Electric Circuit Analysis: Sinusoidal Steady-State Analysis

ES 2210 - Electric Circuit Analysis

Chapter 9 - Sinusoidal Steady-State Analysis

Chapter 9 - Objectives
  • The student should:

    • Be able to perform a phasor transform of a sinusoid and its phasor inverse.

    • Be able to phasor-transform a circuit.

    • Solve arbitrarily complex circuits with sinusoidal sources using the phasor method.

    • Note: Sections 9.10 and 9.11 (related to transformers) will not be covered in ES 2210, but later in EE 2220.

Why Should You Care?
  • Response of a circuit to a sinusoidal source (i.e., an A.C. source) is important for three reasons:

    • Importance of electrical power generation and distribution.

    • Ability to predict behavior to a non-sinusoidal source if behavior to a sinusoidal source is known, utilizing Fourier series and Fourier transforms.

    • Electrical circuit design requirements and specifications are often based on response to sinusoidal input.

Sinusoidal Steady-State Analysis Overview
  • The process for solving sinusoidal steady-state analysis includes:

    • Electrical Circuit Differential Equation Classical Solution Methods

    • Solution Transform using complex numbers

    • Algebraic Solution

    • Inverse Transform

    • The chapter 9 method will be used for analysis.

Complex Numbers: A Quick Review
  • Definition of j:

    • Defined as j=<br>oot1j = <br>oot{-1}

    • Properties of j:

    • j2=1j^2 = -1

    • j3=j2imesj=jj^3 = j^2 imes j = -j

    • j4=j2imesj2=1j^4 = j^2 imes j^2 = 1

  • Complex numbers are common in almost all engineering disciplines and a more detailed review can be found in Appendix B of the textbook.

Structure of Complex Numbers
  • A complex number is expressed as:

    • C=a+jbC = a + jb

    • Where:

    • a = Real Part

    • b = Imaginary Part

    • The notation does not indicate addition but signifies association between C, a, and b:

    • Real Part: ext{Re}ig"{C} = a

    • Imaginary Part: ext{Im}ig"{C} = b

Representation of Complex Numbers
  • Rectangular Form:

    • Graphically represented in the complex plane:

    • Imaginary axis (b)

    • Real axis (a)

  • Polar Form:

    • Represented as:

    • C=rexthetaC = r ext{∠} heta

    • Where r is the magnitude and $ heta$ is the angle from the real axis.

  • Conversion Forms:

    • Rectangular to Polar conversion:

    • r=<br>oot(a2+b2)r = <br>oot{(a^2 + b^2)}

    • heta=an1(racba)heta = an^{-1}\bigg( rac{b}{a}\bigg)

    • Polar to Rectangular conversion:

    • a=rextcos(heta)a = r ext{cos}( heta)

    • b=rextsin(heta)b = r ext{sin}( heta)

Euler's Formula
  • A critical relationship summarized as:

    • rextheta=rextcos(heta)+jrextsin(heta)=rejhetar ext{∠} heta = r ext{cos}( heta) + j r ext{sin}( heta) = r e^{j heta}

  • Used frequently in Electrical Engineering and disciplines.

Special Cases of Complex Numbers
  • Positive Real Number: a=a+j0=aext0exta = a + j0 = a ext{∠}0^ ext{◦}

  • Positive Imaginary Number: b=0+jb=bext90extb = 0 + jb = b ext{∠}90^ ext{◦}

  • Negative Real Number: a=a+j0=aext180ext-a = -a + j0 = a ext{∠}180^ ext{◦}

  • Negative Imaginary Number: b=0jb=bext90ext-b = 0 - jb = b ext{∠}-90^ ext{◦}

  • Conjugate: If C=a+jbC = a + jb, then C=ajbC^* = a - jb

Operations with Complex Numbers
  • Addition and Subtraction in Rectangular Form:

