 and 10 and the second factor is a power of 10
Example: 65,307.2 = 6.53072 imes 10^4
Standard form to scientific notation and vice versa (examples shown):
6.53072 imes 10^4
3.72 imes 10^{-2}
If exponent is negative, move decimal left; if positive, move right
Operations in scientific notation:
Multiplication:
(a imes 10^{m}) (b imes 10^{n}) = (ab) imes 10^{m+n}Division:
rac{a imes 10^{m}}{b imes 10^{n}} = rac{a}{b} imes 10^{m-n}Addition/Subtraction require same exponent (power of ten) alignment before combining numbers
Practical examples (from slides):
(3.8 imes 10^{4}) (2.0 imes 10^{3}) = 7.6 imes 10^{7}
(4.6 imes 10^{6}) (2 imes 10^{-2}) = ?
Practice problems and multiple-choice prompts are shown throughout, including:
2.3 imes 10^{8} vs 9.2 imes 10^{8} etc.
Important reminder: when converting, keep track of exponent rules and significant figures during the calculation
SI Units and Metric Prefixes (Pages 39–41, 69–71)
SI base units and derived units
Prefixes and their meaning (powers of ten)
Peta (P) = 10^{15}
Tera (T) = 10^{12}
Giga (G) = 10^{9}
Mega (M) = 10^{6}
Kilo (k) = 10^{3}
Deci (d) = 10^{-1}
Centi (c) = 10^{-2}
Milli (m) = 10^{-3}
Micro (μ or mu) = 10^{-6}
Nano (n) = 10^{-9}
Pico (p) = 10^{-12}
Femo (f) = 10^{-15}
Atto (a) = 10^{-18}
Zepto (z) = 10^{-21}
Watt and joule relations
The watt (W) is the SI unit of power; the rate at which energy is generated or consumed
The joule (J) is the SI unit of energy; 1 J = 1 kg·m^2/s^2; 1 W = 1 J/s
Note: mu (μ) is the micro prefix; “mu” is used for the micro symbol
Mass, Length, Temperature, Volume, and Density (Pages 42–46)
Mass
Measure of the amount of material in an object
SI base unit: kilogram (kg); metric base unit: gram (g)
Length
Measure of distance; base unit: meter (m)
Temperature
Scientific measures use Celsius and Kelvin scales
Celsius: 0 °C = freezing point of water; 100 °C = boiling point of water
Kelvin: SI unit of temperature; no negative Kelvin values; absolute zero is 0 K
Conversion: K = °C + 273.15
Volume
Not a base SI unit; derived from length: ext{volume} = m imes m imes m = m^3
Common units: liter (L) and milliliter (mL)
1 cm^3 = 1 mL
Density
Physical property with units derived from mass/volume
Common units: g/mL or g/cm^3
Energy units
Joule (J): 1 J = 1 kg·m^2/s^2
Calorie (cal): 1 cal = 4.184 J
Measurement Uncertainty, Accuracy, and Precision (Pages 47–49)
Exact numbers and inexact (measured) numbers
Exact numbers are counted or defined (e.g., 12 eggs in 1 dozen)
Inexact numbers depend on measurement and instrument precision
Uncertainty in measurements
All measurements have some degree of inaccuracy due to instrument limitations
Accuracy vs. Precision
Accuracy: closeness to true value
Precision: closeness among repeated measurements
Significant Figures (Pages 50–57)
Definition: digits that were measured, used to express measurement precision
Final digit is always estimated and uncertain
Counting sig figs
Non-zero integers always count as sig figs
Zeros rules:
Leading zeros do not count
Captive zeros (in the middle) count
Trailing zeros count if a decimal point is present
Exact numbers (e.g., conversion factors) have infinite sig figs
Examples
3456 has 4 sig figs
0.0486 has 3 sig figs
16.07 has 4 sig figs
9.300 has 4 sig figs; 9,300 has 2 sig figs (decimal point presence matters)
Practice questions shown in slides
Question: How many sig figs in 3270? Answer: 3 (C)
Using sig figs in operations
Multiplication/Division: number of sig figs in result = least number of sig figs in any operand
Example: 6.38 imes 2.0 = 12.76
ightarrow 13 (2 sig figs)Addition/Subtraction: number of decimal places in result = least precise decimal place among operands
Example: 6.8 + 11.934 = 18.734
ightarrow 18.7 (3 sig figs)
Example problem: 6.578 − 4.5 = ? → 2 (sig figs) or 2.1 depending on decimal placement; see slide for options
Dimensional Analysis (Pages 64–77)
Purpose: convert one quantity to another using conversion factors
Core idea: multiply by conversion factors so units cancel, ending with desired unit
Steps (Dimensional Analysis: How-to)
Identify target unit
