Electric Circuit Analysis: Sinusoidal Steady-State Analysis

ES 2210 - Electric Circuit Analysis

Chapter 9 - Sinusoidal Steady-State Analysis

Chapter 9 - Objectives
  • The student should:

    • Be able to perform a phasor transform of a sinusoid and its phasor inverse.

    • Be able to phasor-transform a circuit.

    • Solve arbitrarily complex circuits with sinusoidal sources using the phasor method.

    • Note: Sections 9.10 and 9.11 (related to transformers) will not be covered in ES 2210, but later in EE 2220.

Why Should You Care?
  • Response of a circuit to a sinusoidal source (i.e., an A.C. source) is important for three reasons:

    • Importance of electrical power generation and distribution.

    • Ability to predict behavior to a non-sinusoidal source if behavior to a sinusoidal source is known, utilizing Fourier series and Fourier transforms.

    • Electrical circuit design requirements and specifications are often based on response to sinusoidal input.

Sinusoidal Steady-State Analysis Overview
  • The process for solving sinusoidal steady-state analysis includes:

    • Electrical Circuit Differential Equation Classical Solution Methods

    • Solution Transform using complex numbers

    • Algebraic Solution

    • Inverse Transform

    • The chapter 9 method will be used for analysis.

Complex Numbers: A Quick Review
  • Definition of j:

    • Defined as j =
      oot{-1}

    • Properties of j:

    • j^2 = -1

    • j^3 = j^2 imes j = -j

    • j^4 = j^2 imes j^2 = 1

  • Complex numbers are common in almost all engineering disciplines and a more detailed review can be found in Appendix B of the textbook.

Structure of Complex Numbers
  • A complex number is expressed as:

    • C = a + jb

    • Where:

    • a = Real Part

    • b = Imaginary Part

    • The notation does not indicate addition but signifies association between C, a, and b:

    • Real Part: ext{Re}ig"{C} = a

    • Imaginary Part: ext{Im}ig"{C} = b

Representation of Complex Numbers
  • Rectangular Form:

    • Graphically represented in the complex plane:

    • Imaginary axis (b)

    • Real axis (a)

  • Polar Form:

    • Represented as:

    • C = r ext{∠} heta

    • Where r is the magnitude and $ heta$ is the angle from the real axis.

  • Conversion Forms:

    • Rectangular to Polar conversion:

    • r =
      oot{(a^2 + b^2)}

    • heta = an^{-1}igg( rac{b}{a}igg)

    • Polar to Rectangular conversion:

    • a = r ext{cos}( heta)

    • b = r ext{sin}( heta)

Euler's Formula
  • A critical relationship summarized as:

    • r ext{∠} heta = r ext{cos}( heta) + j r ext{sin}( heta) = r e^{j heta}

  • Used frequently in Electrical Engineering and disciplines.

Special Cases of Complex Numbers
  • Positive Real Number: a = a + j0 = a ext{∠}0^ ext{◦}

  • Positive Imaginary Number: b = 0 + jb = b ext{∠}90^ ext{◦}

  • Negative Real Number: -a = -a + j0 = a ext{∠}180^ ext{◦}

  • Negative Imaginary Number: -b = 0 - jb = b ext{∠}-90^ ext{◦}

  • Conjugate: If C = a + jb, then C^* = a - jb

Operations with Complex Numbers
  • Addition and Subtraction in Rectangular Form:

    • Let C = a + jb and Z = x + jy

    • Addition: C + Z = (a + x) + j(b + y)

    • Subtraction: C - Z = (a - x) + j(b - y)

  • Multiplication in Rectangular:

    • C imes Z = (a + jb)(x + jy)

    • Distribution results in:

    • = ax + j(ay + bx) - by

  • Division in Rectangular Form:

    • rac{C}{Z} = rac{a + jb}{x + jy}

    • Multiply numerator and denominator by the conjugate: rac{(a + jb)(x - jy)}{(x + jy)(x - jy)}

    • Result in terms of real and imaginary components gives:

    • rac{a x + b y}{x^2 + y^2} + j rac{b x - a y}{x^2 + y^2}

Addition and Subtraction in Polar Form
  • In polar form:

    • Let C = r1∠θ1 and Z = r2∠θ2

    • Convert to rectangular form for addition and subtraction.

Multiplication and Division in Polar Form
  • Multiplication: For two phasors,

    • C imes Z = r1 r2 ∠(θ1 + θ2)

  • Division:

    • rac{C}{Z} = rac{r1}{r2} ∠(θ1 - θ2)

Arithmetic for Complex Numbers
  • Recommended strategies:

    • Use rectangular form for addition and subtraction.

    • Use polar form for multiplication and division.