    • Let C=a+jbC = a + jb and Z=x+jyZ = x + jy

    • Addition: C+Z=(a+x)+j(b+y)C + Z = (a + x) + j(b + y)

    • Subtraction: CZ=(ax)+j(by)C - Z = (a - x) + j(b - y)

  • Multiplication in Rectangular:

    • CimesZ=(a+jb)(x+jy)C imes Z = (a + jb)(x + jy)

    • Distribution results in:

    • =ax+j(ay+bx)by= ax + j(ay + bx) - by

  • Division in Rectangular Form:

    • racCZ=raca+jbx+jyrac{C}{Z} = rac{a + jb}{x + jy}

    • Multiply numerator and denominator by the conjugate: rac(a+jb)(xjy)(x+jy)(xjy)rac{(a + jb)(x - jy)}{(x + jy)(x - jy)}

    • Result in terms of real and imaginary components gives:

    • racax+byx2+y2+jracbxayx2+y2rac{a x + b y}{x^2 + y^2} + j rac{b x - a y}{x^2 + y^2}

Addition and Subtraction in Polar Form
  • In polar form:

    • Let C=r<em>1θ</em>1C = r<em>1∠θ</em>1 and Z=r<em>2θ</em>2Z = r<em>2∠θ</em>2

    • Convert to rectangular form for addition and subtraction.

Multiplication and Division in Polar Form
  • Multiplication: For two phasors,

    • CimesZ=r<em>1r</em>2(θ<em>1+θ</em>2)C imes Z = r<em>1 r</em>2 ∠(θ<em>1 + θ</em>2)

  • Division:

    • racCZ=racr<em>1r</em>2(θ<em>1θ</em>2)rac{C}{Z} = rac{r<em>1}{r</em>2} ∠(θ<em>1 - θ</em>2)

Arithmetic for Complex Numbers
  • Recommended strategies:

    • Use rectangular form for addition and subtraction.

    • Use polar form for multiplication and division.

Powers of a Complex Number
  • For any integer n,

    • If C=a+jbC = a + jb

    • Cn=(rejθ)n=rnejnθC^n = (re^{jθ})^n = r^n e^{jnθ}

    • Which can be expressed as: Cn=rnextcos(nθ)+jrnextsin(nθ)C^n = r^n ext{cos}(nθ) + j r^n ext{sin}(nθ)

Sinusoidal Source Terminology
  • A sinusoidal source is given by:

    • v(t)=Vmextcos(extωt+extϕ)v(t) = V_m ext{cos}( ext{ω}t + ext{ϕ})

    • Where:

      • VmV_m: Amplitude or magnitude

      • extωext{ω}: Angular frequency in radians per second [extrad/s][ ext{ rad/s}]

      • tt: Time in seconds [exts][ ext{ s}]

      • extϕext{ϕ}: Phase angle in degrees [extdeg][ ext{ deg}]

      • f=racextω2extπf = rac{ ext{ω}}{2 ext{π}}: Frequency in Hertz [extHz][ ext{ Hz}]

      • T=rac1fT = rac{1}{f}: Period in seconds [exts][ ext{ s}]

Observations about Sinusoids
  • A sinusoidal function is periodic, repeating every TT seconds.

  • Frequency:

    • Cycles per second: f=rac1Tf = rac{1}{T}

  • Angular frequency:

    • extω=2extπf=rac2extπText{ω} = 2 ext{π}f = rac{2 ext{π}}{T}

  • The maximum amplitude is VmV_m.

  • The phase angle extϕext{ϕ} shifts the sinusoid along the time axis.

    • v<em>s(t)=V</em>mextsin(extωt+extϕ)v<em>s(t) = V</em>m ext{sin}( ext{ω}t + ext{ϕ})

Sinusoid Frequency and Phase Angle Questions
  • Frequency for i(t)=36extcos(4extπt+45°)mAi(t) = 36 ext{cos}(4 ext{π}t + 45°) mA is f=2extHzf = 2 ext{Hz}.

