Title: Analysis of Variance
Presented by: Prof. Faggella
Conducted a study on moose populations in a burned area.
Four habitat types were identified on a map.
Researchers expect moose observations to be proportional to the habitat acreage.
Statistical test required to assess consistency with expectations.
Habitat Type & Data:
Type 1: 34% of total acreage, 25 moose observed
Type 2: 10% of total acreage, 22 moose observed
Type 3: 10% of total acreage, 30 moose observed
Type 4: 46% of total acreage, 40 moose observed
Total Observations: 117 moose
Definition of ANOVA: Analysis of Variance, akin to chi-square tests for multiple means.
Tests equality of population means.
Utilizes F-distribution:
Skewed right.
Positive values only.
Shape is determined by two degrees of freedom.
Applicable when data is categorized into one treatment group.
Hypotheses:
Null: All means are equal.
Assumptions:
Populations are approximately normal.
Equal variances among populations.
Random samples.
Independent samples.
Case Study: Turkey farmer tests three types of feeds.
Weights of turkeys (in pounds):
Feed A: [12.3, 11.4, 13.4, 13.4, 12.0]
Feed B: [12.1, 13.4, 12.8, 12.5, 14.2]
Feed C: [11.5, 12.1, 13.6, 11.8, 14.0]
Significance Level: α = 0.05
Conduct pairwise tests if differences are found.
F Statistic Definition: Ratio of variances.
Degrees of Freedom:
Numerator: k - 1, where k is the number of samples.
Denominator: k(n - 1), where n is the sample size.
Sample datasets:
Sample 1: [7, 1, 3]
Sample 2: [5, 6, 6]
Sample 3: [6, 5, 7]
Summary Stats:
Means and sample sizes computed.
F-test statistic calculation:
F = 0.1428
P-value = 0.8688
Major change: Data presented in a table with rows and columns.
Examines interaction effects between factors drawn from rows and columns.
Assumes normality, equal variance, simple random sampling, independence, and balanced design.
Null Hypothesis: No interaction between two factors.
Alternative Hypothesis: Interaction exists between two factors.
If no interaction is found, separate one-way ANOVA tests can be performed.
Test for interaction using the formula: F = MS(interaction) / MS(error)
Conclude interaction if P-value is less than or equal to 0.05.
Detailed analysis and results expected but not elaborated in this section.
Introduction to nonparametric statistical methods presented by Prof. Faggella.
Nonparametric tests do not rely on population distribution assumptions.
Less rigid requirements allow wider application.
Can be used with a variety of data types, including ranks and categorical data.
May waste information by simplifying quantifiable data into qualitative form.
Generally less efficient than parametric tests, requiring stronger evidence to reject null hypotheses.
Nonparametric test utilizing positive/negative signs to evaluate claims about sample data.
Analyzes frequency of signs to assess significance.
A flowchart exists to guide through the procedures.
Applicable to claims involving:
Matched pairs
Nominal data
Assessing the median of a single population.
Case Study of Male Weights: Test for claims about equal medians.
Example illustrated: Test statistic of x = 3, failing to reject H0 of no difference.
Final notes on structuring case studies for application of nonparametric testing.