Powers of a Complex Number
  • For any integer n,

    • If C = a + jb

    • C^n = (re^{jθ})^n = r^n e^{jnθ}

    • Which can be expressed as: C^n = r^n ext{cos}(nθ) + j r^n ext{sin}(nθ)

Sinusoidal Source Terminology
  • A sinusoidal source is given by:

    • v(t) = V_m ext{cos}( ext{ω}t + ext{ϕ})

    • Where:

      • V_m: Amplitude or magnitude

      • ext{ω}: Angular frequency in radians per second [ ext{ rad/s}]

      • t: Time in seconds [ ext{ s}]

      • ext{ϕ}: Phase angle in degrees [ ext{ deg}]

      • f = rac{ ext{ω}}{2 ext{π}}: Frequency in Hertz [ ext{ Hz}]

      • T = rac{1}{f}: Period in seconds [ ext{ s}]

Observations about Sinusoids
  • A sinusoidal function is periodic, repeating every T seconds.

  • Frequency:

    • Cycles per second: f = rac{1}{T}

  • Angular frequency:

    • ext{ω} = 2 ext{π}f = rac{2 ext{π}}{T}

  • The maximum amplitude is V_m.

  • The phase angle ext{ϕ} shifts the sinusoid along the time axis.

    • vs(t) = Vm ext{sin}( ext{ω}t + ext{ϕ})

Sinusoid Frequency and Phase Angle Questions
  • Frequency for i(t) = 36 ext{cos}(4 ext{π}t + 45°) mA is f = 2 ext{Hz}.

  • Phase angle for v(t) = 50 ext{cos}(3000t - 60°) V is ext{ϕ} = -60°.

Evaluating Sinusoids at Specific Times
  • To find a sinusoidal current at $t = 5 ms$ for i(t) = 0.2 ext{cos}(50 ext{π}t + 45°) A

    • Convert all arguments to the same units:

    • Example: 50 ext{π}t gives radians and needs to be carefully factored with respect to degrees (conversion method shown).

    • Need careful setting for calculator units!

  • Result: At t = 0.005 s:

    • i(0.005) = 0.2 ext{cos}(90°) = 0 A

Sinusoid Analysis in Circuits
  • When voltage v = Vm ext{sin}( ext{ω}t) and current i = Im ext{sin}( ext{ω}t + ext{ϕ}):

  • We indicate current leads voltage by the phase angle ext{ϕ} or vice-versa.

Current Response for Sinusoidal Sources in Circuits
  • Current i(t) responds according to defined circuit laws, with the phasor representation providing shortcuts for analysis.

  • Transient Phase Component:

    • This component decays to zero as t o ext{∞}.

  • Steady-State Phase Component:

    • Persistently represents system behavior influenced by input voltage.

    • Has the same frequency as the input voltage, though potentially differing in magnitude and phase angle.

Circuit Analysis Techniques
  • Fundamental components of circuit analysis techniques:

    • Ohm’s law

    • Kirchhoff's voltage law (KVL)

    • Kirchhoff's current law (KCL)

  • Using these laws in the time domain leads to effective analytical techniques that can be employed in the phasor domain as well.

    • Relation between voltage and current in resistors, inductors, and capacitors under dynamic conditions is defined succinctly by their impedance

    • Impedance: Defined as the ratio of voltage to current, represented with units of Ohms [ ext{Ω}]

Impedance of Circuit Elements
  • Resistor:

    • Z_R = R

  • Inductor:

    • Z_L = j ext{ω}L

  • Capacitor:

    • Z_C = rac{1}{j ext{ω}C} = -j rac{1}{ ext{ω}C}

Summary of Sinusoidal Steady-State
  • In the Time Domain:

    • Resistor: v(t) = R i(t)

    • Inductor: v(t) = L rac{di(t)}{dt}

    • Capacitor: i(t) = C rac{dv(t)}{dt}

  • In the Phasor Domain:

    • V = Z I

  • Phasor domain allows analysis methods of circuit design under sinusoidal steady-state conditions.

AC Steady-State Analysis Steps
  • Steps in AC steady-state analysis include:

    1. Redraw the circuit (phasing does not change components).

    2. Phasor transform known voltages and currents.

    3. Use $V$ and $I$ for unknown voltages and currents.

    4. Replace inductance and capacitance with their respective impedances.

    5. Write equations using circuit analysis methods, solved with a calculator.

    6. Perform inverse transformation back to the time domain.

Example Problem Summaries & Techniques
  • Iterative evaluation of current and voltage in sinusoidal forms, calculation of impedances, and applying fundamental circuit equations illustrate how to achieve operational results effectively.

  • Conduct operations meticulously, especially when transforming to and from phasor forms to ensure consistency of results.

  • Analysis using source transformations is beneficial for simplifying complex interactions and extracting values.

  • Utilize any DC circuit methods learned to derive phasor responses efficiently—fundamental understanding of electrical interactions remains key to mastering circuit behavior.