Determine an object's position at time t by reading the graph at that instant.
Determine the object's velocity at time t by finding the slope of the position graph at that point; steeper slopes indicate faster speeds.
Determine the direction of motion by noting the sign of the slope.
Positive slopes correspond to positive velocities and motion to the right (or up).
Negative slopes correspond to negative velocities and motion to the left (or down).
From Position to Velocity
A velocity-versus-time graph can be deduced from a position-versus-time graph, representing an object's motion.
QuickCheck Examples (2.1, 2.2, 2.3)
Matching motion diagrams to corresponding velocity-versus-time graphs.
Example: Finding a Car’s Velocity from Its Position Graph
Drawing a velocity-versus-time graph from a given position-versus-time graph.
Describing the car’s motion in words.
From Velocity to Position
A position-versus-time graph can be deduced from a velocity-versus-time graph.
The sign of the velocity indicates whether the slope of the position graph is positive or negative.
The magnitude of the velocity indicates how steep the slope is.
QuickCheck Examples (2.4, 2.5, 2.6)
Matching motion diagrams or position graphs to corresponding velocity-versus-time graphs.
Uniform Motion
Straight-line motion with equal displacements during any successive equal-time intervals is uniform motion or constant-velocity motion.
An object’s motion is uniform if and only if its position-versus-time graph is a straight line.
Equations of Uniform Motion
The velocity of an object in uniform motion tells us the amount by which its position changes during each second.
Position equation for an object in uniform motion:
x = x0 + vx \Delta t
Mathematical Relationships
Graphs with the same overall appearance may relate to different physical phenomena but share the same mathematical relationship.
QuickCheck 2.7
Determining an object's velocity at a specific time using a position graph.
Example Problem
A soccer player kicks a ball toward the goal, and a defender tries to block it.
Problem involves calculating the time the defender has to move into position.
From Velocity to Position, One More Time
The displacement is equal to the area under the velocity graph during the time interval.
QuickCheck 2.8
Determining the object’s position at a specific time using a velocity graph.
Displacement = area under the curve.
Instantaneous Velocity
An object changing its velocity is either speeding up or slowing down.
An object’s velocity at a specific instant of time t is its instantaneous velocity; "velocity" generally means instantaneous velocity.
Finding the Instantaneous Velocity
If the velocity changes, the position graph is a curved line.
Compute a slope at a point by considering a small segment of the graph.
Finding the Instantaneous Velocity
In a magnified segment of the position graph, the curve appears to be a line segment.
The slope can be calculated as rise over run; this is the slope at time t and thus the velocity at this instant.
Finding the Instantaneous Velocity
Graphically, the slope of the curve at a point is the same as the slope of a straight line tangent to the curve at that point.
Calculating rise over run for the tangent line gives the instantaneous velocity at that instant of time.
Instantaneous Velocity
Even when the speed varies, the velocity-versus-time graph can determine displacement.
The area under the curve in a velocity-versus-time graph equals the displacement, even for non-uniform motion.
QuickCheck Examples (2.9, 2.10, 2.11)
Relating slope on a position-versus-time graph to object's velocity.
Determining when objects have the same velocity based on their position graphs.
Example: Calculating the Displacement of a Car during a Rapid Start
Calculating the displacement of a car using its velocity-versus-time graph.
QuickCheck 2.12
Analyzing a car's motion based on its position-versus-time graph, identifying points where displacement is zero, speed is zero, speed is increasing, and speed is decreasing.
Acceleration
Acceleration describes an object whose velocity is changing.
The ratio \Delta v_x / \Delta t is the rate of change of velocity.
The ratio \Delta v_x / \Delta t is the slope of a velocity-versus-time graph.
Definition of acceleration as the rate of change of velocity: ax = \Delta vx / \Delta t
Units of Acceleration
SI unit of velocity: 60 miles per hour = 27 m/s.
The Corvette speeds up 27 m/s in 3.6 seconds.
Every second, the Corvette’s velocity changes by 7.5 m/s.
Acceleration units are abbreviated as “meters per second squared” (m/s^2).
Table 2.2: Performance data for vehicles
2016 Chevy Corvette: 0 to 60 miles per hour in 3.6 seconds
2016 Chevy Sonic: 0 to 60 miles per hour in 9.0 seconds
Example: Animal Acceleration
Lions can sustain an acceleration of 8.0 m/s^2 for up to one second.
Problem involves calculating how much time it takes a lion to reach a typical recreational runner’s top speed of 10 miles per hour.
Representing Acceleration
An object’s acceleration is the slope of its velocity-versus-time graph.
Representing Acceleration
We can find an acceleration graph from a velocity graph.
QuickCheck Examples (2.13, 2.14)
Determining velocity vector and signs of position and velocity for a particle.
Example Problem
A ball moves to the right across a ramp.
Sketching graphs of velocity versus time and acceleration versus time.
The Sign of the Acceleration
An object can move right or left (or up or down) while either speeding up or slowing down.
Whether an object that is slowing down has a negative acceleration depends on the direction of motion.
Object moving to the right and speeding up: vx > 0, ax > 0
Object moving to the left and slowing down: vx < 0, ax > 0
The Sign of the Acceleration
An object can move right or left (or up or down) while either speeding up or slowing down.
