Introduction to Transformers
- Transformers serve to change or transform the voltage in an electrical circuit.
Types of Transformers
- Step-Up Transformer:
- Increases the voltage and decreases the amperage.
- Step-Down Transformer:
- Decreases the voltage and increases the amperage.
- Both types operate based on the number of turns in the transformer.
Formula for Calculating Voltage Change
- The core formula for voltage change in a transformer is:
- \frac{Vs}{Vp} = \frac{Ns}{Np}
- Where:
- $V_s$ = Secondary voltage
- $V_p$ = Primary voltage
- $N_s$ = Number of turns on the secondary side
- $N_p$ = Number of turns on the primary side
Representation of Variables on a Diagram
- $V_p$ = Voltage on the primary side.
- $N_p$ = Number of turns on the primary side.
- $N_s$ = Number of turns on the secondary side.
- $V_s$ = Voltage on the secondary side.
Importance of the Turns Ratio
- The fraction \frac{Ns}{Np} is known as the turns ratio.
- It has practical significance in determining how the voltage changes based on the turns in the transformer.
Rearranging the Equation
- The formula can be rearranged to directly solve for the secondary voltage:
- Vs = Vp \cdot \frac{Ns}{Np}
Sample Problem: Turns Ratio Calculation
- Problem: What is the turns ratio for a transformer having 40 primary turns and 4,000 secondary turns?
- Solution:
- Turns ratio = \frac{Ns}{Np} = \frac{4000}{40} = 100:1
Practice Problem #1: Voltage Calculation
- Problem: What is the voltage produced by a transformer receiving 220 volts if the primary side has 100 turns and the secondary side has 10,000 turns?
- Analysis:
- More secondary turns indicate this is a step-up transformer.
- Calculation: Using modified formula:
- V_s = 220 \cdot \frac{10,000}{100} = 220 \cdot 100 = 22,000 \text{ volts}
Practice Problem #2: Voltage Calculation
- Problem: What is the voltage produced by a transformer receiving 220 volts if the primary side has 10 turns and the secondary side has 400 turns?
- Calculation: Using modified formula:
- V_s = 220 \cdot \frac{400}{10} = 220 \cdot 40 = 8,800 \text{ volts}