Find a conversion factor relating given unit to target unit
Set up expression so units cancel, leaving the desired unit
Consider significant figures when counting digits
Example 1: Convert 3.000 m to cm
Conversion factors used: 1 ext{ cm} = 10^{-2} ext{ m}
Calculation:
Start with 3.000 m
Multiply by 1 cm / 10^{-2} m
Result: 3.000 ext{ m} imes rac{1 ext{ cm}}{10^{-2} ext{ m}} = 300.0 ext{ cm}
Note: Do not count conversion factors when determining sig figs
Useful conversion factors (Table of equivalencies)
Length:
1 ext{ km} = 0.62137 ext{ mi}
1 ext{ mi} = 5280 ext{ ft} = 1.6093 ext{ km}
1 ext{ m} = 1.0936 ext{ yd}
1 ext{ in} = 2.54 ext{ cm}
1 ext{ cm}^3 = 1 ext{ mL}
Mass:
1 ext{ kg} = 2.2046 ext{ lb}
1 ext{ lb} = 16 ext{ oz}
Volume:
1 ext{ L} = 1000 ext{ cm}^3 = 1.0567 ext{ qt}
1 ext{ gal} = 4 ext{ qt} = 3.7854 ext{ L}
Example 2: Convert 6.78 cm to inches
Use conversions: 1 in = 2.54 cm; 1 in ≈ 2.54 cm
Setup to compute: 6.78 cm × (1 in / 2.54 cm) = 2.67 in (approx)
Example 3: Dimensional analysis for volume
Teacup contains 12.0 in³ of tea; convert to mL
Step 1: Use 1 in³ = 16.3871 cm³ and 1 cm³ = 1 mL
Calculation: 12.0 in³ × 16.3871 cm³/in³ × 1 mL/cm³ = 197 mL
Dimensional Analysis: Two or More Conversions (Pages 75–77)
When no direct conversion exists, use multiple factors
Example worked: 3.000 m to in
Steps include: 1 cm = 10^{-2} m; 1 in = 2.54 cm
Result: 118.1 in
Example: Dimensional Analysis – Volume conversions (Teacup Case) – Revisited (Page 76)
Start with 12.0 in³
Use: 1 in³ = 16.3871 cm³ and 1 cm³ = 1 mL
Final units: mL
Calculation structure demonstrates cancellation to reach desired unit
Additional Notes: Practice Problems and Quick References
Practice prompts throughout the slides emphasize:
Decision-making on sign figs in operations
Correct unit cancellations in dimensional analysis
Reading and interpreting the table of metric prefixes
Basic conversions between SI units and common units (lb, oz, qt, gal, etc.)
Key Formulas and Equations (Collected)
Kinetic energy: E_k = frac{1}{2} m v^2
Temperature conversion: K = °C + 273.15
Density:
ho = rac{m}{V}Joule definition: 1 ext{ J} = 1 ext{ kg}\, ext{m}^2/ ext{s}^2
Power and energy relation: 1 ext{ W} = rac{1 ext{ J}}{ ext{s}}
Conversion factor framework: Use factors like 1 ext{ cm} = 10^{-2} ext{ m}, 1 ext{ in} = 2.54 ext{ cm}, 1 ext{ L} = 1000 ext{ cm}^3 = 1.0567 ext{ qt}
Sig figs operation rules:
Multiplication/Division: number of sig figs in result = least number of sig figs among the factors
Addition/Subtraction: decimal places in result = fewest in any term
Connections to Foundational Principles and Real-World Relevance
Matter states and changes underpin material science, chemical engineering, and materials selection for technology (e.g., solar cells, LEDs, medical plastics)
Dimensional analysis is a foundational tool for ensuring correct units and magnitudes in calculations across chemistry and physics
Significant figures reflect measurement precision, crucial in lab contexts and in communicating experimental results
SI units, prefixes, and conversions enable global standardization in science and engineering
Ethical, Philosophical, and Practical Implications
Proper reporting of measurements and uncertainty is essential for reproducibility and trust in scientific results
Clear distinction between physical and chemical properties supports safe material handling and hazard assessment
Understanding energy, work, and efficiency informs sustainability and technology development (e.g., energy conversion, storage, and ecologically responsible design)
Quick Reference: Common Conversions (Selected)
Length/Distance:
1\text{ m} = 100\text{ cm}
1\text{ cm} = 10^{-2}\text{ m}
1\text{ in} = 2.54\text{ cm}
1\text{ km} = 1000\text{ m}
1\text{ mi} = 5280\text{ ft} \approx 1.6093\text{ km}
Mass:
1\text{ kg} = 2.2046\text{ lb}
1\text{ lb} = 16\text{ oz}
Volume:
1\text{ L} = 1000\text{ cm}^3 = 1.0567\text{ qt}
Energy and Power:
1\text{ J} = 1\text{ kg m}^2/\text{s}^2
1\text{ W} = 1\text{ J/s}
Density and Volume examples:
Common density units: g/mL or g/cm³
1 cm³ = 1 mL