RS

Chapter 1 – Scalar and Vector Products

Resultant Force & Vector Operations

Overview of Chapter 1 Requirements
  • Instructor’s request:

    • Produce a summary specifically about the “resulting force” material covered in Chapter 1.

    • Focus on two vector–operation tools used to evaluate the resulting force:

    1. Scalar (Dot) Product

    2. Vector (Cross) Product

  • Reminder of alternate names:

    • Scalar product = dot product

    • Vector product = cross product

Scalar Product (Dot Product)
  • Definition

    • Algebraic form (for vectors \mathbf{A} and \mathbf{B}):
      \mathbf{A}\cdot\mathbf{B}=|\mathbf{A}|\,|\mathbf{B}|\cos\theta

    • |\mathbf{A}| and |\mathbf{B}| = magnitudes

    • \theta = angle between the vectors

  • Key properties

    • Produces a scalar (single numerical) result.

    • Commutative: \mathbf{A}\cdot\mathbf{B}=\mathbf{B}\cdot\mathbf{A}

  • Significance in “resulting force” context

    • Determines how much of one force lies along the direction of another.

    • Useful for calculating work: W = \mathbf{F}\cdot\mathbf{s} (force along a displacement).

Vector Product (Cross Product)
  • Definition

    • Algebraic form:
      \mathbf{A}\times\mathbf{B}=|\mathbf{A}|\,|\mathbf{B}|\sin\theta\,\mathbf{n}

    • \mathbf{n} = unit vector perpendicular to plane containing \mathbf{A} and \mathbf{B}, direction by right-hand rule

  • Key properties

    • Produces a vector result (magnitude and direction).

    • Anti-commutative: \mathbf{A}\times\mathbf{B}= - (\mathbf{B}\times\mathbf{A})

  • Significance in “resulting force” context

    • Determines a vector perpendicular to two force vectors; appears in torque: \boldsymbol\tau = \mathbf{r} \times \mathbf{F}.

Practical Example Links
  • Dot product example (work): If |\mathbf{F}| = 10\,\text{N}, |\mathbf{s}| = 5\,\text{m}, \theta = 30^\circ, then W = 10\times5\times\cos30^\circ = 43.3\,\text{J}.

  • Cross product example (torque): For a wrench of length 0.25\,\text{m} with force 40\,\text{N} applied at 90^\circ, |\boldsymbol\tau| = 0.25\times40\times\sin90^\circ = 10\,\text{N·m}; direction perpendicular to wrench plane.

Recap & Key Takeaways
  • Resulting force analysis often decomposes into:

    • Projection (dot) to find parallel components.

    • Perpendicular influence or moment arm (cross) to find rotational effects.

  • Memorizing both names—dot product for scalar, cross product for vector—ensures quick recall during problem-solving.