Whether an object that is slowing down has a negative acceleration depends on the direction of motion.
Object moving to the right and slowing down: vx > 0, ax < 0
Object moving to the left and speeding up: vx < 0, ax < 0
QuickCheck Examples (2.15 - 2.25)
Various scenarios involving motion diagrams, cyclists, carts, and graphs to determine acceleration, velocity, and position relationships.
Motion with Constant Acceleration
The slope of the graph in the velocity graph determines the acceleration of the rocket.
Constant Acceleration Equations
Use acceleration to find velocity at a later time:
Velocity equation for an object with constant acceleration: vf = vi + a \Delta t
Constant Acceleration Equations
The velocity-versus-time graph for constant-acceleration motion is a straight line with value v{0x} at time t0 and slope a_x.
The displacement during a time interval is the area under the velocity-versus-time graph.
Constant Acceleration Equations
The shaded area can be subdivided into a rectangle and a triangle. Adding these areas gives:
Position equation for an object with constant acceleration: x = x0 + v0 \Delta t + (1/2) a (\Delta t)^2
Constant Acceleration Equations
Combining the velocity and position equations for constant acceleration:
vf^2 = vi^2 + 2 a (\Delta x)
\Delta x is the displacement (not the distance!).
Constant Acceleration Equations
Velocity changes steadily: v = v_0 + at
The position changes as the square of the time interval: x = x0 + v0t + (1/2)at^2
Change in velocity in terms of distance: v^2 = v_0^2 + 2a\Delta x
Example: Coming to a Stop in a Car
Driving at 15 m/s and stopping in 1.5 seconds.
Problem involves finding the distance the car travels while braking.
Example Problem: Reaching New Heights
Spud Webb's vertical leap: 110 cm.
To jump this high, determine the speed at which he would leave the ground.
Example: Finding the Displacement of a Drag Racer
A drag racer travels 6.0 meters in 1.0 second from rest.
Suppose the car continues this acceleration for an additional 4.0 seconds; how far will the car be from the starting line?
Problem-Solving Approach
Break down complex problems into smaller steps.
Four steps: Strategize, Prepare, Solve, and Assess.
Problem-Solving Approach
Strategize: Big-picture questions about the problem.
What kind of problem is this?
What’s the correct general approach?
What should the answer look like?
Problem-Solving Approach
Prepare: Identify important elements and collect information.
Drawing a picture.
Collecting necessary information.
Doing preliminary calculations.
Problem-Solving Approach
Solve: Perform the mathematics or reasoning to arrive at the answer.
Problem-Solving Approach
Assess: Check if the answer makes sense.
Does the solution answer the question asked?
Does the answer have the correct units and number of significant figures?
Does the computed value make physical sense?
Can you estimate what the answer should be to check the solution?
Does the final solution make sense in the context of the material being learned?
Example: Kinematics of a Rocket Launch
A Saturn V rocket launched straight up with constant acceleration of 20 m/s^2.
After 150 s, how fast is the rocket moving, and how far has it traveled?
Example: Calculating the Minimum Length of a Runway
A fully loaded Boeing 747 accelerates at 2.3 m/s^2.
Its minimum takeoff speed is 70 m/s.
How much time will the plane take to reach its takeoff speed?
What minimum length of runway does the plane require for takeoff?
Example: Calculating the Minimum Length of a Runway
Set x0 and t0 equal to zero at the starting point of the motion when the plane is at rest and the acceleration begins.
Example Problem: Champion Jumper
A springbok jumps straight up into the air (pronk).
The speed when leaving the ground can be as high as 7.0 m/s.
How much time will it take to reach its highest point?
How long will it stay in the air?
When it returns to earth, how fast will it be moving?
Free Fall
Free fall occurs when an object moves under the influence of gravity only.
All objects in free fall have the same acceleration, regardless of their mass.
Air resistance is ignored.
Free Fall
Apollo 15 astronaut David Scott dropped a hammer and a feather on the moon simultaneously; both hit the ground at the same time.
Free Fall
The motion diagram for an object released from rest and falling freely is the same for all falling objects.
Free Fall
The free-fall acceleration always points downward.
Any object moving under the influence of gravity only is in free fall.
The average value of free-fall acceleration on Earth is approximately 9.8 m/s^2
Class Video: Free Fall
Free Fall
g is always positive.
Even though a falling object speeds up, it has negative acceleration.
Kinematic equations for constant acceleration can be used for free fall.
g is the free-fall acceleration; other planets have different values of g.
QuickCheck Examples (2.26, 2.27, 2.28)
Analyzing the acceleration and velocity of an arrow launched vertically upward.
Example: Analyzing a Rock’s Fall
A heavy rock is dropped from rest at the top of a cliff and falls 100 m before hitting the ground.
How long does the rock take to fall to the ground?
What is its velocity when it hits?
Example: Finding the Height of a Leap
A springbok goes into a crouch and extends its legs forcefully, accelerating at 35 m/s^2 as its legs straighten.
At what speed does the springbok leave the ground?
How high does it go?
Example Problem
Passengers on the Giant Drop at Six Flags experience 2.6 seconds of free fall.
How fast are the passengers moving at the end of this speeding up phase?
If the cars then come to rest in 1.0 seconds, what is the acceleration (magnitude and direction) of this slowing down phase?