  • Phase angle for v(t)=50extcos(3000t60°)Vv(t) = 50 ext{cos}(3000t - 60°) V is extϕ=60°ext{ϕ} = -60°.

Evaluating Sinusoids at Specific Times
  • To find a sinusoidal current at $t = 5 ms$ for i(t)=0.2extcos(50extπt+45°)Ai(t) = 0.2 ext{cos}(50 ext{π}t + 45°) A

    • Convert all arguments to the same units:

    • Example: 50extπt50 ext{π}t gives radians and needs to be carefully factored with respect to degrees (conversion method shown).

    • Need careful setting for calculator units!

  • Result: At t=0.005st = 0.005 s:

    • i(0.005)=0.2extcos(90°)=0Ai(0.005) = 0.2 ext{cos}(90°) = 0 A

Sinusoid Analysis in Circuits
  • When voltage v=V<em>mextsin(extωt)v = V<em>m ext{sin}( ext{ω}t) and current i=I</em>mextsin(extωt+extϕ)i = I</em>m ext{sin}( ext{ω}t + ext{ϕ}):

  • We indicate current leads voltage by the phase angle extϕext{ϕ} or vice-versa.

Current Response for Sinusoidal Sources in Circuits
  • Current i(t)i(t) responds according to defined circuit laws, with the phasor representation providing shortcuts for analysis.

  • Transient Phase Component:

    • This component decays to zero as toextt o ext{∞}.

  • Steady-State Phase Component:

    • Persistently represents system behavior influenced by input voltage.

    • Has the same frequency as the input voltage, though potentially differing in magnitude and phase angle.

Circuit Analysis Techniques
  • Fundamental components of circuit analysis techniques:

    • Ohm’s law

    • Kirchhoff's voltage law (KVL)

    • Kirchhoff's current law (KCL)

  • Using these laws in the time domain leads to effective analytical techniques that can be employed in the phasor domain as well.

    • Relation between voltage and current in resistors, inductors, and capacitors under dynamic conditions is defined succinctly by their impedance

    • Impedance: Defined as the ratio of voltage to current, represented with units of Ohms [extΩ][ ext{Ω}]

Impedance of Circuit Elements
  • Resistor:

    • ZR=RZ_R = R

  • Inductor:

    • ZL=jextωLZ_L = j ext{ω}L

  • Capacitor:

    • ZC=rac1jextωC=jrac1extωCZ_C = rac{1}{j ext{ω}C} = -j rac{1}{ ext{ω}C}

Summary of Sinusoidal Steady-State
  • In the Time Domain:

    • Resistor: v(t)=Ri(t)v(t) = R i(t)

    • Inductor: v(t)=Lracdi(t)dtv(t) = L rac{di(t)}{dt}

    • Capacitor: i(t)=Cracdv(t)dti(t) = C rac{dv(t)}{dt}

  • In the Phasor Domain:

    • V=ZIV = Z I

  • Phasor domain allows analysis methods of circuit design under sinusoidal steady-state conditions.

AC Steady-State Analysis Steps
  • Steps in AC steady-state analysis include:

    1. Redraw the circuit (phasing does not change components).

    2. Phasor transform known voltages and currents.

    3. Use $V$ and $I$ for unknown voltages and currents.

    4. Replace inductance and capacitance with their respective impedances.

    5. Write equations using circuit analysis methods, solved with a calculator.

    6. Perform inverse transformation back to the time domain.

Example Problem Summaries & Techniques
  • Iterative evaluation of current and voltage in sinusoidal forms, calculation of impedances, and applying fundamental circuit equations illustrate how to achieve operational results effectively.

  • Conduct operations meticulously, especially when transforming to and from phasor forms to ensure consistency of results.

  • Analysis using source transformations is beneficial for simplifying complex interactions and extracting values.

  • Utilize any DC circuit methods learned to derive phasor responses efficiently—fundamental understanding of electrical interactions remains key to mastering circuit behavior.