Objectives:
Recognize characteristics of parabolas.
Graph parabolas.
Determine a quadratic function’s minimum or maximum value.
Solve problems involving a quadratic function’s minimum or maximum value.
The quadratic function can be expressed in vertex form:
General form: ( f(x) = a(x - h)^2 + k )
The vertex of the parabola is at the point (h, k).
The parabola is symmetric about the line ( x = h ).
Direction of Opening:
If ( a > 0 ), opens upward.
If ( a < 0 ), opens downward.
Determine Direction:
Check the value of ( a ).
Find the Vertex:
Coordinate is (h, k).
Find x-intercepts:
Solve ( f(x) = 0 ) for x-intercepts.
Find the y-intercept:
Calculate ( f(0) ).
Plot Points:
Plot intercepts and vertex, and draw a smooth curve.
Step 1: The parabola opens downward (( a < 0 )).
Step 2: The vertex is at (1, 4).
Step 3: x-intercepts found to be (3, 0).
Step 4: y-intercept is (0, 3).
Graph Summary:
Opens downward; axis of symmetry: x = 1; intercepts: x = 3, y = 3.
For the quadratic function ( f(x) = ax^2 + bx + c ):
Vertex Coordinates:
x-coordinate: ( x = -\frac{b}{2a} )
y-coordinate calculated by evaluating ( f ) at the x-coordinate.
Steps to Graph:
Determine the direction (upward if ( a > 0 ), downward if ( a < 0 )).
Calculate the vertex using the formula for x and substituting back to find y.
Solve for x-intercepts (roots).
Find the y-intercept at (0, c).
Plot all points and connect with a smooth curve.
Steps:
The parabola opens downward.
The vertex calculated to be (2, 5).
x-intercepts identified.
y-intercept identified as (0, 1).
Complete the graph with intercepts and vertex points.
General Criterion:
If ( a > 0 ): Minimum at vertex.
If ( a < 0 ): Maximum at vertex.
Determine the vertex to find the minimum or maximum value of the quadratic function.
Evaluate: Given ( a = 4 ) implies a minimum value exists.
Locate the vertex and evaluate the function for maximum/minimum values.
Identify domain (all real numbers) and range, based on vertex location and direction of parabola.
Steps to Solve:
Identify the quantity to optimize (maximize/minimize).
Express this quantity as a function in one variable.
Write the function in the standard quadratic form.
Determine the vertex based on a or b to find extremum.
State the solution clearly.
Define the problem: 120 feet of fencing must enclose an area.
Express Area: Area as a function of dimensions using given perimeter constraints.
Calculate Extremum: Identify maxima/minima based on function parameters derived from dimensions.
Conclude dimensions for maximum area: Dimensions derived yield 30 ft x 30 ft as optimal; maximum area calculated.